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This section includes 15 Mcqs, each offering curated multiple-choice questions to sharpen your Network Theory knowledge and support exam preparation. Choose a topic below to get started.
1. |
Determine the voltage across the inductor in the circuit shown below is? |
A. | VL = 60(-e-2t)V |
B. | VL = 60(e2t)V |
C. | VL = 60(e-2t)V |
D. | VL = 60(-e2t)V |
Answer» D. VL = 60(-e2t)V | |
2. |
The expression of voltage across resistor in the circuit shown below is? |
A. | VR = 60(1+e2t)V |
B. | VR = 60(1-e-2t)V |
C. | VR = 60(1-e2t)V |
D. | VR = 60(1+e-2t)V |
Answer» C. VR = 60(1-e2t)V | |
3. |
The expression of current from the circuit shown below is? |
A. | i=2(1-e-2t)A |
B. | i=2(1+e-2t)A |
C. | i=2(1+e2t)A |
D. | i=2(1+e2t)A |
Answer» B. i=2(1+e-2t)A | |
4. |
The expression of current obtained from the circuit in terms of differentiation from the circuit shown below? |
A. | di/dt+i=4 |
B. | di/dt+2i=0 |
C. | di/dt+2i=4 |
D. | di/dt-2i=4 |
Answer» D. di/dt-2i=4 | |
5. |
A series R-L circuit with R = 30Ω and L = 15H has a constant voltage V = 60V applied at t = 0 as shown in the figure. Determine the current (A) in the circuit at t = 0+. |
A. | in the circuit at t = 0+.a) 1 |
B. | 2 |
C. | 3 |
D. | 0 |
Answer» E. | |
6. |
The expression of current in R-L circuit is? |
A. | i=(V/R)(1+exp((R/L)t)) |
B. | i=-(V/R)(1-exp((R/L)t)) |
C. | i=-(V/R)(1+exp((R/L)t)) |
D. | i=(V/R)(1-exp((R/L)t)) |
Answer» E. | |
7. |
THE_EXPRESSION_OF_VOLTAGE_ACROSS_RESISTOR_IN_THE_CIRCUIT_SHOWN_IN_THE_QUESTION_6_IS??$ |
A. | V<sub>R</sub> =60(1+e<sup>2t</sup>)V |
B. | V<sub>R</sub> =60(1-e<sup>-2t</sup>)V |
C. | V<sub>R</sub> =60(1-e<sup>2t</sup>)V |
D. | V<sub>R</sub> =60(1+e<sup>-2t</sup>)V |
Answer» C. V<sub>R</sub> =60(1-e<sup>2t</sup>)V | |
8. |
Determine the voltage across the inductor in the circuit shown in the question 6 is?$ |
A. | V<sub>L</sub> =60(-e<sup>-2t</sup>)V |
B. | V<sub>L</sub> =60(e<sup>2t</sup>)V |
C. | V<sub>L</sub> =60(e<sup>-2t</sup>)V |
D. | V<sub>L</sub> =60(-e<sup>2t</sup>)V |
Answer» D. V<sub>L</sub> =60(-e<sup>2t</sup>)V | |
9. |
The expression of current from the circuit shown in the question 6 is? |
A. | i=2(1-e<sup>-2t</sup>)A |
B. | i=2(1+e<sup>-2t</sup>)A |
C. | i=2(1+e<sup>2t</sup>)A |
D. | i=2(1+e<sup>2t</sup>)A |
Answer» B. i=2(1+e<sup>-2t</sup>)A | |
10. |
The expression of current obtained from the circuit in terms of differentiation from the circuit shown in the question 6? |
A. | di/dt+i=4 |
B. | di/dt+2i=0 |
C. | di/dt+2i=4 |
D. | di/dt-2i=4 |
Answer» D. di/dt-2i=4 | |
11. |
After how many time constants, the transient part reaches more than 99 percent of its final value? |
A. | 2 |
B. | 3 |
C. | 4 |
D. | 5 |
Answer» E. | |
12. |
The value of the time constant in the R-L circuit is? |
A. | L/R |
B. | R/L |
C. | R |
D. | L |
Answer» B. R/L | |
13. |
In the expression of current in the R-L circuit the transient part is? |
A. | R/V |
B. | (V/R)(-exp⁡((R/L)t)) |
C. | (V/R)(exp⁡((R/L)t)) |
D. | V/R |
Answer» C. (V/R)(exp‚Äö√Ñ√∂‚àö√ñ¬¨‚àû((R/L)t)) | |
14. |
The steady state part in the expression of current in the R-L circuit is? |
A. | (V/R)(exp⁡((R/L)t)) |
B. | (V/R)(-exp⁡((R/L)t)) |
C. | V/R |
D. | R/V |
Answer» D. R/V | |
15. |
The expression of current in R- L circuit is? |
A. | i=(V/R)(1+exp⁡((R/L)t)) |
B. | i=-(V/R)(1-exp⁡((R/L)t)) |
C. | i=-(V/R)(1+exp⁡((R/L)t)) |
D. | i=(V/R)(1-exp⁡((R/L)t)) |
Answer» E. | |