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1. |
The average residual service time, which again assumes Poisson arrivals as: |
A. | Average residual service time= 1/Arithemtic mean+(1+ C^2) |
B. | Average residual service time= 2xArithemtic mean+(1+ C^2) |
C. | Average residual service time=1/ 2xArithemtic mean+(1+ C^2) |
D. | Average residual service time=1/ 2xArithemtic meanx(1+ C^2) |
Answer» D. Average residual service time=1/ 2xArithemtic meanx(1+ C^2) | |