MCQOPTIONS
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MCQOPTIONS
This section includes 10 Mcqs, each offering curated multiple-choice questions to sharpen your Electronic Devices Circuits knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Determine the voltage gain for the given circuit known that R1 = R3 = 10kΩ abd R2 = R4 = 100kΩ. |
| A. | 1 |
| B. | 10 |
| C. | 100 |
| D. | 1000 |
| Answer» C. 100 | |
| 2. |
For the difference amplifier shown below, let all the resistors be 10kΩ ± x%. The expression for the worst-case common-mode gain is |
| A. | x / 50 |
| B. | x / 100 |
| C. | 2x / (100 – x) |
| D. | 2x / (100 + x) |
| Answer» E. | |
| 3. |
For the circuit given below determine the input common mode resistance. |
| A. | (R1 + R3) || (R2) || + (R4) |
| B. | (R1 + R4) || (R2 + R3) |
| C. | (R1 + R2) || (R3 + R4) |
| D. | (R1 + R3) || (R2 + R4) |
| Answer» D. (R1 + R3) || (R2 + R4) | |
| 4. |
For the difference amplifier as shown in the figure show that if each resistor has a tolerance of ±100 ε % (i.e., for, say, a 5% resistor, ε = 0.05) then the worst-case CMRR is given approximately by (given K = R2/R1 = R4/R3) |
| A. | 20 log [K+1/4ε]. |
| B. | 20 log [K+1/2ε]. |
| C. | 20 log [K+1/ε]. |
| D. | 20 log [2K+2/ε]. |
| Answer» B. 20 log [K+1/2ε]. | |
| 5. |
If for an amplifier v1 and v2 are the input signals, vc and vd represent the common mode and differential signals respectively, then the expression for CMRR (Common Mode Rejection Ratio) isa) 20 log (|Ad| / |Ac|)b) -10 log (|Ac| / |Ad |
| A. | 20 log (|Ad| / |Ac|) |
| B. | -10 log (|Ac| / |Ad|)2 |
| C. | 20 log (v2 – v1 / 0.5(v2 + v1)) |
| D. | All of the mentioned |
| Answer» E. | |
| 6. |
If for an amplifier the common mode input signal is vc, the differential signal id vd and Ac and Ad represent common mode gain and differential gain respectively, then the output voltage v0 is given by |
| A. | v0 = Ad vd – Ac vc |
| B. | v0 = – Ad vd + Ac vc |
| C. | v0 = Ad vd + Ac vc |
| D. | v0 = – Ad vd – Ac vc |
| Answer» D. v0 = – Ad vd – Ac vc | |
| 7. |
The problem with the single operational difference amplifier is its |
| A. | High input resistance |
| B. | Low input resistance |
| C. | Low output resistance |
| D. | None of the mentioned |
| Answer» C. Low output resistance | |
| 8. |
If for an amplifier v1 and v2 are the input signals, vc and vd represent the common mode and differential signals respectively, then the expression for CMRR (Common Mode Rejection Ratio) is |
| A. | 20 log (|A<sub>d</sub>| / |A<sub>c</sub>|) |
| B. | -10 log (|A<sub>c</sub>| / |Ad|)<sup>2</sup> |
| C. | 20 log (v<sub>2</sub> – v<sub>1</sub> / 0.5(v<sub>2</sub> + v<sub>1</sub>)) |
| D. | All of the mentioned |
| Answer» E. | |
| 9. |
If for an amplifier the common mode input signal is vc, the differential signal id vd and Ac and Ad represent common mode gain and differential gain respectively, then the output voltage v0 is given by |
| A. | v<sub>0</sub> = A<sub>d</sub> v<sub>d</sub> – A<sub>c</sub> v<sub>c</sub> |
| B. | v<sub>0</sub> = – A<sub>d</sub> v<sub>d</sub> + A<sub>c</sub> v<sub>c</sub> |
| C. | v<sub>0</sub> = A<sub>d</sub> v<sub>d</sub> + A<sub>c</sub> v<sub>c</sub> |
| D. | v<sub>0</sub> = – A<sub>d</sub> v<sub>d</sub> – A<sub>c</sub> v<sub>c</sub> |
| Answer» D. v<sub>0</sub> = ‚Äö√Ñ√∂‚àö√ë‚àö¬® A<sub>d</sub> v<sub>d</sub> ‚Äö√Ñ√∂‚àö√ë‚àö¬® A<sub>c</sub> v<sub>c</sub> | |
| 10. |
For the difference amplifier which of the following is true? |
| A. | It responds to the difference between the two signals and rejects the signal that are common to both the signal |
| B. | It responds to the signal that are common to the two inputs only |
| C. | It has a low value of input resistance |
| D. | The efficacy of the amplifier is measured by the degree of its differential signal to the preference of the common mode signal |
| Answer» B. It responds to the signal that are common to the two inputs only | |