MCQOPTIONS
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MCQOPTIONS
This section includes 15 Mcqs, each offering curated multiple-choice questions to sharpen your Design Electrical Machines knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
What is the formula for the length of the stator slots? |
| A. | length of the stator slots = 2 * perimeter of one magnet |
| B. | length of the stator slots = 1/2 * perimeter of one magnet |
| C. | length of the stator slots = 1/3 * perimeter of one magnet |
| D. | length of the stator slots = 3 * perimeter of one magnet |
| Answer» C. length of the stator slots = 1/3 * perimeter of one magnet | |
| 2. |
The radial thickness of the joke is directly proportional to the length of the stator slots. |
| A. | true |
| B. | false |
| Answer» C. | |
| 3. |
The radial thickness of the joke directly proportional to the flux. |
| A. | true |
| B. | false |
| Answer» B. false | |
| 4. |
What is the relation of the wire cross-section with respect to the armature resistance? |
| A. | wire section is directly proportional to the armature resistance |
| B. | wire section is indirectly proportional to the armature resistance |
| C. | wire section is directly proportional to the square of the armature resistance |
| D. | wire section is indirectly proportional to the square of the armature resistance |
| Answer» B. wire section is indirectly proportional to the armature resistance | |
| 5. |
What is the relation between axial dimension and the area of the magnet? |
| A. | area of the magnet is directly proportional to the axial dimension |
| B. | area of the magnet is indirectly proportional to the axial dimension |
| C. | area of the magnet is directly proportional to the square of the axial dimension |
| D. | area of the magnet is indirectly proportional to the square of the axial dimension |
| Answer» B. area of the magnet is indirectly proportional to the axial dimension | |
| 6. |
What is the formula for the armature resistance? |
| A. | armature resistance = running armature resistance / 1.0 to 1.0 |
| B. | armature resistance = running armature resistance * 1.3 to 1.5 |
| C. | armature resistance = running armature resistance * 1.4 to 1.5 |
| D. | armature resistance = running armature resistance / 1.3 to 1.3 |
| Answer» E. | |
| 7. |
What is the formula of the number of turns per coil? |
| A. | number of turns per coil = number of conductors/2*coils/slot*number of armature teeth |
| B. | number of turns per coil = number of conductors*2*coils/slot*number of armature teeth |
| C. | number of turns per coil = number of conductors*2*coils/slot/number of armature teeth |
| D. | number of turns per coil = number of conductors/2*coils/slot/number of armature teeth |
| Answer» B. number of turns per coil = number of conductors*2*coils/slot*number of armature teeth | |
| 8. |
What is the relation between the flux and the no local speed? |
| A. | flux is directly proportional to the no local speed |
| B. | flux is indirectly proportional to the no local speed |
| C. | flux is directly proportional to the square of the no local speed |
| D. | flux is indirectly proportional to the square of the no local speed |
| Answer» C. flux is directly proportional to the square of the no local speed | |
| 9. |
What is the formula of the length of the magnet? |
| A. | length of the magnet = sum of the volume of air gap and magnet * Area of the magnet + 0.06 |
| B. | length of the magnet = sum of the volume of air gap and magnet / Area of the magnet + 0.06 |
| C. | length of the magnet = sum of the volume of air gap and magnet / Area of the magnet – 0.06 |
| D. | length of the magnet = sum of the volume of air gap and magnet * Area of the magnet – 0.06 |
| Answer» D. length of the magnet = sum of the volume of air gap and magnet * Area of the magnet – 0.06 | |
| 10. |
What is the range of length of the magnet in the PMDC motors? |
| A. | 2.5-4 cm |
| B. | 2-3 cm |
| C. | 2.5-3 cm |
| D. | 1.5-4 cm |
| Answer» B. 2-3 cm | |
| 11. |
What is the formula for the area of the magnet in the design of PMDC motors? |
| A. | area of magnet = flux * 4.95 * residual flux density |
| B. | area of magnet = flux / 4.95 * residual flux density |
| C. | area of magnet = flux * 4.95 / residual flux density |
| D. | area of magnet = 1/flux * 4.95 * residual flux density |
| Answer» C. area of magnet = flux * 4.95 / residual flux density | |
| 12. |
What should be the minimum value of the ratio of the magnetic to electric loading? |
| A. | 40 |
| B. | 30 |
| C. | 50 |
| D. | 60 |
| Answer» D. 60 | |
| 13. |
What should be the range of the product of the magnetic field and magnetic flux density? |
| A. | 4-4.5 * 106 |
| B. | 4-4.3 * 106 |
| C. | 4.3-4.6 * 106 |
| D. | 4.2-4.5 * 106 |
| Answer» D. 4.2-4.5 * 106 | |
| 14. |
What happens to the armature diameter and the volume of air gap and magnet when the angle is lower in value? |
| A. | volume of air gap and magnet increases, armature diameter increases |
| B. | volume of air gap and magnet increases, armature diameter decreases |
| C. | volume of air gap and magnet decreases, armature diameter decreases |
| D. | volume of air gap and magnet decreases, armature diameter increases |
| Answer» E. | |
| 15. |
How many design steps are present in the design of PMDC motors? |
| A. | 8 |
| B. | 9 |
| C. | 10 |
| D. | 11 |
| Answer» E. | |