 
			 
			MCQOPTIONS
 Saved Bookmarks
				| 1. | A spring of force constant k is cut into two pieces such that one piece is double the length of the other. Then the long piece will have a force constant of [IIT-JEE (Screening) 1999] | 
| A. | \[(2/3)k\] | 
| B. | \[(3/2)k\] | 
| C. | For an adiabatic change \[\frac{{{P}_{2}}}{{{P}_{1}}}={{\left( \frac{{{V}_{2}}}{{{V}_{1}}} \right)}^{\gamma }}\], where \[\gamma \] is the ratio of specific heats | 
| D. | \[6k\] | 
| Answer» C. For an adiabatic change \[\frac{{{P}_{2}}}{{{P}_{1}}}={{\left( \frac{{{V}_{2}}}{{{V}_{1}}} \right)}^{\gamma }}\], where \[\gamma \] is the ratio of specific heats | |