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This section includes 23 Mcqs, each offering curated multiple-choice questions to sharpen your Machine Kinematics knowledge and support exam preparation. Choose a topic below to get started.
1. |
In SHM, what is the phase difference between velocity and acceleration? |
A. | 0 |
B. | π |
C. | π/2 |
D. | π/3 |
Answer» D. π/3 | |
2. |
In an SHM the time taken to go from mean position to A/2 is the same as that from A/2 to A. True or False? Here, A is the amplitude of motion. |
A. | True |
B. | False |
Answer» C. | |
3. |
What is the amplitude of motion for x = 2sin(2t) + 4sin2t ? |
A. | 2√2 m |
B. | 4 m |
C. | 2 m |
D. | The given equation is not that of an SHM |
Answer» B. 4 m | |
4. |
A particle starts from the extreme position, at t = 0, in a SHM. If the time period of motion is 2s & maximum speed is 5m/s, find the equation of motion. |
A. | x = 1.59cos(πt) |
B. | x = 1.59sin(πt) |
C. | x = 2.5sin(2t) |
D. | x = 2.5cos(2t) |
Answer» B. x = 1.59sin(πt) | |
5. |
What is the relation between time periods of the two given SHMs. |
A. | 4T1 = T2 |
B. | T1 = 2T2 |
C. | 2T1 = T2 |
D. | T1 = 4T2 |
Answer» D. T1 = 4T2 | |
6. |
A particle has an equation of motion given by: x = cos2wt – sin2wt. Select the correct statement regarding the same. |
A. | It is not a SHM |
B. | It is a SHM with T = π/w |
C. | It is an SHM with T = 2π/w |
D. | Amplitude of motion is 1/√2 m |
Answer» C. It is an SHM with T = 2π/w | |
7. |
2 particles undergoing SHM start from the mean position and go in opposite directions. Particle 1 starts with a speed of 10m/s and particle 2 starts with a speed 0f 5m/s. If the amplitude(=10cm) is the same. At what position will they first meet? |
A. | 0.0866m |
B. | -0.0633m |
C. | 0 |
D. | 0.0633m |
Answer» B. -0.0633m | |
8. |
The displacement vs time graphs of 2 SHMs are given below. Which parameter is the same for both of them? |
A. | Angular frequency |
B. | Amplitude |
C. | Maximum speed |
D. | Phase constant |
Answer» E. | |
9. |
A particle is undergoing SHM with amplitude 10cm. The maximum speed it achieves is 1m/s. Find the time it takes to reach from the mean position to half the amplitude. |
A. | π/60 s |
B. | π/30 s |
C. | π/15 s |
D. | π/40 s |
Answer» B. π/30 s | |
10. |
A particle is initially at the centre and going towards the left. Let T be the time period of the SHM it is undergoing. What will be its position and velocity at time 3T/4, if it starts from the centre at t=0? |
A. | At right extreme, zero velocity |
B. | at centre, maximum speed towards left |
C. | at centre, maximum speed towards right |
D. | Mid-way between centre and -A |
Answer» B. at centre, maximum speed towards left | |
11. |
Which of the following variables has zero value at the extreme position in SHM? |
A. | Acceleration |
B. | Speed |
C. | Displacement |
D. | Angular frequency |
Answer» C. Displacement | |
12. |
The equivalent length of a simple pendulum which gives the same frequency as the compound pendulum is |
A. | h/ k2G +h2 |
B. | k2G +h2/h |
C. | h2/k2G +h2 |
D. | k2G +h2/h2 |
Answer» C. h2/k2G +h2 | |
13. |
The periodic time (tp) is given by |
A. | ω / 2 π |
B. | 2 π / ω |
C. | 2 π × ω |
D. | π/ω |
Answer» C. 2 π × ω | |
14. |
THE_FREQUENCY_OF_OSCILLATION_OF_A_TORSIONAL_PENDULUM_IS?$ |
A. | 2πk<sub>G</sub>/r √g/I |
B. | r/2πk<sub>G</sub>√g/I |
C. | 2πk<sub>G</sub>/r√I/g |
D. | r/2πk<sub>G</sub>√I/g |
Answer» C. 2‚âà√¨‚àö√ëk<sub>G</sub>/r‚Äö√Ñ√∂‚àö‚Ć‚àö‚àÇI/g | |
15. |
THE_CENTRE_OF_PERCUSSION_IS_BELOW_THE_CENTRE_OF_GRAVITY_OF_THE_BODY_AND_IS_AT_A_DISTANCE_EQUAL_TO?$ |
A. | h / k<sub>G</sub> |
B. | h.k<sub>G</sub> |
C. | h<sup>2</sup>/k<sub>G</sub> |
D. | k<sup>2</sup><sub>G</sub>/h |
Answer» E. | |
16. |
The equivalent length of a simple pendulum which gives the same frequency as the compound pendulum i? |
A. | h/ k<sup>2</sup><sub>G</sub> +h<sup>2</sup> |
B. | k<sup>2</sup><sub>G</sub> +h<sup>2</sup>/h |
C. | h<sup>2</sup>/k<sup>2</sup><sub>G</sub> +h<sup>2</sup> |
D. | k<sup>2</sup><sub>G</sub> +h<sup>2</sup>/h<sup>2</sup> |
Answer» C. h<sup>2</sup>/k<sup>2</sup><sub>G</sub> +h<sup>2</sup> | |
17. |
The frequency of oscillation of a compound pendulum is |
A. | 1/2π √g.h/k<sup>2</sup><sub>G</sub> +h<sup>2</sup> |
B. | 1/2π √k<sup>2</sup><sub>G</sub> +h<sup>2</sup>/g.h |
C. | 2π√g.h/k<sup>2</sup><sub>G</sub> +h<sup>2</sup> |
D. | 2π√k<sup>2</sup><sub>G</sub> +h<sup>2</sup>/g.h |
Answer» B. 1/2‚âà√¨‚àö√ë ‚Äö√Ñ√∂‚àö‚Ć‚àö‚àÇk<sup>2</sup><sub>G</sub> +h<sup>2</sup>/g.h | |
18. |
When a rigid body is suspended vertically and it oscillates with a small amplitude under the action of the force of gravity, the body is known as |
A. | simple pendulum |
B. | torsional pendulum |
C. | compound pendulum |
D. | second’s pendulum |
Answer» D. second‚Äö√Ñ√∂‚àö√ë‚àö¬•s pendulum | |
19. |
The frequency of oscillation for the simple pendulum is |
A. | 1/2π √L/g |
B. | 1/2π √g/L |
C. | 2π √L/g |
D. | 2π√g/L |
Answer» C. 2‚âà√¨‚àö√ë ‚Äö√Ñ√∂‚àö‚Ć‚àö‚àÇL/g | |
20. |
The maximum acceleration of a particle moving with simple harmonic motion is |
A. | ω |
B. | ω.r |
C. | ω<sup>2</sup>.r |
D. | ω<sup>2</sup>/r |
Answer» D. ‚âà√¨‚àö¬¢<sup>2</sup>/r | |
21. |
The velocity of a particle (v) moving with simple harmonic motion, at any instant is given by |
A. | ω √r<sup>2</sup> − x<sup>2</sup> |
B. | ω √x<sup>2</sup> − r<sup>2</sup> |
C. | ω<sup>2</sup> √r<sup>2</sup> − x<sup>2</sup> |
D. | ω<sup>2</sup>√x<sup>2</sup> − r<sup>2</sup> |
Answer» B. ‚âà√¨‚àö¬¢ ‚Äö√Ñ√∂‚àö‚Ć‚àö‚àÇx<sup>2</sup> ‚Äö√Ñ√∂‚àö‚Ć‚àö‚↠r<sup>2</sup> | |
22. |
The velocity of a particle moving with simple harmonic motion is . . . . at the mean position. |
A. | zero |
B. | minimum |
C. | maximum |
D. | none of the mentioned |
Answer» D. none of the mentioned | |
23. |
The periodic time (tp) is given by |
A. | ω / 2 π |
B. | 2 π / ω |
C. | 2 π × ω |
D. | π/ω |
Answer» C. 2 ‚âà√¨‚àö√ë ‚Äö√†√∂‚àö‚â• ‚âà√¨‚àö¬¢ | |