1.

An ac circuit has two branches in parallel. The impedances of the two branches are equal. Their power factors are 0.8 lagging and 0.8 leading. The overall p.f. is

A. Number of links = Number of branches - number of nodes + 1
B. Number of links = Number of branches - number of nodes
C. Number of links = Number of branches - number of nodes - 1
D. Number of links = Number of branches - number of nodes - 2
Answer» B. Number of links = Number of branches - number of nodes


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