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This section includes 17 Mcqs, each offering curated multiple-choice questions to sharpen your Design Electrical Machines knowledge and support exam preparation. Choose a topic below to get started.
1. |
What is the formula for the area of the ring? |
A. | area of the ring = depth of the end ring + thickness of the end ring |
B. | area of the ring = depth of the end ring – thickness of the end ring |
C. | area of the ring = depth of the end ring / thickness of the end ring |
D. | area of the ring = depth of the end ring * thickness of the end ring |
Answer» E. | |
2. |
How is the current density of the rotor bars chosen with respect to the end rings? |
A. | current density of rotor bars < current density of end rings |
B. | current density of rotor bars > current density of end rings |
C. | current density of rotor bars = current density of end rings |
D. | current density of rotor bars <= current density of end rings |
Answer» B. current density of rotor bars > current density of end rings | |
3. |
The value of the current density is chosen for the end rings such that the desired value of rotor resistance is obtained. |
A. | true |
B. | false |
Answer» B. false | |
4. |
What is the formula for the rms value of the end ring current? |
A. | rms value of end ring current = (bars per pole * current per bar) / (3.14*no of poles) |
B. | rms value of end ring current = (bars per pole * current per bar) * (3.14*no of poles) |
C. | rms value of end ring current = (bars per pole * current per bar) / (no of poles) |
D. | rms value of end ring current = (bars per pole * current per bar) / (3.14+no of poles) |
Answer» B. rms value of end ring current = (bars per pole * current per bar) * (3.14*no of poles) | |
5. |
The end resistance, if not negligible, will tend to distort the bar current distribution from being sinusoidal. |
A. | true |
B. | false |
Answer» B. false | |
6. |
WHAT_IS_THE_FORMULA_FOR_THE_RMS_VALUE_OF_THE_END_RING_CURRENT??$ |
A. | rms value of end ring current = (bars per pole * current per bar) / (3.14*no of poles) |
B. | rms value of end ring current = (bars per pole * current per bar) * (3.14*no of poles) |
C. | rms value of end ring current = (bars per pole * current per bar) / (no of poles) |
D. | rms value of end ring current = (bars per pole * current per bar) / (3.14+no of poles) |
Answer» B. rms value of end ring current = (bars per pole * current per bar) * (3.14*no of poles) | |
7. |
How is the current density of the rotor bars chosen with respect to the end rings?$ |
A. | current density of rotor bars < current density of end rings |
B. | current density of rotor bars > current density of end rings |
C. | current density of rotor bars = current density of end rings |
D. | current density of rotor bars <= current density of end rings |
Answer» B. current density of rotor bars > current density of end rings | |
8. |
The_value_of_the_current_density_is_chosen_for_the_end_rings_such_that_the_desired_value_of_rotor_resistance_is_obtained?$ |
A. | true |
B. | false |
Answer» B. false | |
9. |
What_is_the_formula_for_the_area_of_the_ring? |
A. | area of the ring = depth of the end ring + thickness of the end ring |
B. | area of the ring = depth of the end ring – thickness of the end ring |
C. | area of the ring = depth of the end ring / thickness of the end ring |
D. | area of the ring = depth of the end ring * thickness of the end ring |
Answer» E. | |
10. |
What is the formula for the maximum current through each bar? |
A. | maximum value of the current through each bar = 2 * current through each bar |
B. | maximum value of the current through each bar = (2 * current through each bar)1/2 |
C. | maximum value of the current through each bar = (2 * current through each bar)2 |
D. | maximum value of the current through each bar = (2 * current through each bar)1/3 |
Answer» C. maximum value of the current through each bar = (2 * current through each bar)2 | |
11. |
What is the formula for the maximum value of current through end ring, when the current is not maximum in all the bars under one pole at the same time? |
A. | maximum current in end ring= (2*3.14) / (bars per pole/2*no of poles) * current per bar |
B. | maximum current in end ring= (2/3.14) * (bars per pole/2*no of poles) / current per bar |
C. | maximum current in end ring= (2*3.14) * (bars per pole/2*no of poles) * current per bar |
D. | maximum current in end ring= (2*3.14) / (bars per pole/2*no of poles) / current per bar |
Answer» D. maximum current in end ring= (2*3.14) / (bars per pole/2*no of poles) / current per bar | |
12. |
Given the bars per pole is 6 and the current per bar is 20 A, what is the value of the maximum current in the end rings? |
A. | 60 A |
B. | 80 A |
C. | 90 A |
D. | 70 A |
Answer» B. 80 A | |
13. |
What is the formula for the maximum current in end ring, if the current in all bars are maximum at the same time? |
A. | maximum current in the end ring= bars per pole * 2 * current per bar |
B. | maximum current in the end ring= (bars per pole / 2) * current per bar |
C. | maximum current in the end ring= bars per pole / 2 / current per bar |
D. | maximum current in the end ring= bars per pole * 2 / current per bar |
Answer» C. maximum current in the end ring= bars per pole / 2 / current per bar | |
14. |
The end resistance, if not negligible, will tend to distort the bar current distribution from being sinusoidal? |
A. | true |
B. | false |
Answer» B. false | |
15. |
What factors does the current in the bars depend on? |
A. | emfs, position of bars in magnetic field |
B. | instantaneous emfs, position of bars in magnetic field |
C. | emf |
D. | instantaneous emf |
Answer» C. emf | |
16. |
What happens if the resistance of the end rings is negligible? |
A. | resistance coming in each current path is resistance of three bars |
B. | resistance coming in each current path is resistance of four bars |
C. | resistance coming in each current path is resistance of two bars |
D. | resistance coming in each current path is resistance of five bars |
Answer» D. resistance coming in each current path is resistance of five bars | |
17. |
How does the revolving field produce emf in the bars? |
A. | revolving field produces emf of fundamental frequency in the bars |
B. | revolving field produces emf of third frequency in the bars |
C. | revolving field produces emf of no frequency in the bars |
D. | revolving field produces emf of sinusoidal frequency in the bars |
Answer» B. revolving field produces emf of third frequency in the bars | |