1.

Consider the common emitter amplifier shown below with the following circuit parameters: β = 100, gm = 0.3861 A/V, r0 = ∞ rp = 259 Ω, Rs = 1 kΩ, RB = 93 kΩ, RC = 250 Ω, RL = 1 kW, C1 = ∞ and C2 = 4.7mF.The lower cut-off frequency due to C2 is

A. 33.9 Hz
B. 27.1 Hz
C. 13.6 Hz
D. 16.9 Hz
Answer» B. 27.1 Hz


Discussion

No Comment Found

Related MCQs