MCQOPTIONS
Home
About Us
Contact Us
Bookmark
Saved Bookmarks
Testing Subject
General Aptitude
Logical and Verbal Reasoning
English Skills Ability
Technical Programming
Current Affairs
General Knowledge
Finance & Accounting
GATE (Mechanical Engineering)
Chemical Engineering
→
Boolean Algebra and Logic Simplification
→
Boolean Algebra and Logic Simplification in Boolean Algebra and Logic Simplification
→
Solve this binary problem:
An error occurred while fetching the topics. Please try again later.
1.
Solve this binary problem:
A.
1001
B.
0110
C.
0111
D.
0101
Answer» D. 0101
Show Answer
Discussion
No Comment Found
Post Comment
Related MCQs
Find the 2's complement of –110110 2 .
Subtract the following binary numbers. 0101 1000 1010 0011 1101 1110 –0010 0011 –0011 1000 –0101 0111
The BCD addition of 9 10 and 7 10 will give initial code groups of 1001 + 0111. Addition of these groups generates a carry to the next higher position. The correct solution to this problem would be to:
Subtract the following hexadecimal numbers. 47 34 FA –25 –1C –2F
Add the following binary numbers. 0010 0110 0011 1011 0011 1100 +0101 0101 +0001 1110 +0001 1111
Convert each of the decimal numbers to two's-complement form and perform the addition in binary. +13 –10 add –7 add +15
How many BCD adders would be required to add the numbers 973 10 + 39 10 ?
When multiplying 13 × 11 in binary, what is the third partial product?
Divide the following binary numbers.
Solve this binary problem: 01000110 ÷ 00001010 =
Reply to Comment
×
Name
*
Email
*
Comment
*
Submit Reply
Your experience on this site will be improved by allowing cookies. Read
Cookie Policy
Reject
Allow cookies
