Consider the following pseudo-codeI = 0; J = 0; K = 8;while (I < K-1) / / while-1 { J=J+1; while ( J< K) / /while-2 { If (x[I] < x[J] ) { temp = x[I]; x[I] = x[J]; x[J] = temp; } } // end of while-2 I=I+1 } // end of while-1The cyclomatic complexity of the above is

Consider the following pseudo-codeI = 0; J = 0; K = 8;while (I < K-1)

1.	Consider the following pseudo-codeI = 0; J = 0; K = 8;while (I < K-1) / / while-1 { J=J+1; while ( J< K) / /while-2 { If (x[I] < x[J] ) { temp = x[I]; x[I] = x[J]; x[J] = temp; } } // end of while-2 I=I+1 } // end of while-1The cyclomatic complexity of the above is
A.	3
B.	2
C.	4
D.	1
Answer» D. 1

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Consider the following pseudo-codeI = 0; J = 0; K = 8;while (I < K-1) / / while-1 { J=J+1; while ( J< K) / /while-2 { If (x[I] < x[J] ) { temp = x[I]; x[I] = x[J]; x[J] = temp; } } // end of while-2 I=I+1 } // end of while-1The cyclomatic complexity of the above is

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