Consider the differential equation \(\frac{{dy}}{{dx}} = \left( {1 + {y^2}} \right)x\). The general solution with constant C is

\(y = \tan \frac{{{x^2}}}{2} + tanc\)

\(y = {\tan ^2}\left( {\frac{x}{2} + c} \right)\)

\(y = {\tan ^2}\left( {\frac{x}{2}} \right) + c\)

\(y = \tan \left( {\frac{{{x^2}}}{2} + c} \right)\)

Consider the differential equation \(\frac{{dy}}{{dx}} = \left( {1 + {

1.	Consider the differential equation \(\frac{{dy}}{{dx}} = \left( {1 + {y^2}} \right)x\). The general solution with constant C is
A.	\(y = \tan \frac{{{x^2}}}{2} + tanc\)
B.	\(y = {\tan ^2}\left( {\frac{x}{2} + c} \right)\)
C.	\(y = {\tan ^2}\left( {\frac{x}{2}} \right) + c\)
D.	\(y = \tan \left( {\frac{{{x^2}}}{2} + c} \right)\)
Answer» E.

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