ΔABC ∼ ΔEDF and ar(ΔABC) ∶ ar(ΔDEF) = 1 ∶ 4. If AB = 7 cm, BC = 8 cm and CA = 9 cm, then DF is equal to∶

ΔABC ∼ ΔEDF and ar(ΔABC) ∶ ar(ΔDEF) = 1 ∶ 4. If AB = 7 cm, B

1.	ΔABC ∼ ΔEDF and ar(ΔABC) ∶ ar(ΔDEF) = 1 ∶ 4. If AB = 7 cm, BC = 8 cm and CA = 9 cm, then DF is equal to∶
A.	14 cm
B.	18 cm
C.	16 cm
D.	8 cm
Answer» D. 8 cm

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ΔABC ∼ ΔEDF and ar(ΔABC) ∶ ar(ΔDEF) = 1 ∶ 4. If AB = 7 cm, BC = 8 cm and CA = 9 cm, then DF is equal to∶

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