MCQOPTIONS
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MCQOPTIONS
This section includes 13 Mcqs, each offering curated multiple-choice questions to sharpen your Design Electrical Machines knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
What is the range of the average flux density used in the output equation? |
| A. | 0.30-0.55 weber per m2 |
| B. | 0.30-0.50 weber per m2 |
| C. | 0.35-0.45 weber per m2 |
| D. | 0.35-0.55 weber per m2 |
| Answer» E. | |
| 2. |
What factor does the output coefficient depend upon? |
| A. | specific magnetic loading |
| B. | specific electric loading |
| C. | specific electric loading or specific magnetic loading |
| D. | specific electric loading and specific magnetic loading |
| Answer» C. specific electric loading or specific magnetic loading | |
| 3. |
The smaller values are applicable for lower rating machines. |
| A. | true |
| B. | false |
| Answer» B. false | |
| 4. |
WHAT_FACTOR_DOES_THE_OUTPUT_COEFFICIENT_DEPEND_UPON??$ |
| A. | specific magnetic loading |
| B. | specific electric loading |
| C. | specific electric loading or specific magnetic loading |
| D. | specific electric loading and specific magnetic loading |
| Answer» C. specific electric loading or specific magnetic loading | |
| 5. |
What_is_the_range_of_the_average_flux_density_used_in_the_output_equation?$ |
| A. | 0.30-0.55 weber per m<sup>2</sup> |
| B. | 0.30-0.50 weber per m<sup>2</sup> |
| C. | 0.35-0.45 weber per m<sup>2</sup> |
| D. | 0.35-0.55 weber per m<sup>2</sup> |
| Answer» E. | |
| 6. |
What is the power factor of output watt of 90? |
| A. | 0.46 |
| B. | 0.51 |
| C. | 0.56 |
| D. | 0.62 |
| Answer» C. 0.56 | |
| 7. |
What is the efficiency for the output watt of 180? |
| A. | 0.38 |
| B. | 0.48 |
| C. | 0.57 |
| D. | 0.65 |
| Answer» D. 0.65 | |
| 8. |
The smaller values are applicable for lower rating machines? |
| A. | true |
| B. | false |
| Answer» B. false | |
| 9. |
What is the ratio of power factor of the 75 watt to 750 watt motor? |
| A. | 0.55 : 0.60 |
| B. | 0.50 : 0.60 |
| C. | 0.55 : 0.65 |
| D. | 0.50 : 0.65 |
| Answer» D. 0.50 : 0.65 | |
| 10. |
What is the ratio of the efficiency for 75 watt to 750 watt motor? |
| A. | 4:7 |
| B. | 5:7 |
| C. | 6:7 |
| D. | 3:7 |
| Answer» C. 6:7 | |
| 11. |
What is the formula of the kVA input if the rating of the machine is given in horse power? |
| A. | kVA input = horse power / 0.746 * efficiency * power factor |
| B. | kVA input = horse power * 0.746 * efficiency * power factor |
| C. | kVA input = horse power * 0.746 / efficiency * power factor |
| D. | kVA input = horse power * 0.746 * efficiency / power factor |
| Answer» D. kVA input = horse power * 0.746 * efficiency / power factor | |
| 12. |
What is the formula for the output coefficient of the output equation? |
| A. | output coefficient = 11 * winding space factor * specific magnetic loading / specific electric loading * 10<sup>-3</sup> |
| B. | output coefficient = 11 * winding space factor * specific magnetic loading * specific electric loading * 10<sup>-3</sup> |
| C. | output coefficient = 11 * winding space factor / specific magnetic loading * specific electric loading * 10<sup>-3</sup> |
| D. | output coefficient = 11 / winding space factor * specific magnetic loading * specific electric loading * 10<sup>-3</sup> |
| Answer» C. output coefficient = 11 * winding space factor / specific magnetic loading * specific electric loading * 10<sup>-3</sup> | |
| 13. |
What is the formula of the output equation of ac machines? |
| A. | kVA input Q = output coefficient * diameter2 * length * synchronous speed |
| B. | kVA input Q = output coefficient / diameter2 * length * synchronous speed |
| C. | kVA input Q = output coefficient * diameter2 / length * synchronous speed |
| D. | kVA input Q = output coefficient * diameter2 * length / synchronous speed |
| Answer» B. kVA input Q = output coefficient / diameter2 * length * synchronous speed | |