Which of these is correct for mixed inhibition?

Vmax is unchanged and Km increases 2Km

Lowers to 0.5 Vmax and Km remains unchanged

Lowers to 0.67 Vmax and Km increases to 2Km

In competitive inhibition, what happens to Vmax and Km if [I] = Ki?

Lowers to 0.5 Vmax and Km remains unchanged

Vmax is unchanged and Km increases 2Km

Lowers to 0.5 Vmax and Km remains unchanged

Lowers to 0.67 Vmax and Km increases to 2Km

Explore topic-wise MCQs in Enzyme Technology.

This section includes 8 Mcqs, each offering curated multiple-choice questions to sharpen your Enzyme Technology knowledge and support exam preparation. Choose a topic below to get started.

1.	Which of these is correct for mixed inhibition?
A.	Lowers to 0.5 V<sub>max</sub> and 0.5 K<sub>m</sub>
B.	V<sub>max</sub> is unchanged and K<sub>m</sub> increases 2K<sub>m</sub>
C.	Lowers to 0.5 V<sub>max</sub> and K<sub>m</sub> remains unchanged
D.	Lowers to 0.67 V<sub>max</sub> and K<sub>m</sub> increases to 2K<sub>m</sub>
Answer» E.

Discussion

2.	In competitive inhibition, what happens to V_max and K_m if [I] = K_i?
A.	Lowers to 0.5 V<sub>max</sub> and 0.5 K<sub>m</sub>
B.	V<sub>max</sub> is unchanged and K<sub>m</sub> increases 2K<sub>m</sub>
C.	Lowers to 0.5 V<sub>max</sub> and K<sub>m</sub> remains unchanged
D.	Lowers to 0.67 V<sub>max</sub> and K<sub>m</sub> increases to 2K<sub>m</sub>
Answer» C. Lowers to 0.5 V<sub>max</sub> and K<sub>m</sub> remains unchanged

Discussion

3.	The __________ inhibition gives the following rate equation. (V= frac{V_{max} [S]}{K_m+[S](1+ frac{[S]}{K_s})} )
A.	Substrate
B.	Mixed
C.	Non-competitive
D.	Competitive
Answer» B. Mixed

Discussion

4.	______________ inhibition represent the following rate equation. (V= frac{ left ( frac{V_{max}}{1+ frac{[I]}{K_i}} right )[S]}{K_m+[S]} )
A.	Substrate inhibition
B.	Competitive inhibition
C.	Product inhibition
D.	Non-competitive inhibition
Answer» E.

Discussion

5.	Inhibition of invertase by sucrose falls into which category of inhibition?
A.	Substrate inhibition
B.	Non-competitive inhibition
C.	Product inhibition
D.	Competitive inhibition
Answer» B. Non-competitive inhibition

Discussion

6.	Uncompetitive inhibition is most noticeable at low substrate concentration and can be overcome at high substrate concentration.
A.	True
B.	False
Answer» C.

Discussion

7.	The following rate equation represents _____________ inhibition. (V= frac{V_{max} [S]}{K_m (1+ frac{I}{K_i})+[S]} )
A.	competitive
B.	mixed
C.	non-competitive
D.	uncompetitive
Answer» B. mixed

Discussion

8.	Substances which reduce the rate of enzyme catalyzed reactions are known as ____________
A.	substrates
B.	enzymes
C.	products
D.	inhibitors
Answer» E.

Discussion

Explore topic-wise MCQs in Enzyme Technology.

Which of these is correct for mixed inhibition?

In competitive inhibition, what happens to Vmax and Km if [I] = Ki?

The __________ inhibition gives the following rate equation. (V= frac{V_{max} [S]}{K_m+[S](1+ frac{[S]}{K_s})} )

______________ inhibition represent the following rate equation. (V= frac{ left ( frac{V_{max}}{1+ frac{[I]}{K_i}} right )[S]}{K_m+[S]} )

Inhibition of invertase by sucrose falls into which category of inhibition?

Uncompetitive inhibition is most noticeable at low substrate concentration and can be overcome at high substrate concentration.

The following rate equation represents _____________ inhibition. (V= frac{V_{max} [S]}{K_m (1+ frac{I}{K_i})+[S]} )

Substances which reduce the rate of enzyme catalyzed reactions are known as ____________

In competitive inhibition, what happens to V_max and K_m if [I] = K_i?

The __________ inhibition gives the following rate equation.
(V= frac{V_{max} [S]}{K_m+[S](1+ frac{[S]}{K_s})} )

______________ inhibition represent the following rate equation.
(V= frac{ left ( frac{V_{max}}{1+ frac{[I]}{K_i}} right )[S]}{K_m+[S]} )

The following rate equation represents _____________ inhibition.
(V= frac{V_{max} [S]}{K_m (1+ frac{I}{K_i})+[S]} )