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				| 1. | An alternating voltage of 360 V, 50 Hz is applied to a full-wave rectifier. The internal resistance of each diode is 100 W. If RL = 5 kW, then what is the peak value of output current? | 
| A. | 0.9 A | 
| B. | 0.07 A | 
| C. | 0.097 A | 
| D. | 1.097 A | 
| Answer» D. 1.097 A | |