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This section includes 68 Mcqs, each offering curated multiple-choice questions to sharpen your C Programming knowledge and support exam preparation. Choose a topic below to get started.
1. |
The RAID devotes all of its resources to performing reconstruction, is a |
A. | Online reconstruction |
B. | Offline reconstruction |
C. | Offline deconstruction |
D. | Online deconstruction |
Answer» C. Offline deconstruction | |
2. |
Exponential distribution, is such a distribution ehich has a C, of value |
A. | 0 |
B. | 1 |
C. | 2 |
D. | 3 |
Answer» C. 2 | |
3. |
A fault creates one or more |
A. | Latent error |
B. | Mistake |
C. | Failure |
D. | None of above |
Answer» B. Mistake | |
4. |
The sum of entry time, system response time and think time is known as |
A. | Transaction time |
B. | Latency |
C. | Clock rate |
D. | Hit delay |
Answer» B. Latency | |
5. |
The times between two successive requests arriving, called the |
A. | Interarrival time |
B. | Arrival time |
C. | Poisson distribution |
D. | Average residual service time |
Answer» B. Arrival time | |
6. |
When this effective error produces erroneous data that affect the delivered service, then |
A. | Error occurs |
B. | Failure occurs |
C. | Fault occurs |
D. | All above |
Answer» C. Fault occurs | |
7. |
In a RAID disk array, the logical unit is configured as a particular RAID layout, such as |
A. | RAID 4 |
B. | RAID 5 |
C. | RAID 6 |
D. | RAID 7 |
Answer» C. RAID 6 | |
8. |
The average arrival rate of new tasks, and the average time to perform a task is: |
A. | Mean number of tasks in system = Arrival rate / Mean response time |
B. | Mean number of tasks in system = Arrival rate + Mean response time |
C. | Mean number of tasks in system = Arrival rate - Mean response time |
D. | Mean number of tasks in system = Arrival rate |
Answer» E. | |
9. |
The failure occurred because of an error, a defect in that module. The cause of an error is a |
A. | Error |
B. | Mistake |
C. | Fail |
D. | Corruption |
Answer» B. Mistake | |
10. |
The area where the tasks accumulate, waiting to be serviced, is called the |
A. | Queue |
B. | Waiting line |
C. | DIMM |
D. | Both a and b |
Answer» E. | |
11. |
The later added suppport known as RAID 6 is also called a |
A. | Row-diagonal parity |
B. | RAID-DP |
C. | RADI 7 |
D. | Both a and b |
Answer» E. | |
12. |
An I/O system with a single disk gets on average 50 I/O requests per second and the average time for a disk to service an I/O request is 10 ms, the utilization of the I/O system would be |
A. | 0.2 |
B. | 0.5 |
C. | 0.75 |
D. | 1.5 |
Answer» C. 0.75 | |
13. |
RAID 0 has no redundancy and is sometimes nicknamed as |
A. | BJOD |
B. | SAIL |
C. | DIMM |
D. | JBOD |
Answer» E. | |
14. |
Bits or blocks in a file going bad over time, is a |
A. | Interarrival time |
B. | Logical volumes |
C. | Bit rot |
D. | All above |
Answer» D. All above | |
15. |
The …………….. policy segments the disks request queue into sub queues of the length N. |
A. | SCAN |
B. | C-SCAN |
C. | N-Step SCAN |
D. | FSCAN |
Answer» D. FSCAN | |
16. |
The capacity of a memory unit = (the number of words) * (the number of bits / words). What will be the number of separate address and data lines needed for a memory of 4k * 16 ? |
A. | 12 address and 16 data lines |
B. | 12 address and 12 data lines |
C. | 11 address and 6 data lines |
D. | 12 address and 8 data lines |
Answer» B. 12 address and 12 data lines | |
17. |
What will happen when we format a floppy disk? |
A. | Identification information is written on all tracks and sectors |
B. | The system area is deleted |
C. | Data is written |
D. | Data is arranged on the disk in contiguous fashion |
Answer» E. | |
18. |
Average time/task in the system, or the response time, which is the sum of Time queue and Time server is |
A. | Time system |
B. | Time server |
C. | Time queue |
D. | Arrival rate |
Answer» B. Time server | |
19. |
What works on the principle of locality? |
A. | Cache memory |
B. | Interrupts |
C. | Polling |
D. | DMA |
Answer» B. Interrupts | |
20. |
Data are allocated to disks in the RAID at the |
A. | Block level |
B. | Cache level |
C. | Low level |
D. | High level |
Answer» B. Cache level | |
21. |
Server utilization (and, in this case, the mean number of tasks per server) is simply: |
A. | Server utilization = Arrival rate - Timeserver |
B. | Server utilization = Arrival rate + Timeserver |
C. | Server utilization = Arrival rate |
D. | Server utilization = Arrival rate / Timeserver |
Answer» D. Server utilization = Arrival rate / Timeserver | |
22. |
A server utilization of 0.5, the mean number of I/O requests in the queue is |
A. | 1.5 |
B. | 0.75 |
C. | (0.5)^2 |
D. | 0.5 |
Answer» E. | |
23. |
The memory allocation scheme subject to “external” fragmentation is |
A. | segmentation |
B. | swapping |
C. | pure demand paging |
D. | multiple fixed contiguous partitions |
Answer» B. swapping | |
24. |
I/O throughput is sometimes called I/O bandwidth and response time is sometimes called |
A. | Delay |
B. | Mistake |
C. | Failure |
D. | Latency |
Answer» E. | |
25. |
The operating system typically provides the file abstraction on top of blocks stored on the disk, called |
A. | Logical units |
B. | Logical volumes |
C. | Physical volumes |
D. | Both a and b |
Answer» E. | |
26. |
The Poisson distribution is described by the following equation (called the probability mass function): |
A. | Probability(k) = e^ a*a^k/k! |
B. | Probability(k) = e^ |
C. | Probability(k) = e^ |
D. | Probability(k) = e^ |
Answer» C. Probability(k) = e^ | |
27. |
Consider a computer with 8 Mbytes of main memory and a 128 K cache. The cache block size is 4 K. It uses a direct mapping scheme for cache management. How many different main memory blocks can map onto a given physical cache block ? |
A. | 2048 |
B. | 256 |
C. | 64 |
D. | 8 |
Answer» D. 8 | |
28. |
The squared coefficient of variance, traditionally called |
A. | C^2 |
B. | C^3 |
C. | S^2 |
D. | S^3 |
Answer» B. C^3 | |
29. |
Improvement in capacity; measured in bits per square inch, refered to |
A. | WAR stall |
B. | Instruction optimizer |
C. | Window |
D. | Areal density |
Answer» E. | |
30. |
Each entry in a Translation look-aside buffer (TLB) consists of : |
A. | key |
B. | value |
C. | bit value |
D. | constant |
Answer» B. value | |
31. |
Improvement in capacity is customarily expressed as improvement in |
A. | WAR and WAW stalls |
B. | WAR stall |
C. | Areal density |
D. | Unoptimized code |
Answer» D. Unoptimized code | |
32. |
Throughput is the performance metric, but response times are |
A. | Best |
B. | Delay |
C. | Limited |
D. | None of above |
Answer» D. None of above | |
33. |
If interarrival times are exponentially distributed, the number ofarrivals in a time interval t is a |
A. | Passion distribution |
B. | Poisson process |
C. | Poisson distribution |
D. | Both a and b |
Answer» C. Poisson distribution | |
34. |
In fixed sized partition, the degree of multi programming is bounded by ___________ |
A. | the number of partitions |
B. | the CPU utilization |
C. | the memory size |
D. | all of the mentioned |
Answer» B. the CPU utilization | |
35. |
The disks found inside a server connected to an I/O bus, is refered as |
A. | Indirect memory module |
B. | Direct memory module |
C. | Direct attached |
D. | Indirect attached |
Answer» D. Indirect attached | |
36. |
Adding the 0.1 ms ATA controller overhead means 0.2 ms to 0.5 ms per I/O, making the maximum rate per controller |
A. | 500 IOPS and 300 IOPS |
B. | 5000 IOPS and 3000 IOPS |
C. | 3000 IOPS and 2000 IOPS |
D. | 5000 IOPS and 2000 IOPS |
Answer» E. | |
37. |
The network protocol stacks use about |
A. | 100 CPU instructions |
B. | 1000 CPU instructions |
C. | 10,000 CPU instructions |
D. | 100,000 CPU instructions |
Answer» E. | |
38. |
When a fault occurs, it creates a latent error, when gets activated, becomes |
A. | Error |
B. | Mistake |
C. | Effective |
D. | Corruption |
Answer» D. Corruption | |
39. |
The time between the occurrence of an error and the resulting failure is the |
A. | Effection |
B. | Mistake |
C. | Latent error |
D. | Error latency |
Answer» E. | |
40. |
Faults that do not correct themselves with the passing of time, are |
A. | Temporary faults |
B. | Mistakes |
C. | Permanent faults |
D. | Failures |
Answer» D. Failures | |
41. |
For disks with more than 200 cylinders, the seek distance is: |
A. | Seek time(Distance) = a |
B. | Seek time(Distance) = a |
C. | Seek time(Distance) = a /( Distance |
D. | Seek time(Distance) = a |
Answer» B. Seek time(Distance) = a | |
42. |
The time for the user to enter the command, is refered as |
A. | System response time |
B. | Entry time |
C. | Delay |
D. | Latency |
Answer» C. Delay | |
43. |
The average residual service time, which again assumes Poisson arrivals as: |
A. | Average residual service time= 1/Arithemtic mean+(1+ C^2) |
B. | Average residual service time= 2xArithemtic mean+(1+ C^2) |
C. | Average residual service time=1/ 2xArithemtic mean+(1+ C^2) |
D. | Average residual service time=1/ 2xArithemtic meanx(1+ C^2) |
Answer» D. Average residual service time=1/ 2xArithemtic meanx(1+ C^2) | |
44. |
Redundant array, that is known as mirroring or shadowing is |
A. | RAID 0 |
B. | RAID 1 |
C. | RAID 2 |
D. | RAID 3 |
Answer» C. RAID 2 | |
45. |
Memory management is |
A. | not used in modern operating system |
B. | replaced with virtual memory on current system |
C. | not used on multiprogramming systems |
D. | critical for even the simplest operating system |
Answer» C. not used on multiprogramming systems | |
46. |
The I/O bus limits the maximum performance to no more than 18,600 IOPS for 16 KB blocks, then the transfer time would be |
A. | 0.1 ms |
B. | 0.2 ms |
C. | 0.1 ns |
D. | 0.2 ns |
Answer» B. 0.2 ms | |
47. |
The different types of tables maintained by the operating system are ............. |
A. | memory, logical , I/O file |
B. | memory, I/O, file, physical |
C. | memory, I/O, file, process |
D. | memory, logical, I/O, physical |
Answer» D. memory, logical, I/O, physical | |
48. |
Which of the following information not included in memory table ? |
A. | The allocation of main memory to process |
B. | The allocation of secondary memory to process |
C. | Any information needed to manage virtual memory |
D. | Any information about the existence of file |
Answer» E. | |
49. |
…………. Involves treating main memory as a resource to be allocated to and shared among a number of active processes. |
A. | Partition management |
B. | Memory management |
C. | Disk management |
D. | All of the above |
Answer» C. Disk management | |
50. |
The RAID continues to service workload requests while performing the reconstruction, is a |
A. | Online reconstruction |
B. | Offline reconstruction |
C. | Online deconstruction |
D. | Offline deconstruction |
Answer» B. Offline reconstruction | |