Explore topic-wise MCQs in Linear Integrated Circuit.

This section includes 9 Mcqs, each offering curated multiple-choice questions to sharpen your Linear Integrated Circuit knowledge and support exam preparation. Choose a topic below to get started.

1.

Calculate the value of reference current and input resistor for current mirror with IC=1.2 A & VCC=12v. Assume =50.

A. 1.248mA, 9k
B. 1.248mA, 9.6k
C. 1.248mA, 9.2k
D. 1.2mA, 9.6k
Answer» B. 1.248mA, 9.6k
Discussion
2.

When will be the mirror effect valid

A. 1
B. =1
C. <1
D. 1
Answer» B. =1
Discussion
3.

Constant current source in differential amplifier is also called as

A. Current Mirror
B. Current Source
C. Current Repeaters
D. All of the mentioned
Answer» B. Current Source
Discussion
4.

Define total current (IQ) equation in differential amplifier with constant current bias current

A. I<sub>Q</sub>=1/R<sub>3</sub> (VEE/R<sub>1</sub>+R<sub>2</sub>)
B. I<sub>Q</sub> =(VEE R<sub>2</sub>)/(R<sub>1</sub>+R<sub>2</sub>)
C. I<sub>Q</sub>=1/R<sub>3</sub> (VEE R<sub>2</sub>/R<sub>1</sub>+R<sub>2</sub>)
D. I<sub>Q</sub>)=R<sub>3</sub> (VEE/R<sub>1</sub>+R<sub>2</sub>)
Answer» D. I<sub>Q</sub>)=R<sub>3</sub> (VEE/R<sub>1</sub>+R<sub>2</sub>)
Discussion
5.

How to improve CMRR value

A. Increase common mode gain
B. Decrease common mode gain
C. Increase Differential mode gain
D. Decrease differential mode gain
Answer» C. Increase Differential mode gain
Discussion
6.

In differential amplifier the input are given as V1=30sin (50t)+10sin (25t) , V2=30sin (50t)-10 sin (25t), 0 =200,RE =1k and RC = 15k . Find the output voltages V01, V02 &amp; gm=4M -1

A. V<sub>01</sub>=-60[10 sin u2061 (25t) ]-6.637[30sin u2061 (50t) ], V<sub>02</sub>=60[10 sin u2061 (25t) ]-6.637[30sin u2061 (50t) ].
B. V<sub>01</sub>=-6.637[10 sin u2061 (25t) ]-60[30sin u2061 (50t) ], V<sub>02</sub>=6.637[10 sin u2061 (25t) ]-60[30sin u2061 (50t) ].
C. V<sub>01</sub>=-60[30 sin u2061 (50t) ]-6.637[10sin u2061 (25t) ], V<sub>02</sub>=60[30 sin u2061 (50t) ]-6.637[10sin u2061 (25t) ].
D. V<sub>01</sub>=-6.637[30 sin u2061 (50t) ]-60[10sin u2061 (25t) ], V<sub>02</sub>=6.637[30 sin u2061 (50t) ]-60[10sin u2061 (25t) ].
Answer» B. V<sub>01</sub>=-6.637[10 sin u2061 (25t) ]-60[30sin u2061 (50t) ], V<sub>02</sub>=6.637[10 sin u2061 (25t) ]-60[30sin u2061 (50t) ].
Discussion
7.

Find Common Mode Rejection Ration, given gm =16M -1, RE=25k

A. 58 db
B. 40 db
C. 63 db
D. 89 db
Answer» B. 40 db
Discussion
8.

How the differential mode gain is expressed using h parameter for a single ended output?

A. h<sub>fe</sub>RC/h<sub>ie</sub>
B. 1/2 (h<sub>fe</sub>RC)/h<sub>ie</sub>
C. 1/2 h<sub>fe</sub>RC
D. None of the mentioned
Answer» C. 1/2 h<sub>fe</sub>RC
Discussion
9.

How are the arbitrary signal represented, that are applied to the input of transistor? (Assume common mode signal and differential mode signal to be VCM &amp; VDM respectively).

A. Sum of V<sub>CM</sub> &amp; V<sub>DM</sub>
B. Difference of V<sub>CM</sub> &amp; V<sub>DM</sub>
C. Sum and Difference of V<sub>CM</sub> &amp; V<sub>DM</sub>
D. None of the mentioned
Answer» D. None of the mentioned
Discussion