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This section includes 10 Mcqs, each offering curated multiple-choice questions to sharpen your Computational Fluid Dynamics knowledge and support exam preparation. Choose a topic below to get started.
1. |
The central differencing scheme gives good results when _____________ |
A. | the grid is coarse |
B. | the grid is very fine |
C. | the grid is Cartesian and uniform |
D. | the gird is on-Cartesian |
Answer» C. the grid is Cartesian and uniform | |
2. |
The order of accuracy of the central differencing scheme is _____________ |
A. | fourth-order |
B. | third-order |
C. | second-order |
D. | first-order |
Answer» D. first-order | |
3. |
The central difference scheme gives unphysical results when the problem is _____________ |
A. | depends on the boundary conditions |
B. | equally dominated by diffusion and convection |
C. | diffusive dominant |
D. | convective dominant |
Answer» E. | |
4. |
The central differencing scheme becomes inconsistent when the Peclet number _____________ |
A. | is higher than 2 |
B. | is less than 2 |
C. | is higher than 5 |
D. | is less than 5 |
Answer» B. is less than 2 | |
5. |
Which of these is correct about the central differencing scheme? |
A. | The importance of upwind and downwind nodes depends on the problem |
B. | It gives more importance to the downwind nodes |
C. | It gives equal importance to upwind and downwind nodes |
D. | It gives more importance to the upwind nodes |
Answer» D. It gives more importance to the upwind nodes | |
6. |
The central difference approximation goes wrong when _____________ |
A. | Peclet number is negative |
B. | Peclet number is positive |
C. | Peclet number is low |
D. | Peclet number is high |
Answer» E. | |
7. |
What is the relationship between \(\frac{\phi_c-\phi_w}{\phi_E-\phi_w}\) and the Peclet number (Pe) when the grid is uniform? |
A. | \(\frac{\phi_c-\phi_w}{\phi_E-\phi_w} = \frac{1}{2}(1-\frac{Pe}{2}) \) |
B. | \(\frac{\phi_c-\phi_w}{\phi_E-\phi_w} = \frac{1}{2}(1+\frac{Pe}{2}) \) |
C. | \(\frac{\phi_c-\phi_w}{\phi_E-\phi_w} = \frac{1}{2}(\frac{Pe}{2}-1) \) |
D. | \(\frac{\phi_c-\phi_w}{\phi_E-\phi_w} = (\frac{Pe}{4}) \) |
E. | when the grid is uniform?a) \(\frac{\phi_c-\phi_w}{\phi_E-\phi_w} = \frac{1}{2}(1-\frac{Pe}{2}) \) b) \(\frac{\phi_c-\phi_w}{\phi_E-\phi_w} = \frac{1}{2}(1+\frac{Pe}{2}) \) c) \(\frac{\phi_c-\phi_w}{\phi_E-\phi_w} = \frac{1}{2}(\frac{Pe}{2}-1) \) d) \(\frac{\phi_c-\phi_w}{\phi_E-\phi_w} = (\frac{Pe}{4}) \) |
Answer» B. \(\frac{\phi_c-\phi_w}{\phi_E-\phi_w} = \frac{1}{2}(1+\frac{Pe}{2}) \) | |
8. |
What is the central differencing scheme similar to? |
A. | Interpolation profile |
B. | Linear interpolation profile |
C. | Weighted average method |
D. | Geometric mean |
Answer» C. Weighted average method | |
9. |
Consider the following stencil.Assume that the grid is a uniform Cartesian grid. What is φw as given by the central difference scheme?(Note: Φ represents the flow variable). |
A. | Φc |
B. | \(\frac{\phi_c+\phi_w}{2}\) |
C. | \(\frac{\phi_c-\phi_w}{2}\) |
D. | \(\frac{\phi_w-\phi_c}{2}\) |
E. | .a) Φcb) \(\frac{\phi_c+\phi_w}{2}\) c) \(\frac{\phi_c-\phi_w}{2}\) d) \(\frac{\phi_w-\phi_c}{2}\) |
Answer» C. \(\frac{\phi_c-\phi_w}{2}\) | |
10. |
Consider the following stencil. What is Φe as given by the central difference scheme?(Note: Φ represents the flow variable). |
A. | \(\phi_E = \phi_c-\frac{(\phi_E+\phi_c)}{(x_E-x_C)}(x_e-x_C)\) |
B. | \(\phi_E = \phi_c+\frac{(\phi_E+\phi_c)}{(x_E-x_C)}(x_e-x_C)\) c) \(\phi_E = \phi_c+\frac{(\phi_E-\phi_c)}{(x_E-x_C)}(x_e-x_C)\) d) \(\phi_E = \phi_c-\frac{(\phi_E-\phi_ |
C. | }{(x_E-x_C)}(x_e-x_C)\) b) \(\phi_E = \phi_c+\frac{(\phi_E+\phi_c)}{(x_E-x_C)}(x_e-x_C)\) c) \(\phi_E = \phi_c+\frac{(\phi_E-\phi_c)}{(x_E-x_C)}(x_e-x_C)\) |
D. | \(\phi_E = \phi_c-\frac{(\phi_E-\phi_c)}{(x_E-x_C)}(x_e-x_C)\) |
E. | .a) \(\phi_E = \phi_c-\frac{(\phi_E+\phi_c)}{(x_E-x_C)}(x_e-x_C)\) b) \(\phi_E = \phi_c+\frac{(\phi_E+\phi_c)}{(x_E-x_C)}(x_e-x_C)\) c) \(\phi_E = \phi_c+\frac{(\phi_E-\phi_c)}{(x_E-x_C)}(x_e-x_C)\) d) \(\phi_E = \phi_c-\frac{(\phi_E-\phi_c)}{(x_E-x_C)}(x_e-x_C)\) |
Answer» D. \(\phi_E = \phi_c-\frac{(\phi_E-\phi_c)}{(x_E-x_C)}(x_e-x_C)\) | |