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This section includes 15 Mcqs, each offering curated multiple-choice questions to sharpen your Cytogenetics knowledge and support exam preparation. Choose a topic below to get started.
1. |
You cross two heterozygous disc shaped squash. What will be the ratio obtained? |
A. | 1:2:1 |
B. | 3:1 |
C. | 9:3:3:1 |
D. | 9:6:1 |
Answer» E. | |
2. |
If you cross two sphere shaped squash, you always get a disc. |
A. | True |
B. | False |
Answer» C. | |
3. |
If you cross a true breeding long with a true breeding disc shaped squash, what will you get in the F1? |
A. | Disc |
B. | Sphere |
C. | Long |
D. | Disc and long in 3:1 |
Answer» B. Sphere | |
4. |
IF_YOU_CROSS_A_TRUE_BREEDING_LONG_WITH_A_TRUE_BREEDING_DISC_SHAPED_SQUASH,_WHAT_WILL_YOU_GET_IN_THE_F1??$ |
A. | Disc |
B. | Sphere |
C. | Long |
D. | Disc and long in 3:1 |
Answer» B. Sphere | |
5. |
You cross two heterozygous disc shaped squash. What will be the ratio obtained?$ |
A. | 1:2:1 |
B. | 3:1 |
C. | 9:3:3:1 |
D. | 9:6:1 |
Answer» E. | |
6. |
If you cross two sphere shaped squash, you always get a disc.$ |
A. | True |
B. | False |
Answer» C. | |
7. |
The cross between a true breeding sphere shaped and a long shaped squash gives 30 sphere squash in F2. What is the total number of expected progeny? |
A. | 30 |
B. | 40 |
C. | 50 |
D. | 60 |
Answer» C. 50 | |
8. |
Which one of the following summer squash would be true breeding? |
A. | Sphere |
B. | Disc |
C. | Long |
D. | Short |
Answer» D. Short | |
9. |
In summer squash if you cross different varieties of true breeding sphere shaped squash, you get a disk shaped progeny. What phenomenon is seen here? |
A. | Gene interaction |
B. | Epistasis |
C. | Multiple allele |
D. | Codominance |
Answer» B. Epistasis | |
10. |
If a true breeding rose combed chicken is crossed to walnut combed chicken, what are the only possibilities of the F1 progeny? |
A. | Walnut |
B. | Rose |
C. | Walnut or rose |
D. | Walnut or rose or pea |
Answer» D. Walnut or rose or pea | |
11. |
If you cross two walnuts, which of the following is impossible? |
A. | Progeny to be a walnut |
B. | Progeny to be a single |
C. | Progeny to be a homozygous Rose |
D. | Progeny to have a phenotype other than rose, single, pea or walnut |
Answer» E. | |
12. |
You cross a true breeding pea comb chicken with a single comb chicken. What will you observe in the F2 generation? |
A. | Ratio 1:2:1 |
B. | Ratio 3:1 |
C. | Ratio 9:3:3:1 |
D. | All pea combed |
Answer» E. | |
13. |
In case of comb shape of a chicken, which of the following when inbred will breed true? |
A. | Rose |
B. | Pea |
C. | Walnut |
D. | Single |
Answer» E. | |
14. |
Gene interaction always modifies the normal Mendalian ratio. |
A. | True |
B. | False |
Answer» C. | |
15. |
The difference in epistasis and gene interaction is ___________________ |
A. | Gene interaction involves two genes |
B. | Epistasis modifies the normal Mendelian ratio |
C. | Epistasis involves two genes |
D. | Gene interaction produces a novel phenotype |
Answer» E. | |