MCQOPTIONS
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MCQOPTIONS
This section includes 26 Mcqs, each offering curated multiple-choice questions to sharpen your Boolean Algebra and Logic Simplification knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Find the 2's complement of –110110 2 . |
| A. | 110100 2 |
| B. | 101010 2 |
| C. | 001001 2 |
| D. | 001010 2 |
| Answer» E. | |
| 2. |
Subtract the following binary numbers. 0101 1000 1010 0011 1101 1110 –0010 0011 –0011 1000 –0101 0111 |
| A. | 0011Â Â 0100Â Â Â Â 0110Â Â 1010Â Â Â Â 1000Â Â 0110 |
| B. | 0011Â Â 0101Â Â Â Â 0110Â Â 1011Â Â Â Â 1000Â Â 0111 |
| C. | 0011Â Â 0101Â Â Â Â 0110Â Â 1010Â Â Â Â 1000Â Â 0111 |
| D. | 0011Â Â 0101Â Â Â Â 0110Â Â 1010Â Â Â Â 1000Â Â 0110 |
| Answer» C. 0011Â Â 0101Â Â Â Â 0110Â Â 1010Â Â Â Â 1000Â Â 0111 | |
| 3. |
The BCD addition of 9 10 and 7 10 will give initial code groups of 1001 + 0111. Addition of these groups generates a carry to the next higher position. The correct solution to this problem would be to: |
| A. | ignore the lowest order code group because 0000 is a valid code group and prefix the carry with three zeros |
| B. | add 0110 to both code groups to validate the carry from the lowest order code group |
| C. | disregard the carry and add 0110 to the lowest order code group |
| D. | add 0110 to the lowest order code group because a carry was generated and then prefix the carry with three zeros |
| Answer» E. | |
| 4. |
Subtract the following hexadecimal numbers. 47 34 FA –25 –1C –2F |
| A. | 22Â Â Â Â 18Â Â Â Â CB |
| B. | 22Â Â Â Â 17Â Â Â Â CB |
| C. | 22Â Â Â Â 19Â Â Â Â CB |
| D. | 22Â Â Â Â 18Â Â Â Â CC |
| Answer» B. 22Â Â Â Â 17Â Â Â Â CB | |
| 5. |
Add the following binary numbers. 0010 0110 0011 1011 0011 1100 +0101 0101 +0001 1110 +0001 1111 |
| A. | 0111 1011Â Â Â Â 0100Â Â 0001Â Â Â Â 0101Â Â 1011 |
| B. | 0111 1011Â Â Â Â 0101Â Â 1001Â Â Â Â 0101Â Â 1011 |
| C. | 0111 0111Â Â Â Â 0101Â Â 1001Â Â Â Â 0101Â Â 1011 |
| D. | 0111 0111Â Â Â Â 0100Â Â 0001Â Â Â Â 0101Â Â 1011 |
| Answer» C. 0111 0111Â Â Â Â 0101Â Â 1001Â Â Â Â 0101Â Â 1011 | |
| 6. |
Convert each of the decimal numbers to two's-complement form and perform the addition in binary. +13 –10 add –7 add +15 |
| A. | 0001Â Â 0100Â Â Â Â 0000Â Â 0101 |
| B. | 0000Â Â 0110Â Â Â Â 0001Â Â 1001 |
| C. | 0000Â Â 0110Â Â Â Â 0000Â Â 0101 |
| D. | 1111Â Â 0110Â Â Â Â 1111Â Â 0101 |
| Answer» D. 1111Â Â 0110Â Â Â Â 1111Â Â 0101 | |
| 7. |
How many BCD adders would be required to add the numbers 973 10 + 39 10 ? |
| A. | 3 |
| B. | 4 |
| C. | 5 |
| D. | 6 |
| Answer» B. 4 | |
| 8. |
When multiplying 13 × 11 in binary, what is the third partial product? |
| A. | 1011 |
| B. | 00000000 |
| C. | 100000 |
| D. | 100001 |
| Answer» C. 100000 | |
| 9. |
Divide the following binary numbers. |
| A. | 0000Â Â 0010Â Â Â Â 0000Â Â 0010Â Â Â Â 1000Â Â 1111 |
| B. | 0000Â Â 0010Â Â Â Â 0001Â Â 0010Â Â Â Â 0000Â Â 0100 |
| C. | 0000Â Â 0011Â Â Â Â 0000Â Â 0010Â Â Â Â 0000Â Â 0100 |
| D. | 0000Â Â 0010Â Â Â Â 0000Â Â 0010Â Â Â Â 0000Â Â 0100 |
| Answer» E. | |
| 10. |
Solve this binary problem: 01000110 ÷ 00001010 = |
| A. | 0111 |
| B. | 10011 |
| C. | 1001 |
| D. | 0011 |
| Answer» B. 10011 | |
| 11. |
Convert each of the signed decimal numbers to an 8-bit signed binary number (two's-complement). +7        –3        –12 |
| A. | 0000Â Â 0111Â Â Â Â 1111Â Â 1101Â Â Â Â 1111Â Â 0100 |
| B. | 1000Â Â 0111Â Â Â Â 0111Â Â 1101Â Â Â Â 0111Â Â 0100 |
| C. | 0000Â Â 0111Â Â Â Â 0000Â Â 0011Â Â Â Â 0000Â Â 1100 |
| D. | 0000Â Â 0111Â Â Â Â 1000Â Â 0011Â Â Â Â 1000Â Â 1100 |
| Answer» B. 1000Â Â 0111Â Â Â Â 0111Â Â 1101Â Â Â Â 0111Â Â 0100 | |
| 12. |
Perform the following hex subtraction: ACE 16 – 999 16 = |
| A. | 235 16 |
| B. | 135 16 |
| C. | 035 16 |
| D. | 335 16 |
| Answer» C. 035 16 | |
| 13. |
Solve this binary problem: |
| A. | 1001 |
| B. | 0110 |
| C. | 0111 |
| D. | 0101 |
| Answer» D. 0101 | |
| 14. |
Solve this binary problem: 01110010 – 01001000 = |
| A. | 00011010 |
| B. | 00101010 |
| C. | 01110010 |
| D. | 00111100 |
| Answer» C. 01110010 | |
| 15. |
Determine the two's-complement of each binary number. 00110Â Â Â Â Â Â Â Â 00011Â Â Â Â Â Â Â Â 11101 |
| A. | 11001Â Â Â Â 11100Â Â Â Â 00010 |
| B. | 00111Â Â Â Â 00010Â Â Â Â 00010 |
| C. | 00110Â Â Â Â 00011Â Â Â Â 11101 |
| D. | 11010Â Â Â Â 11101Â Â Â Â 00011 |
| Answer» E. | |
| 16. |
The truth table for a full adder is shown below. What are the values of X , Y , and Z ? |
| A. | X = 0, Y = 1, Z = 1 |
| B. | X = 1, Y = 1, Z = 1 |
| C. | X = 1, Y = 0, Z = 1 |
| D. | X = 0, Y = 0, Z = 1 |
| Answer» C. X = 1, Y = 0, Z = 1 | |
| 17. |
If [A] = 1011 1010, [B] = 0011 0110, and [C] = [A] • [B], what is [C 4..2] in decimal? |
| A. | 1 |
| B. | 2 |
| C. | 3 |
| D. | 4 |
| Answer» E. | |
| 18. |
Convert each of the following signed binary numbers (two's-complement) to a signed decimal number. 00000101Â Â Â Â Â Â Â Â 11111100Â Â Â Â Â Â Â Â 11111000 |
| A. | –5    +4    +8 |
| B. | +5    –4    –8 |
| C. | –5    +252    +248 |
| D. | +5    –252    –248 |
| Answer» C. –5    +252    +248 | |
| 19. |
The binary subtraction 0 – 0 = |
| A. | difference = 0 borrow = 0 |
| B. | difference = 1 borrow = 0 |
| C. | difference = 1 borrow = 1 |
| D. | difference = 0 borrow = 1 |
| Answer» B. difference = 1 borrow = 0 | |
| 20. |
Add the following hex numbers: 0110 16 + 10010 16 |
| A. | 10120 16 |
| B. | 10020 16 |
| C. | 11120 16 |
| D. | 00120 16 |
| Answer» B. 10020 16 | |
| 21. |
The decimal value for E 16 is: |
| A. | 12 10 |
| B. | 13 10 |
| C. | 14 10 |
| D. | 15 10 |
| Answer» D. 15 10 | |
| 22. |
Add the following hexadecimal numbers. 3C 14 3B +25 +28 +DC |
| A. | 60Â Â Â Â 3CÂ Â Â Â 116 |
| B. | 62Â Â Â Â 3CÂ Â Â Â 118 |
| C. | 61Â Â Â Â 3CÂ Â Â Â 117 |
| D. | 61Â Â Â Â 3DÂ Â Â Â 117 |
| Answer» D. 61Â Â Â Â 3DÂ Â Â Â 117 | |
| 23. |
Add the following BCD numbers. 0110 0111 1001 0101 1000 1000 |
| A. | 0000Â Â 1011Â Â Â Â 0000Â Â 1111Â Â Â Â 0001Â Â 0001 |
| B. | 0001Â Â 0001Â Â Â Â 0001Â Â 0101Â Â Â Â 0001Â Â 0001 |
| C. | 0000Â Â 1011Â Â Â Â 0000Â Â 1111Â Â Â Â 0001Â Â 0111 |
| D. | 0001Â Â 0001Â Â Â Â 0001Â Â 0101Â Â Â Â 0001Â Â 0111 |
| Answer» E. | |
| 24. |
Multiply the following binary numbers. 1010 1011 1001 ×0011 ×0111 ×1010 |
| A. | 0001Â Â 1110Â Â Â Â 0100Â Â 1101Â Â Â Â 0101Â Â 1011 |
| B. | 0001Â Â 1110Â Â Â Â 0100Â Â 1100Â Â Â Â 0101Â Â 1010 |
| C. | 0001Â Â 1110Â Â Â Â 0100Â Â 1101Â Â Â Â 0101Â Â 1010 |
| D. | 0001Â Â 1101Â Â Â Â 0100Â Â 1101Â Â Â Â 0101Â Â 1010 |
| Answer» D. 0001Â Â 1101Â Â Â Â 0100Â Â 1101Â Â Â Â 0101Â Â 1010 | |
| 25. |
Solving –11 + (–2) will yield which two's-complement answer? |
| A. | 1110 1101 |
| B. | 1111 1001 |
| C. | 1111 0011 |
| D. | 1110 1001 |
| Answer» D. 1110 1001 | |
| 26. |
Perform subtraction on each of the following binary numbers by taking the two's-complement of the number being subtracted and then adding it to the first number. 01001Â Â Â Â Â Â Â Â 01100 00011Â Â Â Â Â Â Â Â 00111 |
| A. | 01100Â Â Â Â 10011 |
| B. | 00110Â Â Â Â 00101 |
| C. | 10110Â Â Â Â 10101 |
| D. | 00111Â Â Â Â 00100 |
| Answer» C. 10110Â Â Â Â 10101 | |