Assertion : The graph between velocity and displacement for a harmonic oscillator is a parabola. Reason : Velocity does not change uniformly with displacement in harmonic motion.

If both assertion and reason are true and the reason is the correct explanation of the assertion.

If both assertion and reason are true but reason is not the correct explanation of the assertion.

\[T=2\pi \sqrt{\left( \frac{M}{PAh} \right)}\]

If the assertion and reason both are false.

If assertion is false but reason is true.

Assertion : The graph between velocity and displacement for a harmonic

1.	Assertion : The graph between velocity and displacement for a harmonic oscillator is a parabola. Reason : Velocity does not change uniformly with displacement in harmonic motion.
A.	If both assertion and reason are true and the reason is the correct explanation of the assertion.
B.	If both assertion and reason are true but reason is not the correct explanation of the assertion.
C.	\[T=2\pi \sqrt{\left( \frac{M}{PAh} \right)}\]
D.	If the assertion and reason both are false.
E.	If assertion is false but reason is true.
Answer» F.

Discussion

No Comment Found

Related MCQs

Two particles are executing S.H.M. The equation of their motion are \[{{y}_{1}}=10\sin \left( \omega \,t+\frac{\pi T}{4} \right),\]\[{{y}_{2}}=25\sin \,\left( \omega \,t+\frac{\sqrt{3}\pi T}{4} \right)\]. What is the ratio of their amplitude [DCE 1996]
The phase of a particle executing simple harmonic motion is \[\frac{\pi }{2}\] when it has [MP PET 1985]
A simple pendulum has time period T1. The point of suspension is now moved upward according to equation \[y=k{{t}^{2}}\] where\[k=1\,m/se{{c}^{2}}\]. If new time period is T2 then ratio \[\frac{T_{1}^{2}}{T_{2}^{2}}\] will be [IIT-JEE (Screening) 2005]
The displacement of a particle moving in S.H.M. at any instant is given by\[y=a\sin \omega t\]. The acceleration after time \[t=\frac{T}{4}\] is (where T is the time period) [MP PET 1984]
As a body performs S.H.M., its potential energy U. varies with time as indicated in [AMU (Med.) 2001]
The displacement time graph of a particle executing S.H.M. is as shown in the figure [KCET 2003]
The amplitude of a particle executing SHM is made three-fourth keeping its time period constant. Its total energy will be [RPMT 2004]
When the potential energy of a particle executing simple harmonic motion is one-fourth of its maximum value during the oscillation, the displacement of the particle from the equilibrium position in terms of its amplitude a is [CBSE PMT 1993; EAMCET (Engg.) 1995; MP PMT 1994, 2000; MP PET 1995, 96, 2002]
The potential energy of a simple harmonic oscillator when the particle is half way to its end point is (where E is the total energy) [CBSE PMT 2003]
The equation of S.H.M. is \[y=a\sin (2\pi nt+\alpha )\], then its phase at time t is [DPMT 2001]

Assertion : The graph between velocity and displacement for a harmonic oscillator is a parabola. Reason : Velocity does not change uniformly with displacement in harmonic motion.

Discussion

No Comment Found

Related MCQs

Reply to Comment