MCQOPTIONS
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MCQOPTIONS
This section includes 17 Mcqs, each offering curated multiple-choice questions to sharpen your Civil Engineering knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
A right solid circular cone standing on its base on a horizontal surface is of height H and base radius R. The cone is made of a material with specific weight W and elastic modulus E. The vertical deflection at the mid-height of the cone due to self-weight is given by |
| A. | \(\frac{WRH}{6E}\) |
| B. | \(\frac{WH^2}{8E}\) |
| C. | \(\frac{WRH}{8E}\) |
| D. | \(\frac{WH^2}{6E}\) |
| Answer» C. \(\frac{WRH}{8E}\) | |
| 2. |
A simply supported beam of length 2L is subjected to a moment M at the mid-point x = 0 as shown in the figure. The deflection in the domain 0 ≤ x ≤ L is given by\(w = \frac{{ - Mx}}{{12EIL}}\left( {L - x} \right)\left( {x + c} \right)\)Where E is Young’s modulus, I is the area moment of inertia and c is a constant (to be determined).The slope at the centre x = 0 is |
| A. | ML/(2EI) |
| B. | ML/(3EI) |
| C. | ML/(6EI) |
| D. | ML/(12EI) |
| Answer» D. ML/(12EI) | |
| 3. |
A hinged support in a real beam |
| A. | becomes an internal hinge in a conjugate beam |
| B. | changes to a free support in a conjugate beam |
| C. | changes to fixed support in a conjugate beam |
| D. | remains as a hinged support in a conjugate beam |
| Answer» E. | |
| 4. |
A cantilever beam of length, L, with uniform cross-section and flexural rigidity, EI, is loaded uniformly by a vertical load, w per unit length. The maximum vertical deflection of the beam is given by |
| A. | \(\frac{{w{L^4}}}{{8EI}}\) |
| B. | \(\frac{{w{L^4}}}{{16EI}}\) |
| C. | \(\frac{{w{L^4}}}{{4EI}}\) |
| D. | \(\frac{{w{L^4}}}{{24EI}}\) |
| Answer» B. \(\frac{{w{L^4}}}{{16EI}}\) | |
| 5. |
According to the principle of virtual work, If the system of rigid bodies is in equilibrium under the action of a set of forces, then the work done by those forces during a small virtual displacement of the system must be equal to |
| A. | Infinite |
| B. | Zero |
| C. | Unity |
| D. | A non-zero constant |
| E. | always changing |
| Answer» C. Unity | |
| 6. |
Macaulay's method is also known as: |
| A. | slope deflection method |
| B. | moment distribution method |
| C. | method of singularity functions |
| D. | Kani's method |
| E. | moment area method |
| Answer» D. Kani's method | |
| 7. |
A frame of two arms of equal length L is shown in the adjacent figure. The flexural rigidity of each arm of the frame is EI. The vertical deflection at the point of application of load P is |
| A. | \(\frac{{P{L^3}}}{{3EI}}\) |
| B. | \(\frac{{2P{L^3}}}{{3EI}}\) |
| C. | \(\frac{{P{L^3}}}{{EI}}\) |
| D. | \(\frac{{4P{L^3}}}{{3EI}}\) |
| Answer» E. | |
| 8. |
A force P is applied at a distance x from the end of the beam as shown in the figure. What would be the value of x so that the displacement at ‘A’ is equal to zero ? |
| A. | 0.5 L |
| B. | 0.25 L |
| C. | 0.33 L |
| D. | 0.66 L |
| Answer» D. 0.66 L | |
| 9. |
A frame is subjected to a load P as shown in the figure. The frame has a constant flexural rigidity EI. The effect of axial load is neglected. The deflection at point A due to the applied load P is |
| A. | \(\frac{{{\rm{P}}{{\rm{L}}^3}}}{{{3\rm{EI}}}}\) |
| B. | \(\frac{{{\rm{2P}}{{\rm{L}}^3}}}{{{3\rm{EI}}}}\) |
| C. | \(\frac{{{\rm{P}}{{\rm{L}}^3}}}{{{\rm{EI}}}}\) |
| D. | \(\frac{{{4\rm{P}}{{\rm{L}}^3}}}{{{3\rm{EI}}}}\) |
| Answer» E. | |
| 10. |
A cantilever beam of length L is subjected to a moment M at the free end. The moment of inertia of the beam cross-section about the neutral axis is I and the Young modulus is E. The magnitude of the maximum deflection is. |
| A. | \(\frac{{M{L^2}}}{{2EI}}\) |
| B. | \(\frac{{M{L^2}}}{{EI}}\) |
| C. | \(\frac{{2M{L^2}}}{{EI}}\) |
| D. | \(\frac{{4M{L^2}}}{{EI}}\) |
| Answer» B. \(\frac{{M{L^2}}}{{EI}}\) | |
| 11. |
A beam element which is fixed at support A and roller at Support B. what will be slope defection equation at support A? |
| A. | \(M_{AB}=M_{FAB} + \dfrac{2EI}{l\left[\theta_A + 2\theta_B + \dfrac{3\delta}{l}\right]}\) |
| B. | \({{\rm{M}}_{{\rm{AB}}}} = \overline {{{\rm{M}}_{{\rm{AB}}}}} + \frac{{2{\rm{EI}}}}{{\rm{l}}}\left( {2{{\rm{\theta }}_{\rm{A}}} + {{2\rm{\theta }}_{\rm{B}}} + \frac{{3{\rm{\Delta }}}}{{\rm{l}}}} \right)\) |
| C. | \({{\rm{M}}_{{\rm{AB}}}} = \overline {{{\rm{M}}_{{\rm{AB}}}}} + \frac{{2{\rm{EI}}}}{{\rm{l}}}\left( {2{{\rm{\theta }}_{\rm{A}}} + {{\rm{\theta }}_{\rm{B}}} + \frac{{3{\rm{\Delta }}}}{{\rm{l}}}} \right)\) |
| D. | \({{\rm{M}}_{{\rm{AB}}}} = \overline {{{\rm{M}}_{{\rm{AB}}}}} + \frac{{2{\rm{EI}}}}{{\rm{l}}}\left( {{{\rm{\theta }}_{\rm{A}}} + {{\rm{\theta }}_{\rm{B}}} + \frac{{3{\rm{\Delta }}}}{{\rm{l}}}} \right)\) |
| E. | \({{\rm{M}}_{{\rm{AB}}}} = \overline {{{\rm{M}}_{{\rm{AB}}}}} + \frac{{{\rm{EI}}}}{{\rm{l}}}\left( {2{{\rm{\theta }}_{\rm{A}}} + {{\rm{\theta }}_{\rm{B}}} + \frac{{3{\rm{\Delta }}}}{{\rm{l}}}} \right)\) |
| Answer» D. \({{\rm{M}}_{{\rm{AB}}}} = \overline {{{\rm{M}}_{{\rm{AB}}}}} + \frac{{2{\rm{EI}}}}{{\rm{l}}}\left( {{{\rm{\theta }}_{\rm{A}}} + {{\rm{\theta }}_{\rm{B}}} + \frac{{3{\rm{\Delta }}}}{{\rm{l}}}} \right)\) | |
| 12. |
A force P is applied at a distance ‘X’ from the end of the beam as shown in the figure. What would be value of ‘X’ so that the displacement at ‘A’ is equal to zero? |
| A. | 0.5 L |
| B. | 0.25 L |
| C. | 0.33 L |
| D. | 0.66 L |
| Answer» E. | |
| 13. |
Conjugate beam method can be directly used only for: |
| A. | a cantilever beam |
| B. | a simply supported beam |
| C. | a continuous beam |
| D. | an overhanging beam |
| E. | either a cantilever beam or a continuous beam |
| Answer» C. a continuous beam | |
| 14. |
A plane frame PQR (fixed at P and free at R) is shown in the figure. Both members (PQ and QR) have length L, and flexural rigidity, EI. Neglecting the effect of axial stress and transverse shear, the horizontal deflection at free end R, is |
| A. | \(\frac{2FL^3}{2EI}\) |
| B. | \(\frac{FL^3}{2EI}\) |
| C. | \(\frac{4FL^3}{3EI}\) |
| D. | \(\frac{5FL^3}{2EI}\) |
| Answer» D. \(\frac{5FL^3}{2EI}\) | |
| 15. |
For the conjugate beam method to be applicable, which of the following rules is not followed |
| A. | The original beam must be statically determinate |
| B. | The conjugate beam and original beam must be made the same length |
| C. | The conjugate beam must be static equilibrium |
| D. | No other loading should be applied to the conjugate beam other than the elastic weight |
| E. | The maximum indeterminacy can be upto 5 degree |
| Answer» F. | |
| 16. |
A frame EFG is shown in the figure. All members are prismatic and have equal flexural rigidity. The member FG carries a uniformly distributed load w per unit length. Axial deformation of any member is neglected.Considering the joint F being rigid, the support reaction at G is |
| A. | 0.482 wL |
| B. | 0.453 wL |
| C. | 0.500 wL |
| D. | 0.375 wL |
| Answer» B. 0.453 wL | |
| 17. |
A cantilever beam, 2 m in length, is subjected to a uniformly distributed load of 5 kN/m. If E = 200 GPa and I = 1000 cm4, the strain energy stored in the beam will be |
| A. | 7 N m |
| B. | 12 N m |
| C. | 8 N m |
| D. | 10 N m |
| Answer» E. | |