MCQOPTIONS
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MCQOPTIONS
This section includes 18 Mcqs, each offering curated multiple-choice questions to sharpen your Network Theory knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The value of the current after taking the inverse transform of the current is? |
| A. | (4-2e5t)u(t) |
| B. | (4-2e-5t)u(t) |
| C. | (4+2e5t)u(t) |
| D. | (4-2e-5t)u(t) |
| Answer» E. | |
| 2. |
The current equation for the circuit shown below is? |
| A. | I=4/s-2/(s-5) |
| B. | I=4/s-2/(s+5) |
| C. | I=4/s+2/(s+5) |
| D. | I=4/s+2/(s-5) |
| Answer» D. I=4/s+2/(s-5) | |
| 3. |
Determine the voltage V after taking the inverse transform (12 + 60/s + 10/(s+5)). |
| A. | 12δ(t)-(60-10e-5t)u(t) |
| B. | 12δ(t)+(60+10e-5t)u(t) |
| C. | 12δ(t)-(60+10e-5t)u(t) |
| D. | 12δ(t)+(60-10e-5t)u(t) |
| Answer» C. 12δ(t)-(60+10e-5t)u(t) | |
| 4. |
The value of the voltage V after taking the partial fractions in the equation V/(2s+15)+(V-[(100/s)+30])/(3s+10)=0 is? |
| A. | 12 + 60/s + 10/(s+5) |
| B. | 12 – 60/s + 10/(s+5) |
| C. | 12 – 60/s – 10/(s+5) |
| D. | 12 + 60/s – 10/(s+5) |
| Answer» B. 12 – 60/s + 10/(s+5) | |
| 5. |
The value of the voltage V in the circuit shown below is? |
| A. | 40(s+7.5)/s(s+5) – 12(s+7.5)/(s-5) |
| B. | 40(s+7.5)/s(s+5) – 12(s+7.5)/(s+5) |
| C. | 40(s+7.5)/s(s+5) + 12(s+7.5)/(s-5) |
| D. | 40(s+7.5)/s(s+5) + 12(s+7.5)/(s+5) |
| Answer» E. | |
| 6. |
Consider the circuit shown below. On applying the Kirchhoff’s current law, the equation will be? |
| A. | V/(2s-15)+(V-[(100/s)+30])/(3s+10)=0 |
| B. | V/(2s-15)+(V-[(100/s)+30])/(3s-10)=0 |
| C. | V/(2s+15)+(V-[(100/s)+30])/(3s+10)=0 |
| D. | V/(2s+15)+(V-[(100/s)+30])/(3s-10)=0 |
| Answer» D. V/(2s+15)+(V-[(100/s)+30])/(3s-10)=0 | |
| 7. |
By taking the inverse transform of the current (V/R)/(s+1/RCe), the value of the current is? |
| A. | V/R et/Ce |
| B. | V/R et/RCe |
| C. | V/R e-t/RCe |
| D. | V/R e-t/Ce |
| E. | , the value of the current is?a) V/R et/Ceb) V/R et/RCec) V/R e-t/RCed) V/R e-t/Ce |
| Answer» D. V/R e-t/Ce | |
| 8. |
The current in the circuit shown below is? |
| A. | (V/R)/(s+1/Ce) |
| B. | (V/R)/(s+1/RCe) |
| C. | (V/R)/(s-1/RCe) |
| D. | (V/R)/(s-1/C |
| E. | (V/R)/(s+1/RCe)c) (V/R)/(s-1/RCe)d) (V/R)/(s-1/Ce) |
| Answer» C. (V/R)/(s-1/RCe) | |
| 9. |
The charge on capacitor C2 in the circuit shown below is? |
| A. | 0 |
| B. | 1 |
| C. | 2 |
| D. | 3 |
| Answer» B. 1 | |
| 10. |
For the circuit shown below, find the voltage across the capacitor C1 at the time the switch is closed. |
| A. | 0 |
| B. | V/4 |
| C. | V/2 |
| D. | V |
| Answer» E. | |
| 11. |
THE_CURRENT_EQUATION_FOR_THE_CIRCUIT_SHOWN_IN_QUESTION_5_IS??$ |
| A. | I=4/s-2/(s-5) |
| B. | I=4/s-2/(s+5) |
| C. | I=4/s+2/(s+5) |
| D. | I=4/s+2/(s-5) |
| Answer» D. I=4/s+2/(s-5) | |
| 12. |
The_value_of_the_current_after_taking_the_inverse_transform_of_the_current_in_the_question_5_is?$ |
| A. | (4-2e<sup>5t</sup> )u(t) |
| B. | (4-2e<sup>-5t</sup>)u(t) |
| C. | (4+2e<sup>5t</sup>)u(t) |
| D. | (4-2e<sup>-5t</sup>)u(t) |
| Answer» E. | |
| 13. |
Determine the voltage V after taking the inverse transform in the question 5? |
| A. | 12δ(t)-(60-10e<sup>-5t</sup>)u(t) |
| B. | 12δ(t)+(60+10e<sup>-5t</sup>)u(t) |
| C. | 12δ(t)-(60+10e<sup>-5t</sup>)u(t) |
| D. | 12δ(t)+(60-10e<sup>-5t</sup>)u(t) |
| Answer» C. 12‚âà√≠¬¨‚Ä¢(t)-(60+10e<sup>-5t</sup>)u(t) | |
| 14. |
The value of the voltage V after taking the partial fractions in the question 5 is? |
| A. | 12+ 60/s+10/(s+5) |
| B. | 12- 60/s+10/(s+5) |
| C. | 12- 60/s-10/(s+5) |
| D. | 12+ 60/s-10/(s+5) |
| Answer» B. 12- 60/s+10/(s+5) | |
| 15. |
The value of the voltage V in the circuit shown in question 5 is? |
| A. | 40(s+7.5)/s(s+5) -12(s+7.5)/(s-5) |
| B. | 40(s+7.5)/s(s+5) -12(s+7.5)/(s+5) |
| C. | 40(s+7.5)/s(s+5) +12(s+7.5)/(s-5) |
| D. | 40(s+7.5)/s(s+5) +12(s+7.5)/(s+5) |
| Answer» E. | |
| 16. |
By taking the inverse transform of the current in the question 3, the value of the current is? |
| A. | V/R e<sup>t/C<sub>e</sub></sup> |
| B. | V/R e<sup>t/RC<sub>e</sub></sup> |
| C. | V/R e<sup>-t/RC<sub>e</sub></sup> |
| D. | V/R e<sup>-t/C<sub>e</sub></sup> |
| Answer» D. V/R e<sup>-t/C<sub>e</sub></sup> | |
| 17. |
The current in the circuit shown in question 1 is? |
| A. | (V/R)/(s+1/C<sub>e</sub>) |
| B. | (V/R)/(s+1/RC<sub>e</sub>) |
| C. | (V/R)/(s-1/RC<sub>e</sub>) |
| D. | (V/R)/(s-1/C<sub>e</sub>) |
| Answer» C. (V/R)/(s-1/RC<sub>e</sub>) | |
| 18. |
The charge on capacitor C2 in the circuit shown in question 1 is? |
| A. | 0 |
| B. | 1 |
| C. | 2 |
| D. | 3 |
| Answer» B. 1 | |