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This section includes 28 Mcqs, each offering curated multiple-choice questions to sharpen your Machine Kinematics knowledge and support exam preparation. Choose a topic below to get started.
1. |
Klein’s construction is useful to determine |
A. | velocity of various parts |
B. | acceleration of various parts |
C. | displacement of various parts |
D. | angular acceleration of various parts |
Answer» C. displacement of various parts | |
2. |
Klien’s construction can be used when |
A. | crank has a uniform angular velocity |
B. | crank has non-uniform velocity |
C. | crank has uniform angular acceleration |
D. | crank has uniform angular velocity and angular acceleration |
Answer» B. crank has non-uniform velocity | |
3. |
The sense of Coriol’s component is such that it |
A. | leads the sliding velocity vector by 900 |
B. | lags the sliding velocity vector by 900 |
C. | is along the sliding velocity vector by 900 |
D. | leads the sliding velocity vector by 1800 |
Answer» B. lags the sliding velocity vector by 900 | |
4. |
Corioli’s component acts |
A. | perpendicular to sliding surfaces |
B. | along sliding surfaces |
C. | both of the mentioned |
D. | all of the mentioned |
Answer» B. along sliding surfaces | |
5. |
The number of dead centers in a crank driven slider crank mechanism are |
A. | 0 |
B. | 2 |
C. | 4 |
D. | 6 |
Answer» C. 4 | |
6. |
Klien’s construction can be used to determine acceleration of various parts when the crank is at |
A. | inner dead center |
B. | outer dead center |
C. | right angles to the link of the stroke |
D. | all of the mentioned |
Answer» E. | |
7. |
The velocity of a slider with reference to a fixed point about which a bar is rotating and slider sliding on the bar will be |
A. | parallel to bar |
B. | perpendicular to bar |
C. | both of the mentioned |
D. | none of the mentioned |
Answer» D. none of the mentioned | |
8. |
Klein’s construction gives a graphical construction for |
A. | slider-crank mechanism |
B. | velocity polygon |
C. | acceleration polygon |
D. | none of the mentioned |
Answer» D. none of the mentioned | |
9. |
Corioli’s component is encountered in |
A. | quick return mechanism of shaper |
B. | four bar chain mechanism |
C. | slider crank mechanism |
D. | all of the mentioned |
Answer» B. four bar chain mechanism | |
10. |
In a rotary engine the angular velocity of the cylinder center line is 25 rad/sec and the relative velocity of a point on the cylinder center line w.r.t. cylinder is 10 m/sec. Corioli’s acceleration will be |
A. | 500m/sec2 |
B. | 250m/sec2 |
C. | 1000m/sec2 |
D. | 2000m/sec2 |
Answer» B. 250m/sec2 | |
11. |
The magnitude of the Corioli’s component of acceleration of a slider moving at velocity V on a link rotating at angular speed ω is |
A. | Vω |
B. | 2Vω |
C. | Vω/2 |
D. | 2V/ω |
Answer» C. Vω/2 | |
12. |
In a shaper mechanism, the Corioli’s component of acceleration will |
A. | not exist |
B. | exist |
C. | depend on position of crank |
D. | none of the mentioned |
Answer» C. depend on position of crank | |
13. |
The direction of Corioli’s component of acceleration is the direction |
A. | of relative velocity vector for the two coincident points rotated by 900 in the direction of the angular velocity of the rotation of the link |
B. | along the centripetal acceleration |
C. | along tangential acceleration |
D. | along perpendicular to angular velocity |
Answer» B. along the centripetal acceleration | |
14. |
THE_VELOCITY_OF_A_SLIDER_WITH_REFERENCE_TO_A_FIXED_POINT_ABOUT_WHICH_A_BAR_IS_ROTATING_AND_SLIDER_SLIDING_ON_THE_BAR_WILL_BE?$ |
A. | parallel to bar |
B. | perpendicular to bar |
C. | both of the mentioned |
D. | none of the mentioned |
Answer» D. none of the mentioned | |
15. |
The number of dead centers in a crank driven slider crank mechanism are$ |
A. | 0 |
B. | 2 |
C. | 4 |
D. | 6 |
Answer» C. 4 | |
16. |
Klien’s_construction_can_be_used_to_determine_acceleration_of_various_parts_when_the_crank_is_at$# |
A. | inner dead center |
B. | outer dead center |
C. | right angles to the link of the stroke |
D. | all of the mentioned |
Answer» E. | |
17. |
Klein’s construction is useful to determine$ |
A. | velocity of various parts |
B. | acceleration of various parts |
C. | displacement of various parts |
D. | angular acceleration of various parts |
Answer» C. displacement of various parts | |
18. |
Klien’s construction can be used when$ |
A. | crank has a uniform angular velocity |
B. | crank has non-uniform velocity |
C. | crank has uniform angular acceleration |
D. | crank has uniform angular velocity and angular acceleration |
Answer» B. crank has non-uniform velocity | |
19. |
The sense of Coriol’s component is such that it$ |
A. | leads the sliding velocity vector by 90<sup>0</sup> |
B. | lags the sliding velocity vector by 90<sup>0</sup> |
C. | is along the sliding velocity vector by 90<sup>0</sup> |
D. | leads the sliding velocity vector by 180<sup>0</sup> |
Answer» B. lags the sliding velocity vector by 90<sup>0</sup> | |
20. |
Corioli’s_component_acts$ |
A. | perpendicular to sliding surfaces |
B. | along sliding surfaces |
C. | both of the mentioned |
D. | all of the mentioned |
Answer» B. along sliding surfaces | |
21. |
Klein’s construction gives a graphical construction fo?# |
A. | slider-crank mechanism |
B. | velocity polygon |
C. | acceleration polygon |
D. | none of the mentioned |
Answer» D. none of the mentioned | |
22. |
Corioli’s component is encountered in$ |
A. | quick return mechanism of shaper |
B. | four bar chain mechanism |
C. | slider crank mechanism |
D. | all of the mentioned |
Answer» B. four bar chain mechanism | |
23. |
In a rotary engine the angular velocity of the cylinder center line is 25 rad/sec and the relative velocity of a point on the cylinder center line w.r.t. cylinder is 10 m/sec. Corioli’s acceleration will be$ |
A. | 500m/sec<sup>2</sup> |
B. | 250m/sec<sup>2</sup> |
C. | 1000m/sec<sup>2</sup> |
D. | 2000m/sec<sup>2</sup> |
Answer» B. 250m/sec<sup>2</sup> | |
24. |
The magnitude of the Corioli’s component of acceleration of a slider moving at velocity V on a link rotating at angular speed ω is$ |
A. | Vω |
B. | 2Vω |
C. | Vω/2 |
D. | 2V/ω |
Answer» C. V‚âà√¨‚àö¬¢/2 | |
25. |
Tangential acceleration direction is |
A. | along the angular velocity |
B. | opposite to angular velocity |
C. | perpendicular to angular velocity |
D. | all of the mentioned |
Answer» E. | |
26. |
The magnitude of tangential acceleration is equal to |
A. | velocity<sup>2</sup> x crank radius |
B. | velocity<sup>2</sup>/ crank radius |
C. | (velocity/ crank radius)<sup>2</sup> |
D. | velocity x crank radius<sup>2</sup> |
Answer» C. (velocity/ crank radius)<sup>2</sup> | |
27. |
In a shaper mechanism, the Corioli’s component of acceleration will$ |
A. | not exist |
B. | exist |
C. | depend on position of crank |
D. | none of the mentioned |
Answer» C. depend on position of crank | |
28. |
The direction of Corioli’s component of acceleration is the direction |
A. | of relative velocity vector for the two coincident points rotated by 90<sup>0</sup> in the direction of the angular velocity of the rotation of the link |
B. | along the centripetal acceleration |
C. | along tangential acceleration |
D. | along perpendicular to angular velocity |
Answer» B. along the centripetal acceleration | |