MCQOPTIONS
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| 1. |
Energy equation in terms of specific internal energy is\(\frac{\partial(\rho \hat{u})}{\partial t}+\nabla.(\rho\vec{V}\hat{u})=-\nabla.\dot{q_s} – p\nabla .\vec{V}-\tau:\nabla \vec{V}+\dot{q_v}\) Where,t → Timeρ → Density\(\hat{u}\) → Specific internal energy\(\vec{V}\) → Velocity vector\(\dot{q_s}\)→ Rate of heat transfer per unit areaτ → Shear stress\(\dot{q}_v\) → Rate of heat source or sink per unit volumeConvert this equations in terms of specific enthalpy \(\hat{h}\). |
| A. | \(\frac{\partial(\rho \hat{h})}{\partial t}+\nabla .(\rho \vec{V}\hat{h})=-\nabla .\dot{q_s}+\frac{Dp}{Dt} -\tau:\nabla \vec{V}+\dot{q_v}\) |
| B. | \(\frac{\partial(\rho \hat{h})}{\partial t}+\nabla .(\rho \vec{V}\hat{h})=-\nabla .\dot{q_s}-p\nabla .\vec{V}-\tau:\nabla \vec{V}+\dot{q_v}\) |
| C. | \(\frac{\partial(\rho \hat{h})}{\partial t}+\nabla .(\rho \vec{V}\hat{h})=-\nabla .\dot{q_s}-p\nabla .\vec{V}+\nabla .(p\vec{V})-\tau:\nabla \vec{V}+\dot{q_v}\) |
| D. | \(\frac{\partial(\rho \hat{h})}{\partial t}+\nabla .(\rho \vec{V}\hat{h})=-\nabla .\dot{q_s}+\vec{V}.\nabla p-\tau:\nabla \vec{V}+\dot{q_v}\) |
| Answer» B. \(\frac{\partial(\rho \hat{h})}{\partial t}+\nabla .(\rho \vec{V}\hat{h})=-\nabla .\dot{q_s}-p\nabla .\vec{V}-\tau:\nabla \vec{V}+\dot{q_v}\) | |