

MCQOPTIONS
Saved Bookmarks
This section includes 20 Mcqs, each offering curated multiple-choice questions to sharpen your Design Electrical Machines knowledge and support exam preparation. Choose a topic below to get started.
1. |
What is the formula for the length of the tank? |
A. | length of the tank = external diameter of h.v winding + clearance on each side between the winding and tank along the width |
B. | length of the tank = external diameter of h.v winding * clearance on each side between the winding and tank along the width |
C. | length of the tank = external diameter of h.v winding + 2*clearance on each side between the winding and tank along the width |
D. | length of the tank = external diameter of h.v winding / 2*clearance on each side between the winding and tank along the width |
Answer» D. length of the tank = external diameter of h.v winding / 2*clearance on each side between the winding and tank along the width | |
2. |
What is the formula for width of the tank for single phase transformers used? |
A. | width of tank = 2*distance between adjacent limbs + external diameter of h.v windings + 2*clearance between h.v windings and tank |
B. | width of tank = distance between adjacent limbs + external diameter of h.v windings + 2*clearance between h.v windings and tank |
C. | width of tank = 2*distance between adjacent limbs * external diameter of h.v windings + 2*clearance between h.v windings and tank |
D. | width of tank = distance between adjacent limbs * external diameter of h.v windings + 2*clearance between h.v windings and tank |
Answer» C. width of tank = 2*distance between adjacent limbs * external diameter of h.v windings + 2*clearance between h.v windings and tank | |
3. |
Elliptical tubes with pressed radiators are increasingly been used. |
A. | true |
B. | false |
Answer» B. false | |
4. |
What is the range of the diameter of the tubes used? |
A. | 50-60 mm |
B. | 60-70 mm |
C. | 70-80 mm |
D. | 50-70 mm |
Answer» E. | |
5. |
An addition of 35 percent should be made to tube area of the transformers. |
A. | true |
B. | false |
Answer» B. false | |
6. |
ELLIPTICAL_TUBES_WITH_PRESSED_RADIATORS_ARE_INCREASINGLY_BEEN_USED??$ |
A. | true |
B. | false |
Answer» B. false | |
7. |
WHAT_IS_THE_RANGE_OF_THE_DIAMETER_OF_THE_TUBES_USED??$ |
A. | 50-60 mm |
B. | 60-70 mm |
C. | 70-80 mm |
D. | 50-70 mm |
Answer» E. | |
8. |
What is the formula for the length of the tank?$ |
A. | length of the tank = external diameter of h.v winding + clearance on each side between the winding and tank along the width |
B. | length of the tank = external diameter of h.v winding * clearance on each side between the winding and tank along the width |
C. | length of the tank = external diameter of h.v winding + 2*clearance on each side between the winding and tank along the width |
D. | length of the tank = external diameter of h.v winding / 2*clearance on each side between the winding and tank along the width |
Answer» D. length of the tank = external diameter of h.v winding / 2*clearance on each side between the winding and tank along the width | |
9. |
What is the formula for width of the tank for single phase transformers used?$ |
A. | width of tank = 2*distance between adjacent limbs + external diameter of h.v windings + 2*clearance between h.v windings and tank |
B. | width of tank = distance between adjacent limbs + external diameter of h.v windings + 2*clearance between h.v windings and tank |
C. | width of tank = 2*distance between adjacent limbs * external diameter of h.v windings + 2*clearance between h.v windings and tank |
D. | width of tank = distance between adjacent limbs * external diameter of h.v windings + 2*clearance between h.v windings and tank |
Answer» C. width of tank = 2*distance between adjacent limbs * external diameter of h.v windings + 2*clearance between h.v windings and tank | |
10. |
What is the rating of the transformer for the voltage of above 11 kV upto 33 kV? |
A. | 1000-5000 kVA |
B. | less than 1000 kVA |
C. | above 1000 kVA |
D. | 100-500 kVA |
Answer» C. above 1000 kVA | |
11. |
What is the rating of the transformer for the voltage of about 11 kV? |
A. | 1000-2000 kVA |
B. | 100-3000 kVA |
C. | 1000-5000 kVA |
D. | 100-500 kVA |
Answer» D. 100-500 kVA | |
12. |
What is the formula for height of transformer tank? |
A. | height of transformer tank = Height of transformer frame + clearance height between the assembled transformer and tank |
B. | height of transformer tank = Height of transformer frame * clearance height between the assembled transformer and tank |
C. | height of transformer tank = Height of transformer frame / clearance height between the assembled transformer and tank |
D. | height of transformer tank = Height of transformer frame – clearance height between the assembled transformer and tank |
Answer» B. height of transformer tank = Height of transformer frame * clearance height between the assembled transformer and tank | |
13. |
What is the formula for number of tubes? |
A. | number of tubes = (1/ 8 * area of each tube) * (total loss / temperature rise with tubes – 12.5 * dissipating surface) |
B. | number of tubes = (1* 8 * area of each tube) * (total loss / temperature rise with tubes – 12.5 * dissipating surface) |
C. | number of tubes = (1/ 8 * area of each tube) / (total loss / temperature rise with tubes – 12.5 * dissipating surface) |
D. | number of tubes = (1/ 8 * area of each tube) + (total loss / temperature rise with tubes – 12.5 * dissipating surface) |
Answer» B. number of tubes = (1* 8 * area of each tube) * (total loss / temperature rise with tubes ‚Äö√Ñ√∂‚àö√ë‚àö¬® 12.5 * dissipating surface) | |
14. |
What is the formula for temperature rise with tubes? |
A. | temperature rise with tubes = total loss / dissipating surface*(12.5 + 8.8x) |
B. | temperature rise with tubes = total loss * dissipating surface*(12.5 + 8.8x) |
C. | temperature rise with tubes = total loss / dissipating surface / (12.5 + 8.8x) |
D. | temperature rise with tubes = total loss + dissipating surface*(12.5 + 8.8x) |
Answer» B. temperature rise with tubes = total loss * dissipating surface*(12.5 + 8.8x) | |
15. |
What is the loss dissipated by tubes by convection, given area of the tubes = 3.5? |
A. | 12.3 W per 0c |
B. | 2.51 W per 0c |
C. | 5.3 W per 0c |
D. | 30.8 W per 0c |
Answer» E. | |
16. |
An addition of 35 per cent should be made to tube area of the transformers? |
A. | true |
B. | false |
Answer» B. false | |
17. |
How is the circulation of oil improved in tanks with tubes? |
A. | it can be improved by using dissipating heat |
B. | it can be improved by using more effective air circulation |
C. | it can be improved by using more effect power flow |
D. | it can be improved by using more effective heads of pressure |
Answer» E. | |
18. |
What is the relation of the transformer surface with respect to dissipation of heat? |
A. | transformer surface has no relation with respect to dissipation of heat |
B. | transformer surface has minor changes with respect to dissipation of heat |
C. | transformer surface has major changes with respect to dissipation of heat |
D. | transformer surface has no change with respect to dissipation of heat |
Answer» E. | |
19. |
What is the relation of the provision of tubes with respect to dissipation of heat? |
A. | the provision of tubes is directly proportional to the dissipation of heat |
B. | the provision of tubes is indirectly proportional to the dissipation of heat |
C. | the provision of tubes is directly proportional to square of the dissipation of heat |
D. | the provision of tubes is indirectly proportional to square of the dissipation of heat |
Answer» C. the provision of tubes is directly proportional to square of the dissipation of heat | |
20. |
What is the usage of the tanks with tubes? |
A. | if the temperature rise with plain tank is very low |
B. | if the temperature rise with plain tank is very high |
C. | if the temperature rise is zero |
D. | if the temperature rise with plain tank exceeds the specific limits |
Answer» E. | |