Explore topic-wise MCQs in Enzyme Technology.

This section includes 7 Mcqs, each offering curated multiple-choice questions to sharpen your Enzyme Technology knowledge and support exam preparation. Choose a topic below to get started.

1.

Loss of activity which may be restored by the removal of inhibitor is referred to as ___________

A. reversible inhibition
B. irreversible inhibition
C. competitive inhibition
D. mixed inhibition
Answer» B. irreversible inhibition
Discussion
2.

Inhibition of lactase by galactose is an example of which kind of inhibition?

A. Uncompetitive inhibition
B. Mixed inhibition
C. Competitive inhibition
D. Substrate inhibition
Answer» D. Substrate inhibition
Discussion
3.

The rate equation for _______________ inhibition is given by (V= frac{V_{max} [S]}{K_m (1+ frac{[P]}{K_p})+[S]} ).

A. substrate
B. non-competitive
C. product
D. competitive
Answer» D. competitive
Discussion
4.

The following rate equation is given by ___________ inhibition.
(V= frac{ left ( frac{V_{max}}{1+ frac{[I]}{K_i }} right ) [S]}{ left ( frac{K_m}{1+ frac{[I]}{K_i }} right )+[S]} )

A. mixed
B. competitive
C. uncompetitive
D. non-competitive
Answer» D. non-competitive
Discussion
5.

Mercury causes irreversible inhibition.

A. True
B. False
Answer» B. False
Discussion
6.

If I = Ki = Ki , then what will happen to Vmax and Km when inhibitor acts non-competitively?

A. Lowers to 0.5 V<sub>max</sub> and 0.5 K<sub>m</sub>
B. V<sub>max</sub> is unchanged and K<sub>m</sub> increases 2K<sub>m</sub>
C. Lowers to 0.5 V<sub>max</sub> and K<sub>m</sub> remains unchanged
D. Lowers to 0.67 V<sub>max</sub> and K<sub>m</sub> increases to 2K<sub>m</sub>
Answer» D. Lowers to 0.67 V<sub>max</sub> and K<sub>m</sub> increases to 2K<sub>m</sub>
Discussion
7.

What happens to Vmax and Km in case of uncompetitive inhibition when I = Ki ?

A. Lowers to 0.5 V<sub>max</sub> and 0.5 K<sub>m</sub>
B. V<sub>max</sub> is unchanged and K<sub>m</sub> increases 2K<sub>m</sub>
C. Lowers to 0.5 V<sub>max</sub> and K<sub>m</sub> remains unchanged
D. Lowers to 0.67 V<sub>max</sub> and K<sub>m</sub> increases to 2K<sub>m</sub>
Answer» B. V<sub>max</sub> is unchanged and K<sub>m</sub> increases 2K<sub>m</sub>
Discussion