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1. |
Electric potential varies with distance such that V(x) =ax-bx3; where a and b are constants. Where will the electric field intensity be zero? |
A. | x=\(\frac {a}{b}\) |
B. | x=\(\frac {a}{3b}\) |
C. | x=\(\sqrt{\frac {a}{b}}\) |
D. | x=+\(\sqrt{\frac {a}{3b}}\) and x=-\(\sqrt{\frac {a}{3b}}\) |
Answer» E. | |