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This section includes 5314 Mcqs, each offering curated multiple-choice questions to sharpen your Chemical Engineering knowledge and support exam preparation. Choose a topic below to get started.
| 1701. |
Energy equation in terms of specific internal energy is\(\frac{\partial(\rho \hat{u})}{\partial t}+\nabla.(\rho\vec{V}\hat{u})=-\nabla.\dot{q_s} – p\nabla .\vec{V}-\tau:\nabla \vec{V}+\dot{q_v}\) Where,t → Timeρ → Density\(\hat{u}\) → Specific internal energy\(\vec{V}\) → Velocity vector\(\dot{q_s}\)→ Rate of heat transfer per unit areaτ → Shear stress\(\dot{q}_v\) → Rate of heat source or sink per unit volumeConvert this equations in terms of specific enthalpy \(\hat{h}\). |
| A. | \(\frac{\partial(\rho \hat{h})}{\partial t}+\nabla .(\rho \vec{V}\hat{h})=-\nabla .\dot{q_s}+\frac{Dp}{Dt} -\tau:\nabla \vec{V}+\dot{q_v}\) |
| B. | \(\frac{\partial(\rho \hat{h})}{\partial t}+\nabla .(\rho \vec{V}\hat{h})=-\nabla .\dot{q_s}-p\nabla .\vec{V}-\tau:\nabla \vec{V}+\dot{q_v}\) |
| C. | \(\frac{\partial(\rho \hat{h})}{\partial t}+\nabla .(\rho \vec{V}\hat{h})=-\nabla .\dot{q_s}-p\nabla .\vec{V}+\nabla .(p\vec{V})-\tau:\nabla \vec{V}+\dot{q_v}\) |
| D. | \(\frac{\partial(\rho \hat{h})}{\partial t}+\nabla .(\rho \vec{V}\hat{h})=-\nabla .\dot{q_s}+\vec{V}.\nabla p-\tau:\nabla \vec{V}+\dot{q_v}\) |
| Answer» B. \(\frac{\partial(\rho \hat{h})}{\partial t}+\nabla .(\rho \vec{V}\hat{h})=-\nabla .\dot{q_s}-p\nabla .\vec{V}-\tau:\nabla \vec{V}+\dot{q_v}\) | |
| 1702. |
If \(\vec{f}\) is the body force of an infinitesimally small element (volume dx dy dz and density ρ) moving along with the flow (velocity \(\vec{V}\)), Which term is the work done by the body force? |
| A. | \(\vec{f}.\vec{V}\)dx dy dz |
| B. | \(\rho\vec{f}.\vec{V}\) |
| C. | \(\rho\vec{f}.\vec{V}\)dx dy dz |
| D. | \(\rho\vec{f}\)dx dy dz |
| Answer» D. \(\rho\vec{f}\)dx dy dz | |
| 1703. |
The energy equation which is in terms of total energy can be changed to terms of internal energy using ___________ |
| A. | momentum equation |
| B. | stress-strain relations |
| C. | equations of state |
| D. | continuity equation |
| Answer» B. stress-strain relations | |
| 1704. |
The energy equation which is in terms of temperature can be changed to terms of internal energy using ___________ |
| A. | momentum equation |
| B. | stress-strain relations |
| C. | equations of state |
| D. | continuity equation |
| Answer» D. continuity equation | |
| 1705. |
If p and τ are the net pressure and net shear stress acting on an infinitesimally small element (volume dx dy dz) moving along with the flow (velocity \(\vec{V}\)), what is the net work done on the system? |
| A. | \(\rho (\nabla .(p\vec{V} )+\nabla .(τ.\vec{V}))\) |
| B. | \(((p\vec{V})+(\tau.\vec{V}))dx \,dy \,dz\) |
| C. | \(\rho(\nabla.(p\vec{V})+\nabla.(\tau.\vec{V})) dx \,dy \,dz\) |
| D. | \((\nabla .(p)+\nabla.(\tau))dx \,dy \,dz\) |
| Answer» D. \((\nabla .(p)+\nabla.(\tau))dx \,dy \,dz\) | |
| 1706. |
Expressing \(\tau:\Delta \vec{V}\) in terms of flow variables, we get λφ+μψ. What are φ and ψ? |
| A. | \(\phi=(\frac{\partial u}{\partial x}+\frac{\partial v}{\partial y}+\frac{\partial w}{\partial z})^2 \,and\, \psi=(\frac{\partial u}{\partial y}+\frac{\partial v}{\partial x})^2+(\frac{\partial v}{\partial z}+\frac{\partial w}{\partial y})^2+(\frac{\partial u}{\partial z}+\frac{\partial w}{\partial x})^2\) |
| B. | \(\psi=(\frac{\partial u}{\partial x}+\frac{\partial v}{\partial y}+\frac{\partial w}{\partial z})^2 \,and\, \phi=(\frac{\partial u}{\partial y}+\frac{\partial v}{\partial x})^2+(\frac{\partial v}{\partial z}+\frac{\partial w}{\partial y})^2+(\frac{\partial u}{\partial z}+\frac{\partial w}{\partial x})^2\) |
| C. | \(\psi=(\frac{\partial u}{\partial x} + \frac{\partial v}{\partial y} + \frac{\partial w}{\partial z})^2 \,and\, \phi=2(\frac{\partial u}{\partial x})^2 + 2(\frac{\partial v}{\partial y})^2 +2(\frac{\partial w}{\partial z})^2+(\frac{\partial u}{\partial y}+\frac{\partial v}{\partial x})^2 +\) \( (\frac{\partial v}{\partial z} + \frac{\partial w}{\partial y})^2 + (\frac{\partial u}{\partial z} + \frac{\partial w}{\partial x})^2\) |
| D. | \(\phi=(\frac{\partial u}{\partial x}+\frac{\partial v}{\partial y}+\frac{\partial w}{\partial z})^2 \,and\, \psi=2(\frac{\partial u}{\partial x})^2+2(\frac{\partial v}{\partial y})^2+2(\frac{\partial w}{\partial z})^2+(\frac{\partial u}{\partial y}+\frac{\partial v}{\partial x})^2+\) \((\frac{\partial v}{\partial z}+\frac{\partial w}{\partial y})^2+(\frac{\partial u}{\partial z}+\frac{\partial w}{\partial x})^2\) |
| Answer» E. | |
| 1707. |
While converting the energy equation from one form to another, which of the following happens? |
| A. | Either the left-hand side or the right-hand side of the equation changes |
| B. | Both the left-hand side and the right-hand side of the equation change |
| C. | The right-hand side of the equation changes |
| D. | The left-hand side of the equation changes |
| Answer» C. The right-hand side of the equation changes | |
| 1708. |
The energy equation in terms of total energy is\(\frac{\partial(\rho e)}{\partial t}+\nabla.(\rho \vec{V}e)=-\nabla.\dot{q}_s-\nabla.(p\vec{V})+\nabla.(τ.\vec{V})+\vec{f_b}.\vec{V}+\dot{q}_v.\) Where,t → Timeρ → Densitye → Specific total energy\(\vec{V}\) → Velocity vector\(\dot{q}_s\) → Rate of heat transfer per unit area\(\vec{f_b}\) → Body force vectorτ → Shear stress\(\dot{q}_v\) → Rate of heat source or sink per unit volumeWhile converting this equation in terms of internal energy, which of these terms lose its explicit presence? |
| A. | Pressure term |
| B. | Shear stress term |
| C. | Body force term |
| D. | Heat transfer term |
| E. | }{\partial t}+\nabla.(\rho \vec{V}e)=-\nabla.\dot{q}_s-\nabla.(p\vec{V})+\nabla.(τ.\vec{V})+\vec{f_b}.\vec{V}+\dot{q}_v.\) Where,t → Timeρ → Densitye → Specific total energy\(\vec{V}\) → Velocity vector\(\dot{q}_s\) → Rate of heat transfer per unit area\(\vec{f_b}\) → Body force vectorτ → Shear stress\(\dot{q}_v\) → Rate of heat source or sink per unit volumeWhile converting this equation in terms of internal energy, which of these terms lose its explicit presence?a) Pressure termb) Shear stress termc) Body force termd) Heat transfer term |
| Answer» D. Heat transfer term | |
| 1709. |
The details of a skyline assembly matrix are implemented in a program called ____ |
| A. | Boolean program |
| B. | Cholesky program |
| C. | Truss program |
| D. | Trussky program |
| Answer» E. | |
| 1710. |
The second step in skyline approach is assembling the element stiffness values into _____ |
| A. | Row vector |
| B. | Identity vector |
| C. | Column vector |
| D. | Determinant vector |
| Answer» D. Determinant vector | |
| 1711. |
The first step of skyline assembly matrix involves evaluation of ____ |
| A. | Column height |
| B. | Row height |
| C. | Matrix height |
| D. | Undefined |
| Answer» B. Row height | |
| 1712. |
Formula for maximum span or half band width in banded approach is _____ |
| A. | me=[|i-j|+1] |
| B. | \(\frac{y_2-y_1}{l_e}\) |
| C. | q‘=lq |
| D. | me=[2|i-j|+1] |
| Answer» E. | |
| 1713. |
In Skyline matrix, the elements in a stiffness matrix can be placed in _______ |
| A. | Direct values |
| B. | Determinant values |
| C. | Load values |
| D. | Vector form |
| Answer» E. | |
| 1714. |
In banded matrix, elements are _____ placed in stiffness matrix. |
| A. | Singular |
| B. | Determinant values |
| C. | Directly |
| D. | Indirectly |
| Answer» D. Indirectly | |
| 1715. |
Which of these was one of the methods for determining assembly of global stiffness matrix? |
| A. | Galerkin approach |
| B. | Skyline approach |
| C. | Rayleigh method |
| D. | Assembly method |
| Answer» C. Rayleigh method | |
| 1716. |
Symmetry and sparsity of the global stiffness matrix can be approached by _____ methods. |
| A. | One |
| B. | Three |
| C. | Two |
| D. | Four |
| Answer» D. Four | |
| 1717. |
Skyline matrix storage is in the form of ______ |
| A. | Banded matrix |
| B. | Sparse matrix |
| C. | Singular matrix |
| D. | Identity matrix |
| Answer» C. Singular matrix | |
| 1718. |
What is a banded matrix? |
| A. | Sparse matrix |
| B. | Rectangular matrix |
| C. | Unit matrix |
| D. | Square matrix |
| Answer» B. Rectangular matrix | |
| 1719. |
Reaming and counter boring can be performed by______ |
| A. | centres |
| B. | face plates and angle plates |
| C. | special attachments |
| D. | none of the mentioned |
| Answer» C. special attachments | |
| 1720. |
Spinning can be done by_____ |
| A. | centres |
| B. | face plates or angle plates |
| C. | special attachments |
| D. | none of the mentioned |
| Answer» B. face plates or angle plates | |
| 1721. |
Milling can be performed by _____ |
| A. | centres |
| B. | face plates or angel plates |
| C. | chucks |
| D. | special attachments |
| Answer» E. | |
| 1722. |
For lathe operations, work piece can be hold _____ |
| A. | between centres |
| B. | on mandrel |
| C. | either between centres or on mandrel |
| D. | none of the mentioned |
| Answer» D. none of the mentioned | |
| 1723. |
The total number of bones in lower extremity is ___________ |
| A. | 62 |
| B. | 63 |
| C. | 61 |
| D. | 60 |
| Answer» B. 63 | |
| 1724. |
Joint of femur with pelvic girdle is _______ |
| A. | Ball and socket |
| B. | Pivot |
| C. | Saddle |
| D. | Hinge |
| Answer» B. Pivot | |
| 1725. |
Thumb (great toe) of foot is called _______ |
| A. | Pollex |
| B. | Hallux |
| C. | Index |
| D. | Coracoid |
| E. | of foot is called _______a) Pollexb) Halluxc) Indexd) Coracoid |
| Answer» C. Index | |
| 1726. |
How many bones does ankle has? |
| A. | 8 |
| B. | 9 |
| C. | 6 |
| D. | 7 |
| Answer» E. | |
| 1727. |
Contact cuts should be ____ apart. |
| A. | 2λ |
| B. | 3λ |
| C. | 4λ |
| D. | λ |
| Answer» B. 3λ | |
| 1728. |
Minimum diffusion space is __________ |
| A. | 2λ |
| B. | 3λ |
| C. | 4λ |
| D. | λ |
| Answer» C. 4λ | |
| 1729. |
What are the advantages of design rules? |
| A. | durable |
| B. | scalable |
| C. | portable |
| D. | all of the mentioned |
| Answer» E. | |
| 1730. |
Which can bring about variations in threshold voltage? |
| A. | oxide thickness |
| B. | ion implantation |
| C. | poly variations |
| D. | all of the mentioned |
| Answer» E. | |
| 1731. |
The minimum spacing between two n-well is _____ micro meter. |
| A. | 4 |
| B. | 5 |
| C. | 8 |
| D. | 8.5 |
| Answer» E. | |
| 1732. |
Minimum n-well width should be ____________ micro meter. |
| A. | 2 |
| B. | 3 |
| C. | 4 |
| D. | 6 |
| Answer» C. 4 | |
| 1733. |
Hatching is compatible with __________ |
| A. | monochrome encoding |
| B. | bicode encoding |
| C. | tricode encoding |
| D. | not compatible with any encoding |
| Answer» B. bicode encoding | |
| 1734. |
Minimum feature size for thick oxide is? |
| A. | 2λ |
| B. | 3λ |
| C. | 4λ |
| D. | λ |
| Answer» C. 4λ | |
| 1735. |
The oxide layer below the first metal layer is deposited using __________ |
| A. | diffusion method |
| B. | chemical vapour deposition |
| C. | solid deposition |
| D. | scattering method |
| Answer» C. solid deposition | |
| 1736. |
Which is a more complex process? |
| A. | buried contact |
| B. | butting contact |
| C. | buried & butting contact |
| D. | none of the mentioned |
| Answer» B. butting contact | |
| 1737. |
Diffusion and polysilicon layers are connected together using __________ |
| A. | butting contact |
| B. | buried contact |
| C. | separate contact |
| D. | cannot be connected |
| Answer» B. buried contact | |
| 1738. |
By which technique can the existing pavement be reused in the sub-base as well as the base course? |
| A. | Reclamation |
| B. | Asphalt recycling |
| C. | Cold recycling |
| D. | Hot recycling |
| Answer» D. Hot recycling | |
| 1739. |
Resilient modulus is the relevant strength parameter for granular sub-base. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 1740. |
Base course can prevent subgrade soil movement caused due to ______ in rigid pavement. |
| A. | Shoving |
| B. | Depression |
| C. | Weathering |
| D. | Slab pumping |
| Answer» E. | |
| 1741. |
Sub-base layer with less proportion of ______ will help in serving as a better drainage layer. |
| A. | Coarse aggregates |
| B. | Fine aggregates |
| C. | Cement |
| D. | Crushed slag |
| Answer» C. Cement | |
| 1742. |
In which country was the first macadam road built? |
| A. | USA |
| B. | Scotland |
| C. | Netherlands |
| D. | Russia |
| Answer» B. Scotland | |
| 1743. |
Which of the below IRC codes gives the guidelines for wet mix macadam? |
| A. | IRC 102 |
| B. | IRC SP 102 |
| C. | IRC SP 100 |
| D. | IRC 109 |
| Answer» E. | |
| 1744. |
What is the name of the layer laid in between concrete slab and sub-base course in a rigid pavement? |
| A. | Differential layer |
| B. | Differential membrane |
| C. | Separation layer |
| D. | Separation membrane |
| Answer» E. | |
| 1745. |
Which of the below is not used as an unbound sub-base material? |
| A. | Kankar |
| B. | Gravel |
| C. | Lime-fly ash |
| D. | Crushed slag |
| Answer» D. Crushed slag | |
| 1746. |
The method of boulder soling is still used and it is laid over the subgrade. |
| A. | True |
| B. | False |
| Answer» C. | |
| 1747. |
What does WBM stand for? |
| A. | Water Based Macadam |
| B. | Water Bound Macadam |
| C. | Wet Bituminous Macadam |
| D. | Wet Bound Macadam |
| Answer» C. Wet Bituminous Macadam | |
| 1748. |
If in an image there exist similar change in gray-level values in the image, which of the following shows a stronger response using second order derivative operator for sharpening? |
| A. | A line |
| B. | A step |
| C. | A point |
| D. | None of the mentioned |
| Answer» D. None of the mentioned | |
| 1749. |
What kind of relation can be obtained between the response of first order derivative and second order derivative of an image having a transition into gray-level step from zero? |
| A. | First order derivative has a stronger response than a second order |
| B. | Second order derivative has a stronger response than a first order |
| C. | Both first and second order derivative has the same response |
| D. | None of the mentioned |
| Answer» D. None of the mentioned | |
| 1750. |
What kind of relation can be obtained between first order derivative and second order derivative of an image on the response obtained by encountering an isolated noise point in the image? |
| A. | First order derivative has a stronger response than a second order |
| B. | Second order derivative has a stronger response than a first order |
| C. | Both enhances the same and so the response is same for both first and second order derivative |
| D. | None of the mentioned |
| Answer» C. Both enhances the same and so the response is same for both first and second order derivative | |