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This section includes 22 Mcqs, each offering curated multiple-choice questions to sharpen your Civil Engineering knowledge and support exam preparation. Choose a topic below to get started.
1. |
Match the following criteria of material failure, under biaxial stresses \({\sigma _1}\), \({\sigma _2}\) and yield stress σy, with their corresponding graphic representations :A. Maximum-shear–stress criterion L. B. Maximum-distortion-energy criterionM.C. Maximum-normal-stress criterionN |
A. | A – L, B – N, C – M |
B. | A – N, B – L, C – M |
C. | A – M, B – N, C – L |
D. | A – N, B – M, C – L |
Answer» C. A – M, B – N, C – L | |
2. |
Consider the following statements:1. In the infinitesimal strain theory, dilatation is taken as an invariant.2. Dilatation is not proportional to the algebraic sum of all normal stresses.3. The shearing modulus is always less than the elastic modulus.Which of the above statements is/are correct? |
A. | 1 only |
B. | 1 and 2 only |
C. | 2 only |
D. | 1, 2 and 3 |
Answer» E. | |
3. |
A structural element is subjected to pure shear of 80 N/mm2, as shown in the figure. The yield stresses both in tension and in compression are 240 N/mm2. According to the maximum normal stress theory, the factors of safety in tension and compression are, respectively, |
A. | 2 and 2 |
B. | 2.5 and 2.5 |
C. | 3 and 3 |
D. | 4 and 4 |
Answer» D. 4 and 4 | |
4. |
According to the maximum shear stress failure criterion, yielding in material occurs when: |
A. | Maximum shear stress = yield stress |
B. | Maximum shear stress = half of yield stress |
C. | Maximum shear stress = 2 × yield stress |
D. | Maximum shear stress just exceeds the yield stress |
Answer» C. Maximum shear stress = 2 × yield stress | |
5. |
A rod of diameter 20 mm is subjected to a tensile load. Based on Tresca’s failure criterion, if the uniaxial yield stress of the material is 300 MPa, the failure load is |
A. | 20.75 kN |
B. | 54.00 kN |
C. | 94.25 kN |
D. | 105.50 kN |
E. | 115.50 kN |
Answer» D. 105.50 kN | |
6. |
Principal stresses at a point in an elastic material are 1.5 σ (tensile), σ (tensile) and 0.5 σ (compressive). The elastic limit in tension is 210 MPa and μ = 0.3. The value of σ at failure when computed by maximum principal strain theory is, nearly. |
A. | 140.5 MPa |
B. | 145.5 MPa |
C. | 150.5 MPa |
D. | 155.5 MPa |
Answer» E. | |
7. |
According to the maximum strain energy theory, yield locus is _____. |
A. | a rectangle |
B. | a circle |
C. | a hexagon |
D. | an ellipse |
Answer» E. | |
8. |
A material may fail if_________. |
A. | maximum principal stress exceeds the direct stress σ0 |
B. | maximum strain exceeds σ0/E |
C. | maximum shear stress exceeds σ0/2 |
D. | all option are correct |
Answer» E. | |
9. |
From Rankine’s hypothesis Rankine, criteria for failure of brittle material is: |
A. | Maximum principal stress |
B. | Maximum strain energy |
C. | Maximum shear stress |
D. | Maximum shear strain energy |
Answer» B. Maximum strain energy | |
10. |
All the theories of failure, will give nearly the same result when |
A. | When one of the principal stresses at a point is large in comparison to the other |
B. | When shear stresses act |
C. | When both the principal stresses are numerically equal |
D. | For all situations of stress |
Answer» B. When shear stresses act | |
11. |
Maximum Shear Stress Theory is also known as: |
A. | Beltrami and Haigh’s Theory |
B. | Guest's theory |
C. | St. Venant’s Theory |
D. | Rankine Theory |
Answer» C. St. Venant’s Theory | |
12. |
A machine element is subjected to the normal stress of 80 MPa and shear stress of 60 MPa. The yield strength of material is 320 MPa. The factor of safety using maximum shear stress theory will be |
A. | 2.85 |
B. | 4 |
C. | 2.21 |
D. | None of these |
Answer» D. None of these | |
13. |
For ductile materials the most appropriate failure theory is _______ |
A. | Maximum shear stress theory |
B. | Maximum Principal stress theory |
C. | Maximum Principal strain theory |
D. | Shear strain energy theory |
Answer» E. | |
14. |
Maximum shear stress theory was postulated by |
A. | ST Venant |
B. | Tresca |
C. | Mohr |
D. | Rankine |
Answer» C. Mohr | |
15. |
Match List-I (Theory of Failure) with List-Il (Predicted Ratio of Shear Stress to Direct Stress at Yield Condition for Steel Specimen) and select the correct answer using the code given below the Lists:List-IA. Maximum shear stress theoryB. Maximum energy distortion theoryC. Maximum principal stress theoryD. Maximum principal strain theoryList-II1. 1.02. 0.773. 0.5774. 0.50 |
A. | A-1, B-2, C-4, D-3 |
B. | A-4, B-3, C-1, D-2 |
C. | A-1, B-3, C-4, D-2 |
D. | A-4, B-2, C-1, D-3 |
Answer» C. A-1, B-3, C-4, D-2 | |
16. |
For ductile material the suitable theory of failure is: |
A. | Maximum principal stress theory |
B. | Maximum shear stress theory |
C. | Both (a) and (b) |
D. | None of these |
Answer» C. Both (a) and (b) | |
17. |
Name the failure theory that is suitable for designing the brittle component |
A. | Maximum shear stress theory |
B. | Maximum distortion energy theory |
C. | Maximum principle stress theory |
D. | Maximum strain theory |
Answer» D. Maximum strain theory | |
18. |
A bolt is under an axial thrust of 9.6 kN together with a transverse force of 4.8 kN. If factor of safety is 3, yield strength of bolt material is 270 N/mm2 and Poisson’s ratio is 0.3, its diameter as per maximum principal stress theory will be nearly |
A. | 13 mm |
B. | 15 mm |
C. | 17 mm |
D. | 19 mm |
Answer» B. 15 mm | |
19. |
According to Tresca, yield locus is a/an |
A. | rectangle |
B. | circle |
C. | hexagon |
D. | ellipse |
Answer» D. ellipse | |
20. |
Principal stresses at a point are 80 N/mm2 and 40 N/mm2, both tensile. The yield stress in simple tension for this material is 200 N/mm2. The values of factors of safety according to maximum principal stress theory and maximum shear stress theory, respectively, are |
A. | 2.5 and 2.5 |
B. | 2.5 and 5 |
C. | 5 and 5 |
D. | 5 and 1.67 |
Answer» C. 5 and 5 | |
21. |
Design of shafts made of brittle material is based on |
A. | Guest's theory |
B. | Rankine's theory |
C. | St. Venant's theory |
D. | Von Mises theory |
Answer» C. St. Venant's theory | |
22. |
Maximum strain energy theory of failure was postulated by |
A. | Haigh |
B. | Rankine |
C. | Tresca |
D. | St. Venant |
Answer» B. Rankine | |