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This section includes 12 Mcqs, each offering curated multiple-choice questions to sharpen your Heat Transfer Operations knowledge and support exam preparation. Choose a topic below to get started.
1. |
If we are given F value and R value, which is the only one variable we cannot determine by this information? |
A. | Value of P |
B. | Temperature of inlet and outlet of shell |
C. | Temperature of inlet and outlet of tube |
D. | Temperature of inlet and outlet of shell and tube |
Answer» E. | |
2. |
What are the axes of the F-curve? |
A. | X Correction Factor, Y R |
B. | X Correction Factor, Y mean of P and R |
C. | Y Correction Factor, X R |
D. | Y Correction Factor, X P |
Answer» E. | |
3. |
In a shell and tube heat exchanger, in the inner side fluid enters at 15 and leaves at 65 . The shell has oil entering at 105 and leaving at 85 . What is the value of correction factor coefficients R and P? |
A. | R = 0.4, P = 0.55 |
B. | R = 0.3, P = 0.55 |
C. | R = 0.4, P = 0.66 |
D. | R = 0.3, P = 0.66 |
Answer» B. R = 0.3, P = 0.55 | |
4. |
Which one of the following are correct relation of R and P?
|
A. | R = ( frac{T_2-T_1}{t_2-t_1} ), P = ( frac{t_2-t_1}{T_2-T_2} ) |
B. | R = ( frac{T_2-T_1}{t_2- t_1} ), P = ( frac{t_2- t_1}{T_1- t_1} ) |
C. | R = ( frac{T_2-T_1}{t_2- t_1} ), P = ( frac{t_2- t_1}{T_2- T_1} ) |
D. | R = ( frac{T_1-T_2}{t_2- t_1} ), P = ( frac{t_2- t_1}{T_1- t_1} ) |
Answer» E. | |
5. |
In a shell and tube heat exchanger, in the inner side fluid enters at 15 and leaves at 65 . The shell has steam at 1atm. What is the value of corrected LMTD and correction factor? |
A. | 39 , F = 0 |
B. | 56.35 , F = 0 |
C. | 70 , F = 1 |
D. | 56.35 , F = 1 |
Answer» E. | |
6. |
The value of correction factor can be equal to 1 in most cases of operation. |
A. | True |
B. | False |
Answer» C. | |
7. |
What is the value of Correction Factor?
|
A. | n<a href="https://www.sanfoundry.com/wp-content/uploads/2019/10/heat-transfer-operations-interview-questions-answers-freshers-q6.png"><img alt="Find the value from the below F-curve chart where R = 2, P = 0.3" class="alignnone size-full wp-image-249742" height="319" sizes="(max-width: 604px) 100vw, 604px" src="https://www.sanfoundry.com/wp-content/uploads/2019/10/heat-transfer-operations-interview-questions-answers-freshers-q6.png" srcset="https://www.sanfoundry.com/wp-content/uploads/2019/10/heat-transfer-operations-interview-questions-answers-freshers-q6.png 604w, https://www.sanfoundry.com/wp-content/uploads/2019/10/heat-transfer-operations-interview-questions-answers-freshers-q6-300x158.png 300w" width="604"/></a> |
B. | 0.86 |
C. | 0.90 |
D. | 0.80 |
E. | 0.82 |
Answer» B. 0.86 | |
8. |
Why do we use LMTD Correction factor? |
A. | Incomplete Countercurrent flow |
B. | Leakage leading to heat loss |
C. | Counter current and Co-current at parts |
D. | Due to fouling |
Answer» D. Due to fouling | |
9. |
What should be the minimum value of LMTD Correction Factor F for steady state operation of the equipment? |
A. | <0.5 |
B. | <1 |
C. | 1 > F > 0.75 |
D. | 1 > F > 0.5 |
Answer» D. 1 > F > 0.5 | |
10. |
Which of the following has the Log mean temperature difference is used for corrected LMTD for a Shell and tube Heat Exchanger? |
A. | Counter-flow |
B. | Parallel Flow |
C. | Cross Flow |
D. | Split Flow |
Answer» B. Parallel Flow | |
11. |
What should be the minimum value of the Correction Factor to get multiplied to LMTD? |
A. | >1 |
B. | <2 |
C. | <1 |
D. | >2 |
Answer» D. >2 | |
12. |
When using TLM for a shell and tube heat exchanger, we cannot use the conventional formula for LMTD. |
A. | True |
B. | False |
Answer» B. False | |