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| 1. |
A tube of uniform cross section always has water flowing through it. It is kept vertical in such a way that water enters from top and leaves from the bottom. If the speed at a point A below the opening is ‘v’, what will be the speed at a point B vertically below A such that the distance between A & B is ‘2h’? |
| A. | v |
| B. | \(\sqrt{v^2 + 4gh}\) |
| C. | \(\sqrt{v^2 + 2gh}\) |
| D. | v/2 |
| Answer» B. \(\sqrt{v^2 + 4gh}\) | |