 
			 
			MCQOPTIONS
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				| 1. | Find the complementary current from the information provided in the question 4. | 
| A. | i<sub>c</sub> = e<sup>-37.5t</sup>(c<sub>1</sub>cos1290t + c<sub>2</sub>sin1290t) | 
| B. | i<sub>c</sub> = e<sup>-37.5t</sup>(c<sub>1</sub>cos1290t – c<sub>2</sub>sin1290t) | 
| C. | i<sub>c</sub> = e<sup>37.5t</sup>(c<sub>1</sub>cos1290t – c<sub>2</sub>sin1290t) | 
| D. | i<sub>c</sub> = e<sup>37.5t</sup>(c<sub>1</sub>cos1290t + c<sub>2</sub>sin1290t) | 
| Answer» B. i<sub>c</sub> = e<sup>-37.5t</sup>(c<sub>1</sub>cos1290t ‚Äö√Ñ√∂‚àö√ë‚àö¬® c<sub>2</sub>sin1290t) | |