MCQOPTIONS
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MCQOPTIONS
This section includes 13 Mcqs, each offering curated multiple-choice questions to sharpen your Machine Kinematics knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
THE_CORIOLIS_COMPONENT_OF_ACCELERATION_DEPENDS_UPON?$ |
| A. | velocity of slider |
| B. | angular velocity of the link |
| C. | all of the mentioned |
| D. | none of the mentioned |
| Answer» D. none of the mentioned | |
| 2. |
A slider moves at a velocity v on a link revolving at ωrad/s. The coriolis component of acceleration is$# |
| A. | ωv |
| B. | 2ωv |
| C. | ω<sup>2</sup>v |
| D. | 2ωv<sup>2</sup> |
| Answer» C. ‚âà√¨‚àö¬¢<sup>2</sup>v | |
| 3. |
A_body_in_motion_will_be_subjected_to_coriolis_acceleration_when_that_body_is$ |
| A. | in plane rotation with variable velocity |
| B. | in plane translation with variable velocity |
| C. | in plane motion which is a resultant of plane translation and rotation |
| D. | restrained to rotate while sliding over another body |
| Answer» E. | |
| 4. |
The sense of coriolis component 2ωv is same as that of the relative velocity vector v rotated at$ |
| A. | 45<sup>0</sup> in the direction of rotation of the link containing the path |
| B. | 45<sup>0</sup> in the direction opposite to the rotation of the link containing the path |
| C. | 90<sup>0</sup> in the direction of rotation of the link containing the path |
| D. | 180<sup>0</sup> in the direction opposite to the rotation of the link containing the path |
| Answer» D. 180<sup>0</sup> in the direction opposite to the rotation of the link containing the path | |
| 5. |
The coriolis component of acceleration leads the sliding velocity by |
| A. | 45<sup>0</sup> |
| B. | 90<sup>0</sup> |
| C. | 135<sup>0</sup> |
| D. | 180<sup>0</sup> |
| Answer» C. 135<sup>0</sup> | |
| 6. |
The coriolis component of acceleration is taken into account fo? |
| A. | slider crank mechanism |
| B. | four bar chain mechanism |
| C. | quick return motion mechanism |
| D. | all of the mentioned |
| Answer» D. all of the mentioned | |
| 7. |
The coriolis component of acceleration acts |
| A. | along the sliding surface |
| B. | perpendicular to the sliding surface |
| C. | at 45<sup>0</sup> to the sliding surface |
| D. | parallel to the sliding surface |
| Answer» C. at 45<sup>0</sup> to the sliding surface | |
| 8. |
The tangential component of acceleration of the slider with respect to the coincident point on the link is called coriolis component of acceleration. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 9. |
In a shaper mechanism, the coriolis component of acceleration does not exists. |
| A. | True |
| B. | False |
| Answer» C. | |
| 10. |
When a point at the end of a link moves with constant angular velocity, its acceleration will have |
| A. | radial component only |
| B. | tangential component only |
| C. | coriolis component only |
| D. | radial and tangential components both |
| Answer» B. tangential component only | |
| 11. |
When a point moves along a straight line, its acceleration will have |
| A. | radial component only |
| B. | tangential component only |
| C. | coriolis component only |
| D. | radial and tangential components both |
| Answer» C. coriolis component only | |
| 12. |
The centre of gravity of a coupler link in a four bar mechanism will experience |
| A. | no acceleration |
| B. | only linear acceleration |
| C. | only angular acceleration |
| D. | both linear and angular acceleration |
| Answer» E. | |
| 13. |
The acceleration of a particle at any instant has two components, radial component and tangential component. These two components will be |
| A. | parallel to each other |
| B. | perpendicular to each other |
| C. | inclined at 45<sup>0</sup> |
| D. | opposite to each other |
| Answer» C. inclined at 45<sup>0</sup> | |