A satellite of mass “m” revolves around a planet at a height as s – McqOptions

MCQOPTIONS

1.	A satellite of mass “m” revolves around a planet at a height as shown in the figure. If “g” is the acceleration due to gravity on the surface of the planet, what is the orbital velocity of the satellite?
A.	gh/2
B.	(gR)/(R-h)
C.	(gR2)/(R+h)
D.	[(gR2)/(R+h)]1/2
Answer» E.

Discussion

No Comment Found

Related MCQs

The time period of a satellite of earth is 90 minutes. If the separation between the earth and the satellite is quadrupled, the new time period will be _____________
A satellite of mass “m” revolves around a planet at a height as shown in the figure. If “g” is the acceleration due to gravity on the surface of the planet, what is the orbital velocity of the satellite?
The time period of a satellite is independent of the mass of the satellite.
A satellite orbits the earth at a height of R/5. What is its orbital speed?
The orbital velocity of a satellite orbiting a planet of mass “M” and radius “R” at a height as shown is [(G*M)/(R+h)].
A satellite is revolving very close to a planet of density D. What is the time period of that satellite?
A satellite is launched into a circular orbit of radius R while a second satellite is launched into an orbit of radius 1.02R. What is the percentage change in the time periods of the two satellites?
Consider 2 satellites A and B having time periods 16 hours and 1 hour, respectively. What is the ratio of the radius of their orbits?
The time period of the moon around the earth is 24 hours.
The satellites orbiting the earth, eventually fall to the earth when they are left unsupervised or unattended because _____