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This section includes 6 Mcqs, each offering curated multiple-choice questions to sharpen your Network Theory knowledge and support exam preparation. Choose a topic below to get started.
1. |
According to Millman s Theorem, if there are n current sources with n internal conductances respectively, are in series, then the value of equivalent conductance is? |
A. | G =R<sub>1</sub>+R<sub>2</sub>+ R<sub>n</sub> |
B. | G =1/(1/R<sub>1</sub>+1/R<sub>2</sub>+ 1/R<sub>n</sub>) |
C. | G =1/((R<sub>1</sub>+R<sub>2</sub>+ R<sub>n</sub>)) |
D. | G =1/R<sub>1</sub>+1/R<sub>2</sub>+ 1/R<sub>n</sub> |
Answer» D. G =1/R<sub>1</sub>+1/R<sub>2</sub>+ 1/R<sub>n</sub> | |
2. |
According to Millman s Theorem, if there are n current sources with n internal conductances respectively, are in series, then the value of equivalent current source is? |
A. | I<sup> </sup>=((I<sub>1</sub>R<sub>1</sub>+I<sub>2</sub>R<sub>2</sub>+ .+I<sub>n</sub>R<sub>n</sub>))/(R<sub>1</sub>+R<sub>2</sub>+ R<sub>n</sub>) |
B. | I =I<sub>1</sub>R<sub>1</sub>+I<sub>2</sub>R<sub>2</sub>+ .+I<sub>n</sub>R<sub>n</sub> |
C. | I =((I<sub>1</sub>/R<sub>1</sub>+I<sub>2</sub>/R<sub>2</sub>+ .+I<sub>n</sub>/R<sub>n</sub>))/(R<sub>1</sub>+R<sub>2</sub>+ R<sub>n</sub>) |
D. | I =I<sub>1</sub>/R<sub>1</sub>+I<sub>2</sub>/R<sub>2</sub>+ .+I<sub>n</sub>/R<sub>n</sub> |
Answer» B. I =I<sub>1</sub>R<sub>1</sub>+I<sub>2</sub>R<sub>2</sub>+ .+I<sub>n</sub>R<sub>n</sub> | |
3. |
According to Millman s Theorem, if there are n current sources with n internal conductances respectively, are in series, then these sources are replaced by? |
A. | single voltage source V in parallel with G |
B. | single current source I in series with G |
C. | single current source I in parallel with G |
D. | single voltage source V in series with G |
Answer» D. single voltage source V in series with G | |
4. |
According to Millman s Theorem, if there are n voltage sources with n internal resistances respectively, are in parallel, then the value of equivalent resistance is? |
A. | R =G<sub>1</sub>+G<sub>2</sub>+ G<sub>n</sub> |
B. | R =1/G<sub>1</sub>+1/G<sub>2</sub>+ 1/G<sub>n</sub> |
C. | R =1/((G<sub>1</sub>+G<sub>2</sub>+ G<sub>n</sub>)) |
D. | R =1/(1/G<sub>1</sub>+1/G<sub>2</sub>+ 1/G<sub>n</sub>) |
Answer» D. R =1/(1/G<sub>1</sub>+1/G<sub>2</sub>+ 1/G<sub>n</sub>) | |
5. |
According to Millman s Theorem, if there are n voltage sources with n internal resistances respectively, are in parallel, then the value of equivalent voltage source is? |
A. | V<sup> </sup>=(V<sub>1</sub>G<sub>1</sub>+V<sub>2</sub>G<sub>2</sub>+ .+V<sub>n</sub>G<sub>n</sub>) |
B. | V<sup> </sup>=((V<sub>1</sub>G<sub>1</sub>+V<sub>2</sub>G<sub>2</sub>+ .+V<sub>n</sub>G<sub>n</sub>))/((1/G<sub>1</sub>+1/G<sub>2</sub>+ 1/G<sub>n</sub>)) |
C. | V<sup> </sup>=((V<sub>1</sub>G<sub>1</sub>+V<sub>2</sub>G<sub>2</sub>+ .+V<sub>n</sub>G<sub>n</sub>))/(G<sub>1</sub>+G<sub>2</sub>+ G<sub>n</sub>) |
D. | V<sup> </sup>=((V<sub>1</sub>/G<sub>1</sub>+V<sub>2</sub>/G<sub>2</sub>+ .+V<sub>n</sub>/G<sub>n</sub>))/( G<sub>1</sub>+G<sub>2</sub>+ G<sub>n</sub>) |
Answer» D. V<sup> </sup>=((V<sub>1</sub>/G<sub>1</sub>+V<sub>2</sub>/G<sub>2</sub>+ .+V<sub>n</sub>/G<sub>n</sub>))/( G<sub>1</sub>+G<sub>2</sub>+ G<sub>n</sub>) | |
6. |
According to Millman s Theorem, if there are n voltage sources with n internal resistances respectively, are in parallel, then these sources are replaced by? |
A. | single current source I in series with R |
B. | single voltage source V in series with R |
C. | single current source I in parallel to R |
D. | single voltage source V in parallel to R |
Answer» C. single current source I in parallel to R | |