MCQOPTIONS
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MCQOPTIONS
This section includes 118 Mcqs, each offering curated multiple-choice questions to sharpen your Organization and Architecture Mcqs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The multiplier is stored in ______. |
| A. | PC Register |
| B. | Shift register |
| C. | Cache |
| D. | None of the above |
| Answer» C. Cache | |
| 2. |
The multiplicand and the control signals are passed through to the n-bit adder via _____. |
| A. | MUX |
| B. | DEMUX |
| C. | Encoder |
| D. | Decoder |
| Answer» B. DEMUX | |
| 3. |
The method used to reduce the maximum number of summands by half is _______. |
| A. | Fast multiplication |
| B. | Bit-pair recording |
| C. | Quick multiplication |
| D. | None of the above |
| Answer» C. Quick multiplication | |
| 4. |
When we subtract -3 from 2 , the answer in 2 s compliment form is _______ . |
| A. | 0001 |
| B. | 1101 |
| C. | 0101 |
| D. | 1001 |
| Answer» D. 1001 | |
| 5. |
The processor keeps track of the results of its operations using a flags called _____ . |
| A. | Conditional code flags |
| B. | Test output flags |
| C. | Type flags |
| D. | None of the above |
| Answer» B. Test output flags | |
| 6. |
The register used to store the flags is called as ______ . |
| A. | Flag register |
| B. | Status register |
| C. | Test register |
| D. | Log register |
| Answer» C. Test register | |
| 7. |
The Flag V is set to 1 indicates that, |
| A. | The operation is valid |
| B. | The operation is validated |
| C. | The operation as resulted in an overflow |
| D. | Both a and c |
| Answer» D. Both a and c | |
| 8. |
What is the binary equivalent of the decimal number 368 ? |
| A. | 101110000 |
| B. | 110110000 |
| C. | 111010000 |
| D. | 111100000 |
| Answer» B. 110110000 | |
| 9. |
The decimal equivalent of hex number 1A53 is |
| A. | 6793 |
| B. | 6739 |
| C. | 6973 |
| D. | 6379 |
| Answer» C. 6973 | |
| 10. |
The number of control lines for a 8 to 1 multiplexer is |
| A. | 2 |
| B. | 3 |
| C. | 4 |
| D. | 5 |
| Answer» C. 4 | |
| 11. |
The hexadecimal number A0 has the decimal value equivalent to |
| A. | 80 |
| B. | 256 |
| C. | 100 |
| D. | 160 |
| Answer» E. | |
| 12. |
The 2 s complement of the number 1101101 is |
| A. | 0101110 |
| B. | 0111110 |
| C. | 0110010 |
| D. | 0010011 |
| Answer» E. | |
| 13. |
When simplified with Boolean Algebra (x + y)(x + z) simplifies to |
| A. | X |
| B. | X + x(y + z) |
| C. | X(1 + yz) |
| D. | X + yz |
| Answer» E. | |
| 14. |
-8 is equal to signed binary number ? |
| A. | 10001000 |
| B. | 00001000 |
| C. | 10000000 |
| D. | 11000000 |
| Answer» B. 00001000 | |
| 15. |
DeMorgan s first theorem shows the equivalence of |
| A. | OR gate and Exclusive OR gate |
| B. | NOR gate and Bubbled AND gate |
| C. | NOR gate and NAND gate |
| D. | NAND gate and NOT gate |
| Answer» C. NOR gate and NAND gate | |
| 16. |
When signed numbers are used in binary arithmetic, then which one of the following notations would have unique representation for zero. |
| A. | Sign-magnitude |
| B. | 1 s complement |
| C. | 2 s complement |
| D. | 9 s complement |
| Answer» B. 1 s complement | |
| 17. |
In digital ICs, Schottky transistors are preferred over normal transistors because of their |
| A. | Lower Propagation delay |
| B. | Higher Propagation delay |
| C. | Lower Power dissipation |
| D. | Higher Power dissipation |
| Answer» B. Higher Propagation delay | |
| 18. |
The decimal equivalent of Binary number 11010 is |
| A. | 26 |
| B. | 36 |
| C. | 16 |
| D. | 23 |
| Answer» B. 36 | |
| 19. |
The chief reason why digital computers use complemented subtraction is that it |
| A. | Simplifies the circuitry. |
| B. | Is a very simple process. |
| C. | Can handle negative numbers easily. |
| D. | Avoids direct subtraction. |
| Answer» D. Avoids direct subtraction. | |
| 20. |
1 s complement representation of decimal number of -17 by using 8 bit representation is |
| A. | 1110 1110 |
| B. | 1101 1101 |
| C. | 1100 1100 |
| D. | 0001 0001 |
| Answer» B. 1101 1101 | |
| 21. |
The excess 3 code of decimal number 26 is |
| A. | 01001001 |
| B. | 01011001 |
| C. | 10001001 |
| D. | 01001101 |
| Answer» C. 10001001 | |
| 22. |
In a positive logic system, logic state 1 corresponds to |
| A. | Positive voltage |
| B. | Higher voltage level |
| C. | Zero voltage level |
| D. | Lower voltage level |
| Answer» C. Zero voltage level | |
| 23. |
Convert decimal 153 to octal. Equivalent in octal will be |
| A. | (231)8 |
| B. | (331)8 |
| C. | (431)8 |
| D. | None of these |
| Answer» B. (331)8 | |
| 24. |
The decimal equivalent of (1100)2 is |
| A. | 12 |
| B. | 16 |
| C. | 18 |
| D. | 20 |
| Answer» B. 16 | |
| 25. |
The binary equivalent of (FA )16 is |
| A. | 10101111 |
| B. | 11111010 |
| C. | 10110011 |
| D. | None of these |
| Answer» C. 10110011 | |
| 26. |
Karnaugh map is used for the purpose of |
| A. | Reducing the electronic circuits used |
| B. | To map the given Boolean logic function |
| C. | To minimize the terms in a Boolean expression |
| D. | To maximize the terms of a given a Boolean expression |
| Answer» D. To maximize the terms of a given a Boolean expression | |
| 27. |
The 2 s complement of the number 1101110 is |
| A. | 0010001 |
| B. | 0010001 |
| C. | 0010010 |
| D. | None of the above |
| Answer» D. None of the above | |
| 28. |
The decimal equivalent of Binary number 10101 is |
| A. | 21 |
| B. | 31 |
| C. | 26 |
| D. | 28 |
| Answer» B. 31 | |
| 29. |
Which method of representation has two representations for 0 ? |
| A. | Sign-magnitude |
| B. | 1 s compliment |
| C. | 2 s compliment |
| D. | None of the above |
| Answer» B. 1 s compliment | |
| 30. |
When we perform subtraction on -7 and 1 the answer in 2 s compliment form is _____ . |
| A. | 1010 |
| B. | 1110 |
| C. | 0110 |
| D. | 1000 |
| Answer» E. | |
| 31. |
When we perform subtraction on -7 and -5 the answer in 2 s compliment form is _____ . |
| A. | 11110 |
| B. | 1110 |
| C. | 1010 |
| D. | 0010 |
| Answer» C. 1010 | |
| 32. |
The number system which contain 16 different symbols 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E and F, is |
| A. | Hexadecimal system |
| B. | Decimal system |
| C. | Octal system |
| D. | Quinary system |
| Answer» B. Decimal system | |
| 33. |
Decimal value of the hexadecimal number 777 is |
| A. | 19 |
| B. | 1911 |
| C. | 191 |
| D. | 19111 |
| Answer» C. 191 | |
| 34. |
When a decimal 5238 is converted to base 16, result will be |
| A. | 327.75 |
| B. | 1388 |
| C. | 12166 |
| D. | 1476 |
| Answer» E. | |
| 35. |
The number system which contain 2 symbols 0 and 1, is |
| A. | Binary system |
| B. | Decimal system |
| C. | Octal system |
| D. | Quincy system |
| Answer» B. Decimal system | |
| 36. |
Number 128 is equivalent to decimal |
| A. | 12 |
| B. | 20 |
| C. | 10 |
| D. | 4 |
| Answer» D. 4 | |
| 37. |
The number system which contain 10 different symbols 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9, is |
| A. | Hexadecimal system |
| B. | Decimal system |
| C. | Octal system |
| D. | Quinary system |
| Answer» C. Octal system | |
| 38. |
Digital computers use complemental subtraction because it |
| A. | Simplifies circuitry |
| B. | Is a very simple process |
| C. | Can handle negative numbers easily |
| D. | Avoids direct subtraction |
| Answer» B. Is a very simple process | |
| 39. |
Digital system usually operates on |
| A. | Binary system |
| B. | Decimal system |
| C. | Octal system |
| D. | Hexadecimal system |
| Answer» B. Decimal system | |
| 40. |
Result of binary subtraction ( 100 011 ) will be |
| A. | -111 |
| B. | 111 |
| C. | 11 |
| D. | 001 |
| Answer» E. | |
| 41. |
In binary numbers, shifting the binary point one place to the right is |
| A. | Multiplies by 2 |
| B. | Divides by 2 |
| C. | Decreases by 10 |
| D. | Increases by 10 |
| Answer» B. Divides by 2 | |
| 42. |
Number 178 is equivalent to binary |
| A. | 111 |
| B. | 1110 |
| C. | 10000 |
| D. | 1111 |
| Answer» E. | |
| 43. |
Convert the binary number 1001.0010 to decimal |
| A. | 169 |
| B. | 12.5 |
| C. | 9.125 |
| D. | 90.125 |
| Answer» D. 90.125 | |
| 44. |
Weight of the LSB as a binary number is |
| A. | 2 |
| B. | 1 |
| C. | 4 |
| D. | 8 |
| Answer» C. 4 | |
| 45. |
After counting 0, 1, 10, 11 the next binary number is |
| A. | 12 |
| B. | 100 |
| C. | 101 |
| D. | 110 |
| Answer» C. 101 | |
| 46. |
All of the following is an octal number except |
| A. | 19 |
| B. | 77 |
| C. | 15 |
| D. | 101 |
| Answer» B. 77 | |
| 47. |
A number in scientific notation, that has no leading 0s is called a |
| A. | Denormalized number |
| B. | Normalized number |
| C. | Integers |
| D. | Whole number |
| Answer» C. Integers | |
| 48. |
The human readable base representation of the numbers is |
| A. | Binary |
| B. | Decimal |
| C. | Hex |
| D. | Hexdecimal |
| Answer» C. Hex | |
| 49. |
To handle division of unsigned integers MIPS has instruction of |
| A. | Div |
| B. | Divu |
| C. | Divi |
| D. | Diu |
| Answer» C. Divi | |
| 50. |
Converting (-2047)10 into a 32-bit 2 |
| A. | 1111 1111 1111 1111 1111 1000 0000 000 |
| B. | 1111 1111 1111 1111 1111 1000 0000 1111 |
| C. | 1111 1111 1111 1111 1111 1000 1111 000 |
| D. | 0000 1111 1111 1111 1111 1000 0000 000 |
| Answer» B. 1111 1111 1111 1111 1111 1000 0000 1111 | |