A particle is moving with a velocity \(v = K\left( {y\hat i + x\hat j} \right)\) where K is a constant. The general equation for its path is:

A particle is moving with a velocity \(v = K\left( {y\hat i + x\hat j}

1.	A particle is moving with a velocity \(v = K\left( {y\hat i + x\hat j} \right)\) where K is a constant. The general equation for its path is:
A.	y = x2 + constant
B.	y2 = x + constant
C.	y2 = x2 + constant
D.	xy = constant
Answer» D. xy = constant

Discussion

No Comment Found

Related MCQs

Four particles A, B, C, and D with masses mA = m, mB = 2m, mC = 3m and mD = 4m are at the corners of a square. They have accelerations of equal magnitude with directions as shown. The acceleration of the center of mass of the particles is:
Let \(\left| {\overrightarrow {{{\rm{A}}_1}} } \right| = 3,\;\left| {\overrightarrow {{{\rm{A}}_2}} } \right| = 5{\rm{\;and\;}}\left| {\overrightarrow {{{\rm{A}}_1}} + \overrightarrow {{{\rm{A}}_2}} } \right| = 5\). The value of \(\left( {2\overrightarrow {{{\rm{A}}_1}} + 3\overrightarrow {{{\rm{A}}_2}} } \right) \cdot \left( {3\overrightarrow {{{\rm{A}}_1}} - 2\overrightarrow {{{\rm{A}}_2}} } \right)\) is:
A particle moves from the point \(\left( {2.0\hat i + 4.0\hat j} \right)\) m at t = 0 with an initial velocity \(\left( {5.0\hat i + 4.0\;\hat j} \right)m{s^{ - 1}}\). It is acted upon by a constant force which produces a constant acceleration \(\left( {4.0\;\hat i + 4.0\;\hat j} \right)m{s^{ - 2}}\). What is the distance of the particle from the origin at time 2 s?
In the cube of side 'a' shown in the figure, the vector from the central point of the face ABOD to the central point of the face BEFO will be
Find the unit vector perpendicular to the surface x2 + y2 – z2 = 11 at the point (4, 2, 3).
Consider the following physical quantities:Energy, power, pressure, impulse, temperature, gravitational potential. Which of the above is/are the vector quantity/quantities?
A particle is moving with a velocity \(v = K\left( {y\hat i + x\hat j} \right)\) where K is a constant. The general equation for its path is:
If two forces of 5N each are acting along X and Y-axis then the magnitude and direction of resultant is
If two vectors \(\vec{A}=6\hat{i}-8\hat{j}+4\hat{k}\) and \(\vec{B}=4\hat{i}-6\hat{j}+p\hat{k}\) are mutually perpendicular, then value of p is
Cos site of the cosmids

A particle is moving with a velocity \(v = K\left( {y\hat i + x\hat j} \right)\) where K is a constant. The general equation for its path is:

Discussion

No Comment Found

Related MCQs

Reply to Comment