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This section includes 5 Mcqs, each offering curated multiple-choice questions to sharpen your Digital Image Processing knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Which of the following helps to obtain the number of bits to be used to quantize each pixel. |
| A. | tGray-level slicing |
| B. | tContrast stretching |
| C. | tContouring |
| D. | tBit-plane slicing |
| Answer» E. | |
| 2. |
In bit-plane slicing if an image is represented by 8 bits and is composed of eight 1-bit plane, with plane 0 showing least significant bit and plane 7 showing most significant bit. Then, which plane(s) contain the majority of visually significant data. |
| A. | tPlane 4, 5, 6, 7 |
| B. | tPlane 0, 1, 2, 3 |
| C. | tPlane 0 |
| D. | tPlane 2, 3, 4, 5 |
| Answer» B. tPlane 0, 1, 2, 3 | |
| 3. |
Specific bit contribution in the image highlighting is the basic idea of __________ |
| A. | tContrast stretching |
| B. | tBit plane slicing |
| C. | tThresholding |
| D. | tGray-level slicing |
| Answer» C. tThresholding | |
| 4. |
A contrast stretching result been obtained by setting (r1, s1) = (rmin, 0) and (r2, s2) = (rmax, L 1), where, r and s are gray-values of image before and after processing respectively, L is the max gray value allowed and rmax and rmin are maximum and minimum gray-values in image respectively. What should we term the transformation function if r1 = r2 = m, some mean gray-value. |
| A. | tLinear function |
| B. | tThresholding function |
| C. | tIntermediate function |
| D. | tNone of the mentioned |
| Answer» C. tIntermediate function | |
| 5. |
When is the contrast stretching transformation a thresholding function, for r and s as gray-value of image before and after processing respectively? |
| A. | tr<sub>1</sub> = s<sub>1</sub> and r<sub>2</sub> = s<sub>2</sub> |
| B. | tr<sub>1</sub> = r<sub>2</sub>, s<sub>1</sub> = 0 and s<sub>2</sub> = L 1, L is the max gray value allowed |
| C. | tr<sub>1</sub> = 1 and r<sub>2</sub> = 0 |
| D. | tNone of the mentioned |
| Answer» C. tr<sub>1</sub> = 1 and r<sub>2</sub> = 0 | |