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This section includes 30 Mcqs, each offering curated multiple-choice questions to sharpen your Network Theory knowledge and support exam preparation. Choose a topic below to get started.
1. |
If a star connected system has equal impedances Z1, then after converting into delta connected system having equal impedances Z2, then? |
A. | Z2 = Z1 |
B. | Z2 = 2Z1 |
C. | Z2 = 3Z1 |
D. | Z2 = 4Z1 |
Answer» D. Z2 = 4Z1 | |
2. |
A symmetrical three-phase, three-wire 440V supply is connected to star-connected load. The impedances in each branch are ZR = (2+j3) Ω, ZY = (1-j2) Ω, ZB = (3+j4) Ω. Find ZBR. |
A. | (5.22-j0.82) Ω |
B. | (-3.02+j8) Ω |
C. | (-5.22+j0.82) Ω |
D. | (3.8-j0.38) Ω |
Answer» C. (-5.22+j0.82) Ω | |
3. |
A symmetrical three-phase, three-wire 440V supply is connected to star-connected load. The impedances in each branch are ZR = (2+j3) Ω, ZY = (1-j2) Ω, ZB = (3+j4) Ω. Find ZBY. |
A. | (-5.22+j0.82) Ω |
B. | (5.22-j0.82) Ω |
C. | (3.8-j0.38) Ω |
D. | (-3.02+j8) Ω |
Answer» C. (3.8-j0.38) Ω | |
4. |
A symmetrical three-phase, three-wire 440V supply is connected to star-connected load. The impedances in each branch are ZR = (2+j3) Ω, ZY = (1-j2) Ω, ZB = (3+j4) Ω. Find ZRY. |
A. | (5.22-j0.82) Ω |
B. | (-3.02+j8) Ω |
C. | (3.8-j0.38) Ω |
D. | (-5.22+j0.82) Ω |
Answer» D. (-5.22+j0.82) Ω | |
5. |
If the resistors of star connected system are ZR, ZY, ZB then the impedance ZBR in delta connected system will be? |
A. | (ZRZY + ZYZB + ZBZR)/ZY |
B. | (ZRZY + ZYZB + ZBZR)/R |
C. | (ZRZY + ZYZB + ZBZR)/ZB |
D. | (ZRZY + ZYZB + ZBZR)/(ZB+ZR) |
Answer» B. (ZRZY + ZYZB + ZBZR)/R | |
6. |
If the resistors of star connected system are ZR, ZY, ZB then the impedance ZBY in delta connected system will be? |
A. | (ZRZY + ZYZB + ZBZR)/(ZB+ZY) |
B. | (ZRZY + ZYZB + ZBZR)/ZB |
C. | (ZRZY + ZYZB + ZBZR)/ZY |
D. | (ZRZY + ZYZB + ZBZR)/ZR |
Answer» E. | |
7. |
If the resistors of star connected system are ZR, ZY, ZB then the impedance ZRY in delta connected system will be? |
A. | (ZRZY + ZYZB + ZBZR)/ZB |
B. | (ZRZY + ZYZB + ZBZR)/ZY |
C. | (ZRZY + ZYZB + ZBZR)/ZR |
D. | (ZRZY + ZYZB + ZBZR)/(ZR+ZY) |
Answer» B. (ZRZY + ZYZB + ZBZR)/ZY | |
8. |
If a resistor ZR is connected between R and N, ZBR between R and B, ZRY between R and Y and ZBY between B and Y form a delta connection, then after transformation to star, the impedance at B is? |
A. | (ZBRZBY)/(ZRY+ZBY+ZBR) |
B. | (ZRYZBY)/(ZRY+ZBY+ZBR) |
C. | (ZBY)/(ZRY+ZBY+ZBR) |
D. | (ZBR)/(ZRY+ZBY+ZBR) |
Answer» B. (ZRYZBY)/(ZRY+ZBY+ZBR) | |
9. |
If a resistor ZR is connected between R and N, ZBR between R and B, ZRY between R and Y and ZBY between B and Y form a delta connection, then after transformation to star, the impedance at Y is? |
A. | (ZRY)/(ZRY+ZBY+ZBR) |
B. | (ZBY)/(ZRY+ZBY+ZBR) |
C. | (ZRYZBY)/(ZRY+ZBY+ZBR) |
D. | (ZRYZBR)/(ZRY+ZBY+ZBR) |
Answer» D. (ZRYZBR)/(ZRY+ZBY+ZBR) | |
10. |
If a resistor ZR is connected between R and N, ZBR between R and B, ZRY between R and Y and ZBY between B and Y form a delta connection, then after transformation to star, the impedance at R is? |
A. | (ZBRZBY)/(ZRY+ZBY+ZBR) |
B. | (ZRYZBR)/(ZRY+ZBY+ZBR) |
C. | (ZRYZBY)/(ZRY+ZBY+ZBR) |
D. | (ZRY)/(ZRY+ZBY+ZBR) |
Answer» C. (ZRYZBY)/(ZRY+ZBY+ZBR) | |
11. |
Find the equivalent resistance between A and B. |
A. | 32ohm |
B. | 31ohm |
C. | 30ohm |
D. | 29ohm |
Answer» E. | |
12. |
If an 8/9ohm, 4/3ohm and 2/3ohm resistor is connected in star, find its delta equivalent. |
A. | 4ohm, 3ohm, 2ohm |
B. | 1ohm, 3ohm, 2ohm |
C. | 4ohm, 1ohm, 2ohm |
D. | 4ohm, 3ohm, 1ohm |
Answer» B. 1ohm, 3ohm, 2ohm | |
13. |
If a 1ohm 2ohm and 32/3ohm resistor is connected in star, find the equivalent delta connection. |
A. | 34 ohm, 18.67 ohm, 3.19 ohm |
B. | 33 ohm, 18.67 ohm, 3.19 ohm |
C. | 33 ohm, 19.67 ohm, 3.19 ohm |
D. | 34 ohm, 19.67 ohm, 3.19 ohm |
Answer» B. 33 ohm, 18.67 ohm, 3.19 ohm | |
14. |
Ra is resistance at A, Rb is resistance at B, Rc is resistance at C in star connection. After transforming to delta, what is resistance between A and B? |
A. | Rc+Rb+Ra*Rb/Rc |
B. | Ra+Rb+Ra*Rc/Rb |
C. | Ra+Rb+Ra*Rb/Rc |
D. | Ra+Rc+Ra*Rc/Rb |
Answer» D. Ra+Rc+Ra*Rc/Rb | |
15. |
Ra is resistance at A, Rb is resistance at B, Rc is resistance at C in star connection. After transforming to delta, what is resistance between A and C? |
A. | Ra+Rb+Ra*Rb/Rc |
B. | Ra+Rc+Ra*Rc/Rb |
C. | Ra+Rb+Ra*Rc/Ra |
D. | Ra+Rc+Ra*Rb/Rc |
Answer» C. Ra+Rb+Ra*Rc/Ra | |
16. |
Ra is resistance at A, Rb is resistance at B, Rc is resistance at C in star connection. After transforming to delta, what is resistance between B and C? |
A. | Rc+Rb+Rc*Rb/Ra |
B. | Rc+Rb+Ra*Rb/Rc |
C. | Ra+Rb+Ra*Rc/Rb |
D. | Rc+Rb+Rc*Ra/Rb |
Answer» B. Rc+Rb+Ra*Rb/Rc | |
17. |
Find the equivalent resistance between X and Y. |
A. | 3.33 ohm |
B. | 4.34 ohm |
C. | 5.65 ohm |
D. | 2.38 ohm |
Answer» E. | |
18. |
Find the equivalent delta circuit. |
A. | 9.69 ohm, 35.71 ohm, 6.59 ohm |
B. | 10.69 ohm, 35.71 ohm, 6.59 ohm |
C. | 9.69 ohm, 34.71 ohm, 6.59 ohm |
D. | 10.69 ohm, 35.71 ohm, 7.59 ohm |
Answer» B. 10.69 ohm, 35.71 ohm, 6.59 ohm | |
19. |
FIND_ZBR.?$ |
A. | (5.22-j0.82) Ω |
B. | (-3.02+j8) Ω |
C. | (-5.22+j0.82) Ω |
D. | (3.8-j0.38) Ω |
Answer» C. (-5.22+j0.82) ‚Äö√Ñ√∂‚àö√´¬¨‚àÇ | |
20. |
IF_AN_8/9OHM,_4/3OHM_AND_2/3OHM_RESISTOR_IS_CONNECTED_IN_STAR,_FIND_ITS_DELTA_EQUIVALENT.?$ |
A. | 4ohm, 3ohm, 2ohm |
B. | 1ohm, 3ohm, 2ohm |
C. | 4ohm, 1ohm, 2ohm |
D. | 4ohm, 3ohm, 1ohm |
Answer» B. 1ohm, 3ohm, 2ohm | |
21. |
If_a_star_connected_system_has_equal_impedances_Z1,_then_after_converting_into_delta_connected_system_having_equal_impedances_Z2,_then?$ |
A. | Z<sub>2</sub> = Z<sub>1</sub> |
B. | Z<sub>2</sub> = 2Z<sub>1</sub> |
C. | Z<sub>2</sub> = 3Z<sub>1</sub> |
D. | Z<sub>2</sub> = 4Z<sub>1</sub> |
Answer» D. Z<sub>2</sub> = 4Z<sub>1</sub> | |
22. |
Find ZBY in the question 7? |
A. | (-5.22+j0.82) Ω |
B. | (5.22-j0.82) Ω |
C. | (3.8-j0.38) Ω |
D. | (-3.02+j8) Ω |
Answer» C. (3.8-j0.38) ‚Äö√Ñ√∂‚àö√´¬¨‚àÇ | |
23. |
If a 1ohm 2ohm and 32/3ohm resistor is connected in star, find the equivalent delta connection? |
A. | 1ohm, 3ohm, 2ohm |
B. | 4ohm, 3ohm, 5ohm |
C. | 4ohm, 5ohm, 2ohm |
D. | 5ohm, 3ohm, 2ohm |
Answer» B. 4ohm, 3ohm, 5ohm | |
24. |
A symmetrical three-phase, three-wire 440V supply is connected to star-connected load. The impedances in each branch are ZR = (2+j3) Ω, ZY = (1-j2) Ω, ZB = (3+j4) Ω. Find ZRY.$ |
A. | (5.22-j0.82) Ω |
B. | (-3.02+j8) Ω |
C. | (3.8-j0.38) Ω |
D. | (-5.22+j0.82) Ω |
Answer» D. (-5.22+j0.82) ‚Äö√Ñ√∂‚àö√´¬¨‚àÇ | |
25. |
Rab is the resistance between the terminals A and B, Rbc between B and C and Rca between C and A. These 3 resistors are connected in star connection. After transforming to delta, the resistance at A will be? |
A. | Rc+Rb+Rc*Rb/Ra |
B. | Rc+Rb+Ra*Rb/Rc |
C. | Ra+Rb+Ra*Rc/Rb |
D. | Rc+Rb+Rc*Ra/Rb |
Answer» B. Rc+Rb+Ra*Rb/Rc | |
26. |
If the resistors of star connected system are ZR, ZY, ZB then the impedance ZRY in delta connected system will be? |
A. | (Z<sub>R</sub>Z<sub>Y</sub>+ Z<sub>Y</sub>Z<sub>B</sub>+ Z<sub>B</sub>Z<sub>R</sub>)/Z<sub>B</sub> |
B. | (Z<sub>R</sub>Z<sub>Y</sub>+ Z<sub>Y</sub>Z<sub>B</sub>+ Z<sub>B</sub>Z<sub>R</sub>)/Z<sub>Y</sub> |
C. | (Z<sub>R</sub>Z<sub>Y</sub>+ Z<sub>Y</sub>Z<sub>B</sub>+ Z<sub>B</sub>Z<sub>R</sub>)/Z<sub>R</sub> |
D. | (Z<sub>R</sub>Z<sub>Y</sub>+ Z<sub>Y</sub>Z<sub>B</sub>+ Z<sub>B</sub>Z<sub>R</sub>)/(Z<sub>R</sub>+Z<sub>Y</sub> ) |
Answer» B. (Z<sub>R</sub>Z<sub>Y</sub>+ Z<sub>Y</sub>Z<sub>B</sub>+ Z<sub>B</sub>Z<sub>R</sub>)/Z<sub>Y</sub> | |
27. |
Delta connection is also known as____________ |
A. | Y-connection |
B. | Mesh connection |
C. | Either Y-connection or mesh connection |
D. | Neither Y-connection nor mesh connection |
Answer» C. Either Y-connection or mesh connection | |
28. |
Which, among the following is the correct expression for star-delta conversion? |
A. | R1=Ra*Rb/(Ra+Rb+Rc), R2=Rb*Rc/(Ra+Rb+Rc), R3=Rc*Ra/(Ra+Rb+Rc)b) |
B. | R1=Ra/(Ra+Rb+Rc), R2=Rb/(Ra+Rb+Rc), Rc=/(Ra+Rb+Rc) |
C. | R1=Ra+Rb+Ra*Rb/Rc, R2=Rc+Rb+Rc*Rb/Ra, R3=Ra+Rc+Ra*Rc/Rb |
D. | R1=Ra*Rb/Rc, R2=Rc*Rb/Ra, R3=Ra*Rc/Rb |
Answer» D. R1=Ra*Rb/Rc, R2=Rc*Rb/Ra, R3=Ra*Rc/Rb | |
29. |
In the question above the impedance at Y is? |
A. | (Z<sub>RY</sub>)/(Z<sub>RY</sub>+Z<sub>BY</sub>+Z<sub>BR</sub>) |
B. | (Z<sub>BY</sub>)/(Z<sub>RY</sub>+Z<sub>BY</sub>+Z<sub>BR</sub>) |
C. | (Z<sub>RY</sub>Z<sub>BY</sub>)/(Z<sub>RY</sub>+Z<sub>BY</sub>+Z<sub>BR</sub>) |
D. | (Z<sub>RY</sub>Z<sub>BR</sub>)/(Z<sub>RY</sub>+Z<sub>BY</sub>+Z<sub>BR</sub>) |
Answer» D. (Z<sub>RY</sub>Z<sub>BR</sub>)/(Z<sub>RY</sub>+Z<sub>BY</sub>+Z<sub>BR</sub>) | |
30. |
If a resistor ZR is connected between R and N, ZBR between R and B, ZRY between R and Y and ZBY between B and Y form a delta connection, then after transformation to star, the impedance at R is? |
A. | (Z<sub>BR</sub>Z<sub>BY</sub>)/(Z<sub>RY</sub>+Z<sub>BY</sub>+Z<sub>BR</sub>) |
B. | (Z<sub>RY</sub>Z<sub>BR</sub>)/(Z<sub>RY</sub>+Z<sub>BY</sub>+Z<sub>BR</sub>) |
C. | (Z<sub>RY</sub>Z<sub>BY</sub>)/(Z<sub>RY</sub>+Z<sub>BY</sub>+Z<sub>BR</sub>) |
D. | (Z<sub>RY</sub>)/(Z<sub>RY</sub>+Z<sub>BY</sub>+Z<sub>BR</sub>) |
Answer» C. (Z<sub>RY</sub>Z<sub>BY</sub>)/(Z<sub>RY</sub>+Z<sub>BY</sub>+Z<sub>BR</sub>) | |