MCQOPTIONS
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| 1. |
An ac circuit has two branches in parallel. The impedances of the two branches are equal. Their power factors are 0.8 lagging and 0.8 leading. The overall p.f. is |
| A. | Number of links = Number of branches - number of nodes + 1 |
| B. | Number of links = Number of branches - number of nodes |
| C. | Number of links = Number of branches - number of nodes - 1 |
| D. | Number of links = Number of branches - number of nodes - 2 |
| Answer» B. Number of links = Number of branches - number of nodes | |