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This section includes 18 Mcqs, each offering curated multiple-choice questions to sharpen your Network Theory knowledge and support exam preparation. Choose a topic below to get started.
1. |
Determine the power (kW) drawn by the load. |
A. | 21 |
B. | 22 |
C. | 23 |
D. | 24 |
Answer» E. | |
2. |
A three-phase balanced delta connected load of (4+j8) Ω is connected across a 400V, 3 – Ø balanced supply. Determine the phase current IB. |
A. | 44.74∠303.4⁰A |
B. | 44.74∠-303.4⁰A |
C. | 45.74∠303.4⁰A |
D. | 45.74∠-303.4⁰A |
Answer» C. 45.74∠303.4⁰A | |
3. |
A three-phase balanced delta connected load of (4+j8) Ω is connected across a 400V, 3 – Ø balanced supply. Determine the phase current IY. |
A. | 44.74∠183.4⁰A |
B. | 45.74∠183.4⁰A |
C. | 44.74∠183.4⁰A |
D. | 45.74∠-183.4⁰A |
Answer» D. 45.74∠-183.4⁰A | |
4. |
A three-phase balanced delta connected load of (4+j8) Ω is connected across a 400V, 3 – Ø balanced supply. Determine the phase current IR. Assume the phase sequence to be RYB. |
A. | 44.74∠-63.4⁰A |
B. | 44.74∠63.4⁰A |
C. | 45.74∠-63.4⁰A |
D. | 45.74∠63.4⁰A |
Answer» B. 44.74∠63.4⁰A | |
5. |
If the load impedance is Z∠Ø, the expression obtained for current (IB) is? |
A. | (V/Z)∠-240+Ø |
B. | (V/Z)∠-240-Ø |
C. | (V/Z)∠240-Ø |
D. | (V/Z)∠240+Ø |
Answer» C. (V/Z)∠240-Ø | |
6. |
If the load impedance is Z∠Ø, the expression obtained for current (IY) is? |
A. | (V/Z)∠-120+Ø |
B. | (V/Z)∠120-Ø |
C. | (V/Z)∠120+Ø |
D. | (V/Z)∠-120-Ø |
Answer» E. | |
7. |
If the load impedance is Z∠Ø, the current (IR) is? |
A. | (V/Z)∠-Ø |
B. | (V/Z)∠Ø |
C. | (V/Z)∠90-Ø |
D. | (V/Z)∠-90+Ø |
Answer» B. (V/Z)∠Ø | |
8. |
In a balanced three-phase system-delta load, if we assume the line voltage is VRY = V∠0⁰ as a reference phasor. Then the source voltage VBR is? |
A. | V∠120⁰ |
B. | V∠240⁰ |
C. | V∠-240⁰ |
D. | V∠-120⁰ |
Answer» D. V∠-120⁰ | |
9. |
In a balanced three-phase system-delta load, if we assume the line voltage is VRY = V∠0⁰ as a reference phasor. Then the source voltage VYB is? |
A. | V∠0⁰ |
B. | V∠-120⁰ |
C. | V∠120⁰ |
D. | V∠240⁰ |
Answer» C. V∠120⁰ | |
10. |
IN_THE_QUESTION_7,_DETERMINE_THE_PHASE_CURRENT_IB.?$ |
A. | 44.74∠303.4⁰A |
B. | 44.74∠-303.4⁰A |
C. | 45.74∠303.4⁰A |
D. | 45.74∠-303.4⁰A |
Answer» C. 45.74‚Äö√Ñ√∂‚àö‚Ć‚Äö√тĆ303.4‚Äö√Ñ√∂‚àö√ñ‚Äö√†√ªA | |
11. |
Determine_the_power_(kW)_drawn_by_the_load.$ |
A. | 21 |
B. | 22 |
C. | 23 |
D. | 24 |
Answer» E. | |
12. |
In the question 7, determine the phase current IY? |
A. | 44.74∠183.4⁰A |
B. | 45.74∠183.4⁰A |
C. | 44.74∠183.4⁰A |
D. | 45.74∠-183.4⁰A |
Answer» D. 45.74‚Äö√Ñ√∂‚àö‚Ć‚Äö√тĆ-183.4‚Äö√Ñ√∂‚àö√ñ‚Äö√†√ªA | |
13. |
A three phase, balanced delta connected load of (4+j8) Ω is connected across a 400V, 3 – Ø balanced supply. Determine the phase current IR . Assume the phase sequence to be RYB.$ |
A. | 44.74∠-63.4⁰A |
B. | 44.74∠63.4⁰A |
C. | 45.74∠-63.4⁰A |
D. | 45.74∠63.4⁰A |
Answer» B. 44.74‚Äö√Ñ√∂‚àö‚Ć‚Äö√тĆ63.4‚Äö√Ñ√∂‚àö√ñ‚Äö√†√ªA | |
14. |
In the question 4, the expression obtained for current (IY) is? |
A. | (V/Z)∠-120+Ø |
B. | (V/Z)∠120-Ø |
C. | (V/Z)∠120+Ø |
D. | (V/Z)∠-120-Ø |
Answer» E. | |
15. |
If the load impedance is Z∠Ø, the current (IR ) is?$ |
A. | (V/Z)∠-Ø |
B. | (V/Z)∠Ø |
C. | (V/Z)∠90-Ø |
D. | (V/Z)∠-90+Ø |
Answer» B. (V/Z)‚Äö√Ñ√∂‚àö‚Ć‚Äö√тĆ‚Äö√†√∂‚àö‚â§ | |
16. |
In a delta-connected load, the relation between line voltage and the phase voltage is? |
A. | line voltage > phase voltage |
B. | line voltage < phase voltage |
C. | line voltage = phase voltage |
D. | line voltage >= phase voltage |
Answer» D. line voltage >= phase voltage | |
17. |
In the question 1, the source voltage VBR is? |
A. | V∠120⁰ |
B. | V∠240⁰ |
C. | V∠-240⁰ |
D. | V∠-120⁰ |
Answer» D. V‚Äö√Ñ√∂‚àö‚Ć‚Äö√тĆ-120‚Äö√Ñ√∂‚àö√ñ‚Äö√†√ª | |
18. |
In a balanced three-phase system-delta load, if we assume the line voltage is VRY = V∠0⁰ as a reference phasor. Then the source voltage VYB is? |
A. | V∠0⁰ |
B. | V∠-120⁰ |
C. | V∠120⁰ |
D. | V∠240⁰ |
Answer» C. V‚Äö√Ñ√∂‚àö‚Ć‚Äö√тĆ120‚Äö√Ñ√∂‚àö√ñ‚Äö√†√ª | |