MCQOPTIONS
Saved Bookmarks
MCQOPTIONS
This section includes 10 Mcqs, each offering curated multiple-choice questions to sharpen your Computational Fluid Dynamics knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
To overcome the disadvantage caused by the information from the wrong side of cells ____________ is used in the vertex-based method. |
| A. | upwind biased scheme |
| B. | weighted average |
| C. | downwind biased scheme |
| D. | central scheme |
| Answer» B. weighted average | |
| 2. |
The flow variable at the vertex node is calculated using the weighted average of the values at the cells sharing it. What is the weight used here? |
| A. | Inverse of the distance of the vertex from the cell centroid |
| B. | Distance of the vertex from the cell |
| C. | Centroids of the cells |
| D. | Mass of the cells |
| Answer» E. | |
| 3. |
In the vertex-based stencil, the flow variable at the face centroid is computed as ___________ |
| A. | the mean of the values at the vertices defining the surface |
| B. | the mean of the values at the cell centres |
| C. | the mean of the values at the vertices of the cells |
| D. | the mean of the values at the centroids of the neighbouring faces |
| Answer» B. the mean of the values at the cell centres | |
| 4. |
The face-centred stencil is second-order _________ |
| A. | always |
| B. | only when the centroid of the face and the line connecting the two cells meet |
| C. | only when the centroid of the face and the line connecting the two cells do not meet |
| D. | never |
| Answer» C. only when the centroid of the face and the line connecting the two cells do not meet | |
| 5. |
The value of the flow variable at face centre ( f) in terms of the flow variable at the owner cell s centre ( C) and the neighbouring cell s centre ( f) as given by the face-based stencil is ________
|
| A. | <sub>f</sub>=g<sub>C</sub> <sub>C</sub>+g<sub>C</sub> <sub>f</sub> |
| B. | <sub>f</sub>=g<sub>C</sub> <sub>C</sub>+g<sub>f</sub> <sub>f</sub> |
| C. | <sub>f</sub>=g<sub>C</sub> <sub>C</sub>+(1-g<sub>C</sub>) <sub>f</sub> |
| D. | <sub>f</sub>=g<sub>C</sub> <sub>C</sub>+(1+g<sub>C</sub>) <sub>f</sub> |
| Answer» D. <sub>f</sub>=g<sub>C</sub> <sub>C</sub>+(1+g<sub>C</sub>) <sub>f</sub> | |
| 6. |
It is easy to construct _________ in the face-based computation. |
| A. | Grids |
| B. | Stencil |
| C. | Global matrix |
| D. | Jacobian matrices |
| Answer» E. | |
| 7. |
The face-based stencil used for computing f in the Green-Gauss Gradient formula is ________ |
| A. | more accurate and needs a large stencil |
| B. | less accurate and needs a large stencil |
| C. | more accurate and needs a compact stencil |
| D. | less accurate and needs a compact stencil |
| Answer» E. | |
| 8. |
The gradient at the face of an element is obtained using ________ |
| A. | Linear interpolation |
| B. | Geometric values |
| C. | Green-Gauss theorem |
| D. | Weighted average |
| Answer» D. Weighted average | |
| 9. |
What is the final form of the Green-Gauss gradient method for finding the gradient of over element C? |
| A. | <sub>C</sub>= <sub>f~nb(c)</sub> <sub>f</sub> ( vec{S_f} ) |
| B. | <sub>C</sub>=1/V<sub>C</sub> <sub>f~nb(c)</sub> <sub>f</sub> ( vec{S_f} ) |
| C. | <sub>C</sub>=1/V<sub>C</sub> <sub>f~nb(c)</sub> <sub>f</sub> |
| D. | <sub>C</sub>=1/V<sub>C</sub> <sub>f~nb(c)</sub>a<sub>f</sub> <sub>f</sub> |
| Answer» C. <sub>C</sub>=1/V<sub>C</sub> <sub>f~nb(c)</sub> <sub>f</sub> | |
| 10. |
To get the gradient of the flow variable using the Green-Gauss Theorem, which of these theorems is used? |
| A. | Mean value theorem |
| B. | Stolarsky mean |
| C. | Racetrack principle |
| D. | Newmark-beta method |
| Answer» B. Stolarsky mean | |