1.

Consider the following stencil. What is Φe according to the QUICK scheme?

A. Φe=\(\phi_P+\frac{x_e-x_P}{x_E-x_W}\)(ΦE-ΦW)
B. Φe=\(\phi_P+\frac{x_e-x_P}{x_E-x_W}\)(ΦE+ΦW)
C. Φe=\(\phi_P-\frac{x_e-x_P}{x_E-x_W}\)(ΦE-ΦW)
D. Φe=\(\phi_P-\frac{x_e-x_P}{x_E-x_W}\)(ΦE+ΦW)
Answer» B. Φe=\(\phi_P+\frac{x_e-x_P}{x_E-x_W}\)(ΦE+ΦW)


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