ΔABC ~ ΔEDF and ar(ΔABC) : ar(ΔDEF) = 4 : 9. If AB = 6 cm, BC = 8 cm and AC = 10 cm, then DF Is equal to:

ΔABC ~ ΔEDF and ar(ΔABC) : ar(ΔDEF) = 4 : 9. If AB = 6 cm, BC = 8

1.	ΔABC ~ ΔEDF and ar(ΔABC) : ar(ΔDEF) = 4 : 9. If AB = 6 cm, BC = 8 cm and AC = 10 cm, then DF Is equal to:
A.	15 cm
B.	9 cm
C.	12 cm
D.	18 cm
Answer» D. 18 cm

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ΔABC ~ ΔEDF and ar(ΔABC) : ar(ΔDEF) = 4 : 9. If AB = 6 cm, BC = 8 cm and AC = 10 cm, then DF Is equal to:

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