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This section includes 20 Mcqs, each offering curated multiple-choice questions to sharpen your Design Electrical Machines knowledge and support exam preparation. Choose a topic below to get started.
1. |
High value of the specific electric loading can be used for low voltage machines. |
A. | true |
B. | false |
Answer» B. false | |
2. |
How many factors influence the choice of specific electric loading? |
A. | 2 |
B. | 3 |
C. | 4 |
D. | 5 |
Answer» D. 5 | |
3. |
What is the range of the air gap density for salient pole machines? |
A. | 0.52-0.65 Wb per m2 |
B. | 0.5-0.6 Wb per m2 |
C. | 0.54-0.65 Wb per m2 |
D. | 0.44-0.65 Wb per m2 |
Answer» B. 0.5-0.6 Wb per m2 | |
4. |
The machines having high air gap density operates poorly when connected in synchronism. |
A. | true |
B. | false |
Answer» C. | |
5. |
What is the formula for output equations in synchronous machines? |
A. | kVA output = output coefficient * diameter2 * length * synchronous speed |
B. | kVA output = output coefficient / diameter2 * length * synchronous speed |
C. | kVA output = output coefficient * diameter2 / length * synchronous speed |
D. | kVA output = output coefficient * diameter2 * length / synchronous speed |
Answer» B. kVA output = output coefficient / diameter2 * length * synchronous speed | |
6. |
THE_MACHINES_HAVING_HIGH_AIR_GAP_DENSITY_OPERATES_POORLY_WHEN_CONNECTED_IN_SYNCHRONISM??$ |
A. | true |
B. | false |
Answer» C. | |
7. |
How many factors influence the choice of specific electric loading?$ |
A. | 2 |
B. | 3 |
C. | 4 |
D. | 5 |
Answer» D. 5 | |
8. |
What is the range of the air gap density for salient pole machines?$ |
A. | 0.52-0.65 Wb per m<sup>2</sup> |
B. | 0.5-0.6 Wb per m<sup>2</sup> |
C. | 0.54-0.65 Wb per m<sup>2</sup> |
D. | 0.44-0.65 Wb per m<sup>2</sup> |
Answer» B. 0.5-0.6 Wb per m<sup>2</sup> | |
9. |
What is the value of specific electric loading for the salient pole alternators? |
A. | 20,000-40,000 A per m |
B. | 50,000-75,000 A per m |
C. | 25,000-40,000 A per m |
D. | 20,000-45,000 A per m |
Answer» B. 50,000-75,000 A per m | |
10. |
How is the specific electric loading related to the synchronous reactance of the machines? |
A. | specific electric loading is high, leakage reactance is high, giving low synchronous reactance |
B. | specific electric loading is high, leakage reactance is low, giving low synchronous reactance |
C. | specific electric loading is high, leakage reactance is high, giving high synchronous reactance |
D. | specific electric loading is low, leakage reactance is high, giving high synchronous reactance |
Answer» D. specific electric loading is low, leakage reactance is high, giving high synchronous reactance | |
11. |
High value of the specific electric loading can be used for low voltage machines? |
A. | true |
B. | false |
Answer» B. false | |
12. |
How is the specific electric loading related to copper losses and temperature rise? |
A. | high specific electric loading gives high copper losses and high temperature rise |
B. | high specific electric loading gives low copper losses and high temperature rise |
C. | high specific electric loading gives high copper losses and low temperature rise |
D. | high specific electric loading gives low copper losses and low temperature rise |
Answer» B. high specific electric loading gives low copper losses and high temperature rise | |
13. |
How is the steady state stability related with the air gap density? |
A. | air gap density is directly proportional to the steady state stability |
B. | air gap density is indirectly proportional to the steady state stability |
C. | air gap density is directly proportional to the square of the steady state stability |
D. | air gap density is directly proportional to the square of the steady state stability |
Answer» B. air gap density is indirectly proportional to the steady state stability | |
14. |
How is the transient short circuit current related with the air gap density? |
A. | air gap density is directly proportional to the short circuit current |
B. | air gap density is indirectly proportional to the short circuit current |
C. | air gap density is directly proportional to the square of the short circuit current |
D. | air gap density is directly proportional to the square of the short circuit current |
Answer» B. air gap density is indirectly proportional to the short circuit current | |
15. |
How is the voltage related with the air gap density? |
A. | air gap density is directly proportional to the voltage |
B. | air gap density is indirectly proportional to the voltage |
C. | air gap density is directly proportional to the square of the voltage |
D. | air gap density is indirectly proportional to the square of the voltage |
Answer» C. air gap density is directly proportional to the square of the voltage | |
16. |
How is the iron loss related with the choice of specific magnetic loading? |
A. | choice of magnetic loading is directly proportional to the iron loss |
B. | choice of magnetic loading is indirectly proportional to the iron loss |
C. | choice of magnetic loading is directly proportional to the square of the iron loss |
D. | choice of magnetic loading is indirectly proportional to the square of the iron loss |
Answer» B. choice of magnetic loading is indirectly proportional to the iron loss | |
17. |
How many factors does the choice of specific magnetic loading depend upon? |
A. | 4 |
B. | 2 |
C. | 5 |
D. | 8 |
Answer» D. 8 | |
18. |
What is the formula for the output equation with respect to the peripheral speed? |
A. | output = 1.11* specific magnetic loading * specific electrical loading * winding space factor * 10<sup>-3</sup> * peripheral speed<sup>2</sup> *Length * synchronous speed |
B. | output = 1.11* specific magnetic loading * specific electrical loading * winding space factor * 10<sup>-3</sup> * peripheral speed<sup>2</sup> *Length / synchronous speed |
C. | output = 1.11* specific magnetic loading * specific electrical loading * winding space factor / 10<sup>-3</sup> * peripheral speed<sup>2</sup> *Length * synchronous speed |
D. | output = 1.110 / specific magnetic loading * specific electrical loading * winding space factor * 10<sup>-3</sup> * peripheral speed<sup>2</sup> *Length * synchronous speed |
Answer» C. output = 1.11* specific magnetic loading * specific electrical loading * winding space factor / 10<sup>-3</sup> * peripheral speed<sup>2</sup> *Length * synchronous speed | |
19. |
What is the formula of the output coefficient? |
A. | output coefficient = 11 * specific magnetic loading / specific electrical loading * winding space factor * 10<sup>-3</sup> |
B. | output coefficient = 11 / specific magnetic loading * specific electrical loading * winding space factor * 10<sup>-3</sup> |
C. | output coefficient = 11 * specific magnetic loading * specific electrical loading * winding space factor * 10<sup>-3</sup> |
D. | output coefficient = 11 * specific magnetic loading * specific electrical loading / winding space factor * 10<sup>-3</sup> |
Answer» D. output coefficient = 11 * specific magnetic loading * specific electrical loading / winding space factor * 10<sup>-3</sup> | |
20. |
What is the formula for output equation in synchronous machines? |
A. | kVA output = output coefficient * diameter2 * length * synchronous speed |
B. | kVA output = output coefficient / diameter2 * length * synchronous speed |
C. | kVA output = output coefficient * diameter2 / length * synchronous speed |
D. | kVA output = output coefficient * diameter2 * length / synchronous speed |
Answer» B. kVA output = output coefficient / diameter2 * length * synchronous speed | |