Explore topic-wise MCQs in Chemical Engineering.

This section includes 5314 Mcqs, each offering curated multiple-choice questions to sharpen your Chemical Engineering knowledge and support exam preparation. Choose a topic below to get started.

1701.

Energy equation in terms of specific internal energy is\(\frac{\partial(\rho \hat{u})}{\partial t}+\nabla.(\rho\vec{V}\hat{u})=-\nabla.\dot{q_s} – p\nabla .\vec{V}-\tau:\nabla \vec{V}+\dot{q_v}\) Where,t → Timeρ → Density\(\hat{u}\) → Specific internal energy\(\vec{V}\) → Velocity vector\(\dot{q_s}\)→ Rate of heat transfer per unit areaτ → Shear stress\(\dot{q}_v\) → Rate of heat source or sink per unit volumeConvert this equations in terms of specific enthalpy \(\hat{h}\).

A. \(\frac{\partial(\rho \hat{h})}{\partial t}+\nabla .(\rho \vec{V}\hat{h})=-\nabla .\dot{q_s}+\frac{Dp}{Dt} -\tau:\nabla \vec{V}+\dot{q_v}\)
B. \(\frac{\partial(\rho \hat{h})}{\partial t}+\nabla .(\rho \vec{V}\hat{h})=-\nabla .\dot{q_s}-p\nabla .\vec{V}-\tau:\nabla \vec{V}+\dot{q_v}\)
C. \(\frac{\partial(\rho \hat{h})}{\partial t}+\nabla .(\rho \vec{V}\hat{h})=-\nabla .\dot{q_s}-p\nabla .\vec{V}+\nabla .(p\vec{V})-\tau:\nabla \vec{V}+\dot{q_v}\)
D. \(\frac{\partial(\rho \hat{h})}{\partial t}+\nabla .(\rho \vec{V}\hat{h})=-\nabla .\dot{q_s}+\vec{V}.\nabla p-\tau:\nabla \vec{V}+\dot{q_v}\)
Answer» B. \(\frac{\partial(\rho \hat{h})}{\partial t}+\nabla .(\rho \vec{V}\hat{h})=-\nabla .\dot{q_s}-p\nabla .\vec{V}-\tau:\nabla \vec{V}+\dot{q_v}\)
1702.

If \(\vec{f}\) is the body force of an infinitesimally small element (volume dx dy dz and density ρ) moving along with the flow (velocity \(\vec{V}\)), Which term is the work done by the body force?

A. \(\vec{f}.\vec{V}\)dx dy dz
B. \(\rho\vec{f}.\vec{V}\)
C. \(\rho\vec{f}.\vec{V}\)dx dy dz
D. \(\rho\vec{f}\)dx dy dz
Answer» D. \(\rho\vec{f}\)dx dy dz
1703.

The energy equation which is in terms of total energy can be changed to terms of internal energy using ___________

A. momentum equation
B. stress-strain relations
C. equations of state
D. continuity equation
Answer» B. stress-strain relations
1704.

The energy equation which is in terms of temperature can be changed to terms of internal energy using ___________

A. momentum equation
B. stress-strain relations
C. equations of state
D. continuity equation
Answer» D. continuity equation
1705.

If p and τ are the net pressure and net shear stress acting on an infinitesimally small element (volume dx dy dz) moving along with the flow (velocity \(\vec{V}\)), what is the net work done on the system?

A. \(\rho (\nabla .(p\vec{V} )+\nabla .(τ.\vec{V}))\)
B. \(((p\vec{V})+(\tau.\vec{V}))dx \,dy \,dz\)
C. \(\rho(\nabla.(p\vec{V})+\nabla.(\tau.\vec{V})) dx \,dy \,dz\)
D. \((\nabla .(p)+\nabla.(\tau))dx \,dy \,dz\)
Answer» D. \((\nabla .(p)+\nabla.(\tau))dx \,dy \,dz\)
1706.

Expressing \(\tau:\Delta \vec{V}\) in terms of flow variables, we get λφ+μψ. What are φ and ψ?

A. \(\phi=(\frac{\partial u}{\partial x}+\frac{\partial v}{\partial y}+\frac{\partial w}{\partial z})^2 \,and\, \psi=(\frac{\partial u}{\partial y}+\frac{\partial v}{\partial x})^2+(\frac{\partial v}{\partial z}+\frac{\partial w}{\partial y})^2+(\frac{\partial u}{\partial z}+\frac{\partial w}{\partial x})^2\)
B. \(\psi=(\frac{\partial u}{\partial x}+\frac{\partial v}{\partial y}+\frac{\partial w}{\partial z})^2 \,and\, \phi=(\frac{\partial u}{\partial y}+\frac{\partial v}{\partial x})^2+(\frac{\partial v}{\partial z}+\frac{\partial w}{\partial y})^2+(\frac{\partial u}{\partial z}+\frac{\partial w}{\partial x})^2\)
C. \(\psi=(\frac{\partial u}{\partial x} + \frac{\partial v}{\partial y} + \frac{\partial w}{\partial z})^2 \,and\, \phi=2(\frac{\partial u}{\partial x})^2 + 2(\frac{\partial v}{\partial y})^2 +2(\frac{\partial w}{\partial z})^2+(\frac{\partial u}{\partial y}+\frac{\partial v}{\partial x})^2 +\) \( (\frac{\partial v}{\partial z} + \frac{\partial w}{\partial y})^2 + (\frac{\partial u}{\partial z} + \frac{\partial w}{\partial x})^2\)
D. \(\phi=(\frac{\partial u}{\partial x}+\frac{\partial v}{\partial y}+\frac{\partial w}{\partial z})^2 \,and\, \psi=2(\frac{\partial u}{\partial x})^2+2(\frac{\partial v}{\partial y})^2+2(\frac{\partial w}{\partial z})^2+(\frac{\partial u}{\partial y}+\frac{\partial v}{\partial x})^2+\) \((\frac{\partial v}{\partial z}+\frac{\partial w}{\partial y})^2+(\frac{\partial u}{\partial z}+\frac{\partial w}{\partial x})^2\)
Answer» E.
1707.

While converting the energy equation from one form to another, which of the following happens?

A. Either the left-hand side or the right-hand side of the equation changes
B. Both the left-hand side and the right-hand side of the equation change
C. The right-hand side of the equation changes
D. The left-hand side of the equation changes
Answer» C. The right-hand side of the equation changes
1708.

The energy equation in terms of total energy is\(\frac{\partial(\rho e)}{\partial t}+\nabla.(\rho \vec{V}e)=-\nabla.\dot{q}_s-\nabla.(p\vec{V})+\nabla.(τ.\vec{V})+\vec{f_b}.\vec{V}+\dot{q}_v.\) Where,t → Timeρ → Densitye → Specific total energy\(\vec{V}\) → Velocity vector\(\dot{q}_s\) → Rate of heat transfer per unit area\(\vec{f_b}\) → Body force vectorτ → Shear stress\(\dot{q}_v\) → Rate of heat source or sink per unit volumeWhile converting this equation in terms of internal energy, which of these terms lose its explicit presence?

A. Pressure term
B. Shear stress term
C. Body force term
D. Heat transfer term
E. }{\partial t}+\nabla.(\rho \vec{V}e)=-\nabla.\dot{q}_s-\nabla.(p\vec{V})+\nabla.(τ.\vec{V})+\vec{f_b}.\vec{V}+\dot{q}_v.\) Where,t → Timeρ → Densitye → Specific total energy\(\vec{V}\) → Velocity vector\(\dot{q}_s\) → Rate of heat transfer per unit area\(\vec{f_b}\) → Body force vectorτ → Shear stress\(\dot{q}_v\) → Rate of heat source or sink per unit volumeWhile converting this equation in terms of internal energy, which of these terms lose its explicit presence?a) Pressure termb) Shear stress termc) Body force termd) Heat transfer term
Answer» D. Heat transfer term
1709.

The details of a skyline assembly matrix are implemented in a program called ____

A. Boolean program
B. Cholesky program
C. Truss program
D. Trussky program
Answer» E.
1710.

The second step in skyline approach is assembling the element stiffness values into _____

A. Row vector
B. Identity vector
C. Column vector
D. Determinant vector
Answer» D. Determinant vector
1711.

The first step of skyline assembly matrix involves evaluation of ____

A. Column height
B. Row height
C. Matrix height
D. Undefined
Answer» B. Row height
1712.

Formula for maximum span or half band width in banded approach is _____

A. me=[|i-j|+1]
B. \(\frac{y_2-y_1}{l_e}\)
C. q‘=lq
D. me=[2|i-j|+1]
Answer» E.
1713.

In Skyline matrix, the elements in a stiffness matrix can be placed in _______

A. Direct values
B. Determinant values
C. Load values
D. Vector form
Answer» E.
1714.

In banded matrix, elements are _____ placed in stiffness matrix.

A. Singular
B. Determinant values
C. Directly
D. Indirectly
Answer» D. Indirectly
1715.

Which of these was one of the methods for determining assembly of global stiffness matrix?

A. Galerkin approach
B. Skyline approach
C. Rayleigh method
D. Assembly method
Answer» C. Rayleigh method
1716.

Symmetry and sparsity of the global stiffness matrix can be approached by _____ methods.

A. One
B. Three
C. Two
D. Four
Answer» D. Four
1717.

Skyline matrix storage is in the form of ______

A. Banded matrix
B. Sparse matrix
C. Singular matrix
D. Identity matrix
Answer» C. Singular matrix
1718.

What is a banded matrix?

A. Sparse matrix
B. Rectangular matrix
C. Unit matrix
D. Square matrix
Answer» B. Rectangular matrix
1719.

Reaming and counter boring can be performed by______

A. centres
B. face plates and angle plates
C. special attachments
D. none of the mentioned
Answer» C. special attachments
1720.

Spinning can be done by_____

A. centres
B. face plates or angle plates
C. special attachments
D. none of the mentioned
Answer» B. face plates or angle plates
1721.

Milling can be performed by _____

A. centres
B. face plates or angel plates
C. chucks
D. special attachments
Answer» E.
1722.

For lathe operations, work piece can be hold _____

A. between centres
B. on mandrel
C. either between centres or on mandrel
D. none of the mentioned
Answer» D. none of the mentioned
1723.

The total number of bones in lower extremity is ___________

A. 62
B. 63
C. 61
D. 60
Answer» B. 63
1724.

Joint of femur with pelvic girdle is _______

A. Ball and socket
B. Pivot
C. Saddle
D. Hinge
Answer» B. Pivot
1725.

Thumb (great toe) of foot is called _______

A. Pollex
B. Hallux
C. Index
D. Coracoid
E. of foot is called _______a) Pollexb) Halluxc) Indexd) Coracoid
Answer» C. Index
1726.

How many bones does ankle has?

A. 8
B. 9
C. 6
D. 7
Answer» E.
1727.

Contact cuts should be ____ apart.

A.
B.
C.
D. λ
Answer» B. 3λ
1728.

Minimum diffusion space is __________

A.
B.
C.
D. λ
Answer» C. 4λ
1729.

What are the advantages of design rules?

A. durable
B. scalable
C. portable
D. all of the mentioned
Answer» E.
1730.

Which can bring about variations in threshold voltage?

A. oxide thickness
B. ion implantation
C. poly variations
D. all of the mentioned
Answer» E.
1731.

The minimum spacing between two n-well is _____ micro meter.

A. 4
B. 5
C. 8
D. 8.5
Answer» E.
1732.

Minimum n-well width should be ____________ micro meter.

A. 2
B. 3
C. 4
D. 6
Answer» C. 4
1733.

Hatching is compatible with __________

A. monochrome encoding
B. bicode encoding
C. tricode encoding
D. not compatible with any encoding
Answer» B. bicode encoding
1734.

Minimum feature size for thick oxide is?

A.
B.
C.
D. λ
Answer» C. 4λ
1735.

The oxide layer below the first metal layer is deposited using __________

A. diffusion method
B. chemical vapour deposition
C. solid deposition
D. scattering method
Answer» C. solid deposition
1736.

Which is a more complex process?

A. buried contact
B. butting contact
C. buried & butting contact
D. none of the mentioned
Answer» B. butting contact
1737.

Diffusion and polysilicon layers are connected together using __________

A. butting contact
B. buried contact
C. separate contact
D. cannot be connected
Answer» B. buried contact
1738.

By which technique can the existing pavement be reused in the sub-base as well as the base course?

A. Reclamation
B. Asphalt recycling
C. Cold recycling
D. Hot recycling
Answer» D. Hot recycling
1739.

Resilient modulus is the relevant strength parameter for granular sub-base.

A. True
B. False
Answer» B. False
1740.

Base course can prevent subgrade soil movement caused due to ______ in rigid pavement.

A. Shoving
B. Depression
C. Weathering
D. Slab pumping
Answer» E.
1741.

Sub-base layer with less proportion of ______ will help in serving as a better drainage layer.

A. Coarse aggregates
B. Fine aggregates
C. Cement
D. Crushed slag
Answer» C. Cement
1742.

In which country was the first macadam road built?

A. USA
B. Scotland
C. Netherlands
D. Russia
Answer» B. Scotland
1743.

Which of the below IRC codes gives the guidelines for wet mix macadam?

A. IRC 102
B. IRC SP 102
C. IRC SP 100
D. IRC 109
Answer» E.
1744.

What is the name of the layer laid in between concrete slab and sub-base course in a rigid pavement?

A. Differential layer
B. Differential membrane
C. Separation layer
D. Separation membrane
Answer» E.
1745.

Which of the below is not used as an unbound sub-base material?

A. Kankar
B. Gravel
C. Lime-fly ash
D. Crushed slag
Answer» D. Crushed slag
1746.

The method of boulder soling is still used and it is laid over the subgrade.

A. True
B. False
Answer» C.
1747.

What does WBM stand for?

A. Water Based Macadam
B. Water Bound Macadam
C. Wet Bituminous Macadam
D. Wet Bound Macadam
Answer» C. Wet Bituminous Macadam
1748.

If in an image there exist similar change in gray-level values in the image, which of the following shows a stronger response using second order derivative operator for sharpening?

A. A line
B. A step
C. A point
D. None of the mentioned
Answer» D. None of the mentioned
1749.

What kind of relation can be obtained between the response of first order derivative and second order derivative of an image having a transition into gray-level step from zero?

A. First order derivative has a stronger response than a second order
B. Second order derivative has a stronger response than a first order
C. Both first and second order derivative has the same response
D. None of the mentioned
Answer» D. None of the mentioned
1750.

What kind of relation can be obtained between first order derivative and second order derivative of an image on the response obtained by encountering an isolated noise point in the image?

A. First order derivative has a stronger response than a second order
B. Second order derivative has a stronger response than a first order
C. Both enhances the same and so the response is same for both first and second order derivative
D. None of the mentioned
Answer» C. Both enhances the same and so the response is same for both first and second order derivative