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This section includes 13 Mcqs, each offering curated multiple-choice questions to sharpen your Network Theory knowledge and support exam preparation. Choose a topic below to get started.
1. |
The expression of N in a full series equalizer considering Z1 as capacitor and Z2 as inductor is? |
A. | 1+ (ω2 L12)/Ro2 |
B. | (ω2 L12)/Ro2 |
C. | 1+ Ro2/(ωL1)2 |
D. | Ro2/(ωL1)2 |
Answer» D. Ro2/(ωL1)2 | |
2. |
The expression of N in a full series equalizer considering Z1 as inductor and Z2 as capacitor is? |
A. | Ro2/(ωL1)2 |
B. | 1+ Ro2/(ωL1)2 |
C. | (ω2 L12)/Ro2 |
D. | 1+ (ω2 L12)/Ro2 |
Answer» E. | |
3. |
Determine the value of N in the series equalizer. |
A. | 1+ X12/Ro2 |
B. | X12/Ro2 |
C. | 1+ Ro2/X12 |
D. | Ro2/X12 |
Answer» B. X12/Ro2 | |
4. |
THE_EXPRESSION_OF_N_IN_A_FULL_SERIES_EQUALIZER_CONSIDERING_Z1_AS_INDUCTOR_AND_Z2_AS_CAPACITOR_IS??$ |
A. | R<sub>o</sub><sup>2</sup>/(ωL<sub>1</sub>)<sup>2</sup> |
B. | 1+ R<sub>o</sub><sup>2</sup>/(ωL<sub>1</sub>)<sup>2</sup> |
C. | (ω<sup>2</sup> L<sub>1</sub><sup>2</sup>)/R<sub>o</sub><sup>2</sup> |
D. | 1+ (ω<sup>2</sup> L<sub>1</sub><sup>2</sup>)/R<sub>o</sub><sup>2</sup> |
Answer» E. | |
5. |
The_expression_of_N_in_a_full_series_equalizer_considering_Z1_as_capacitor_and_Z2_as_inductor_is?$ |
A. | 1+ (ω<sup>2</sup> L<sub>1</sub><sup>2</sup>)/R<sub>o</sub><sup>2</sup> |
B. | (ω<sup>2</sup> L<sub>1</sub><sup>2</sup>)/R<sub>o</sub><sup>2</sup> |
C. | 1+ R<sub>o</sub><sup>2</sup>/(ωL<sub>1</sub>)<sup>2</sup> |
D. | R<sub>o</sub><sup>2</sup>/(ωL<sub>1</sub>)<sup>2</sup> |
Answer» D. R<sub>o</sub><sup>2</sup>/(‚âà√¨‚àö¬¢L<sub>1</sub>)<sup>2</sup> | |
6. |
Determine the value of N in the series equalizer? |
A. | 1+ X<sub>1</sub><sup>2</sup>/R<sub>o</sub><sup>2</sup> |
B. | X<sub>1</sub><sup>2</sup>/R<sub>o</sub><sup>2</sup> |
C. | 1+ R<sub>o</sub><sup>2</sup>/X<sub>1</sub><sup>2</sup> |
D. | R<sub>o</sub><sup>2</sup>/X<sub>1</sub><sup>2</sup> |
Answer» B. X<sub>1</sub><sup>2</sup>/R<sub>o</sub><sup>2</sup> | |
7. |
What is the power at the load of a series equalizer? |
A. | [ V<sub>max</sub><sup>2</sup>/(R<sub>o</sub><sup>2</sup>+X<sub>1</sub><sup>2</sup> )]R<sub>o</sub> |
B. | [ V<sub>max</sub><sup>2</sup>/(2(R<sub>o</sub><sup>2</sup>+X<sub>1</sub><sup>2</sup>))]R<sub>o</sub> |
C. | [ V<sub>max</sub><sup>2</sup>/(3(R<sub>o</sub><sup>2</sup>+X<sub>1</sub><sup>2</sup>))]R<sub>o</sub> |
D. | [ V<sub>max</sub><sup>2</sup>/(4(R<sub>o</sub><sup>2</sup>+X<sub>1</sub><sup>2</sup>))]R<sub>o</sub> |
Answer» E. | |
8. |
The expression of current flowing in a series equalizer is? |
A. | V<sub>max</sub>/‚àö((R<sub>o</sub>)<sup>2</sup>+(X<sub>1</sub>)<sup>2</sup>) |
B. | V<sub>max</sub>/‚àö((2R<sub>o</sub>)<sup>2</sup>+(X<sub>1</sub>)<sup>2</sup> ) |
C. | V<sub>max</sub>/‚àö((2R<sub>o</sub>)<sup>2</sup>+(2X<sub>1</sub>)<sup>2</sup> ) |
D. | V<sub>max</sub>/‚àö((R<sub>o</sub>)<sup>2</sup>+(2X<sub>1</sub>)<sup>2</sup> ) |
Answer» D. V<sub>max</sub>/‚Äö√Ñ√∂‚àö‚Ć‚àö‚àÇ((R<sub>o</sub>)<sup>2</sup>+(2X<sub>1</sub>)<sup>2</sup> ) | |
9. |
The expression of input power of a series equalizer is? |
A. | V<sub>max</sub><sup>2</sup>/R<sub>o</sub> |
B. | V<sub>max</sub><sup>2</sup>/2R<sub>o</sub> |
C. | V<sub>max</sub><sup>2</sup>/3R<sub>o</sub> |
D. | V<sub>max</sub><sup>2</sup>/4R<sub>o</sub> |
Answer» E. | |
10. |
The N is defined as? |
A. | output power/ input power |
B. | input power/ output power |
C. | output power at inductor/ input power |
D. | output power at capacitor/ input power |
Answer» C. output power at inductor/ input power | |
11. |
The input to output power ratio of the load (N) is the ratio of the________ to the __________ |
A. | Maximum power delivered to the load when the equalizer is not present, power delivered to the load when equalizer is present |
B. | Power delivered to the load when equalizer is present, maximum power delivered to the load when the equalizer is not present |
C. | Maximum power delivered to the load when the equalizer is present, power delivered to the load when equalizer is not present |
D. | Power delivered to the load when equalizer is not present, maximum power delivered to the load when the equalizer is present |
Answer» B. Power delivered to the load when equalizer is present, maximum power delivered to the load when the equalizer is not present | |
12. |
The value of N in terms of attenuation D is? |
A. | antilog(D) |
B. | antilog(D/10) |
C. | antilog(D/20) |
D. | antilog(D/40) |
Answer» C. antilog(D/20) | |
13. |
The value of attenuation D is equal to? |
A. | log<sub>10</sub> (N) |
B. | 10 log<sub>10</sub> (N) |
C. | 20 log<sub>10</sub> (N) |
D. | 40 log<sub>10</sub> (N) |
Answer» B. 10 log<sub>10</sub> (N) | |