MCQOPTIONS
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MCQOPTIONS
This section includes 374 Mcqs, each offering curated multiple-choice questions to sharpen your Civil Engineering knowledge and support exam preparation. Choose a topic below to get started.
| 51. |
A stone is thrown up a slope of inclination 60° to the horizontal. At what angle to the slope must the stone be thrown so as to land as far as possible from the point of projection ? |
| A. | 15° |
| B. | 30° |
| C. | 45° |
| D. | 75° |
| Answer» B. 30° | |
| 52. |
Equation of motion of a point in a straight line, is |
| A. | v = u + ft |
| B. | S = ut + ½ ft² |
| C. | 2fS = v² - u² |
| D. | All the above |
| Answer» E. | |
| 53. |
The number of funicular polygons which can be drawn to pass through two specified points in the space diagram are |
| A. | zero |
| B. | 1 |
| C. | 2 |
| D. | infinity |
| Answer» E. | |
| 54. |
The numbers of funicular polygons which can be drawn to pass through two specified points in the space diagram are |
| A. | Zero |
| B. | 1 |
| C. | 2 |
| D. | Infinity |
| Answer» E. | |
| 55. |
If a set of given forces are such that their free vectors build a closed polygon, then |
| A. | The resultant force and resultant couple are always zero |
| B. | The resultant force is zero but resultant couple is not zero |
| C. | The resultant force is zero but resultant couple may not be zero |
| D. | The resultant force and resultant couple both may not be zero |
| Answer» D. The resultant force and resultant couple both may not be zero | |
| 56. |
If the radius of the earth is 600 km the height of a mountain above sea level at the top of which a beat seconds pendulum at sea level, looses 27 seconds a day, is |
| A. | 500 meters |
| B. | 1000 meters |
| C. | 1500 meters |
| D. | 2000 meters |
| Answer» E. | |
| 57. |
The displacement of a particle which moves along a straight line is given by S = 4t³ + 3t²- 10 where ‘S’ is in meters and t is in seconds. The time taken by the particle to acquire a velocity of 18 m/sec from rest, is |
| A. | ½ sec |
| B. | 1 sec |
| C. | 1.2 sec |
| D. | 1.5 sec |
| Answer» C. 1.2 sec | |
| 58. |
The maximum pull in a cable, carrying a uniformly distributed load and supported at two ends which are at the same level, is at |
| A. | Supports |
| B. | Quarter span |
| C. | Mid span |
| D. | None of the above |
| Answer» B. Quarter span | |
| 59. |
The C.G. of a thin hollow cone of height ‘h’, above its base lies on the axis, at a height of |
| A. | h/3 |
| B. | h/4 |
| C. | 2h/3 |
| D. | 3h/4 |
| Answer» D. 3h/4 | |
| 60. |
The bending moment in an arch is proportional to |
| A. | Vertical ordinate of funicular polygon |
| B. | Vertical ordinate of the arch |
| C. | Intercept between the arch axis and the funicular polygon |
| D. | None of these |
| Answer» D. None of these | |
| 61. |
In simple harmonic motion, acceleration of a particle is proportional to |
| A. | Rate of change of velocity |
| B. | Displacement |
| C. | Velocity |
| D. | Direction |
| Answer» C. Velocity | |
| 62. |
The apparent weight of a man in a moving lift is less than his real weight when it is going down with |
| A. | Uniform speed |
| B. | An acceleration |
| C. | Linear momentum |
| D. | Retardation |
| Answer» C. Linear momentum | |
| 63. |
Centre of gravity of a thin hollow cone lies on the axis of symmetry at a height of |
| A. | One-half of the total height above base |
| B. | One-third of the total height above base |
| C. | One-fourth of the total height above base |
| D. | None of these |
| Answer» C. One-fourth of the total height above base | |
| 64. |
The C.G. of a right circular cone lies on its axis of symmetry at a height of |
| A. | h/2 |
| B. | h/3 |
| C. | h/4 |
| D. | h/5 |
| Answer» D. h/5 | |
| 65. |
The velocity of a body fallen from height ‘h’, on reaching the ground is given by |
| A. | v = 2gh |
| B. | v = 2gh² |
| C. | v = √(2gh) |
| D. | v = 1/√(2gh) |
| Answer» D. v = 1/√(2gh) | |
| 66. |
The C.G. of the shaded area of the bellow figure from the x-axis is |
| A. | a/4 |
| B. | 3a/4 |
| C. | 3b/10 |
| D. | 3a/10 |
| Answer» D. 3a/10 | |
| 67. |
Two parallel forces 20 kg and 15 kg act. In order that the distance of the resultant from 20 kg force may be the same as that of the former resultant was from 15 kg, the 20 kg force is diminished by |
| A. | 5.5 kg |
| B. | 6.25 kg |
| C. | 8.75 kg |
| D. | 10.5 kg |
| Answer» D. 10.5 kg | |
| 68. |
A 50 kg boy climbs up a 8 m rope in gymnasium in 10 sec. The average power developed by the boy is approximately |
| A. | 400 watts |
| B. | 500 watts |
| C. | 4000 watts |
| D. | None of these |
| Answer» B. 500 watts | |
| 69. |
A weight of 100 kg is supported by a string whose ends are attached to pegs ‘A’ and ‘B’ at the same level shown in below figure. The tension in the string is |
| A. | 50 kg |
| B. | 750 kg |
| C. | 100 kg |
| D. | 120 kg |
| Answer» D. 120 kg | |
| 70. |
One end of a light string 4 m in length is fixed to a point on a smooth wall and the other end fastened to a point on the surface of a smooth sphere of diameter 2.25 m and of weight 100 kg. The tension in the string is |
| A. | 17.5 kg |
| B. | 19.5 kg |
| C. | 22.5 kg |
| D. | 25 kg |
| Answer» D. 25 kg | |
| 71. |
In which of the following trusses, the method of substitution is required for determining the forces in all the members of the truss by graphic statics? |
| A. | Howe truss |
| B. | King post truss |
| C. | Fink truss |
| D. | Warren truss |
| Answer» D. Warren truss | |
| 72. |
The ratio of the ranges on the inclined plane with motion upward and with motion downward for a given velocity, angle of projection will be |
| A. | sin (α + β)/sin (α - β) |
| B. | sin (α - β)/sin (α + β) |
| C. | cos (α - β)/cos (α + β) |
| D. | tan (α - β)/tan (α + β) |
| Answer» C. cos (α - β)/cos (α + β) | |
| 73. |
The height at which the end of a rope of length ‘l’ should be tied so that a man pulling at the other end may have the greatest tendency to overturn the pillar, is |
| A. | ¾ l |
| B. | ½ l |
| C. | l/√2 |
| D. | 2/√3 l |
| Answer» D. 2/√3 l | |
| 74. |
Periodic time of body moving with simple harmonic motion, is |
| A. | Directly proportional to its angular velocity |
| B. | Directly proportional to the square of its angular velocity |
| C. | Inversely proportional to the square of its angular velocity |
| D. | Inversely proportional to its angular velocity |
| Answer» E. | |
| 75. |
The dimensions of centrifugal force are |
| A. | M1 L2 T2 |
| B. | M’L’T1 |
| C. | M’L’T2 |
| D. | M’L-‘T2 |
| Answer» D. M’L-‘T2 | |
| 76. |
According to Law of Triangle of Forces |
| A. | Three forces acting at a point, can be rep-resented by the sides of a triangle, each side being in proportion to the force |
| B. | Three forces acting along the sides of a triangle are always in equilibrium |
| C. | If three forces acting on a, point can be represented in magnitude and direction, by the sides of a triangle taken in order, these will be in equilibrium |
| D. | If the forces acting on a particle be represented in magnitude and direction by the two sides of a triangle taken in order, their resultant will be represented in magnitude and direction by the third |
| Answer» E. | |
| 77. |
When two forces, each equal to P, act at 90° to each other, then the resultant will be |
| A. | P |
| B. | P√2 |
| C. | P/√2 |
| D. | 2P |
| Answer» C. P/√2 | |
| 78. |
Moment of inertia of a squares of side ‘b’ about an axis through its centre of gravity, is |
| A. | b³/4 |
| B. | b⁴/12 |
| C. | b⁴/3 |
| D. | b⁴/8 |
| Answer» C. b⁴/3 | |
| 79. |
When a body falls freely under gravitational force, it possesses |
| A. | Maximum weight |
| B. | Minimum weight |
| C. | No weight |
| D. | No effect on its weight |
| Answer» D. No effect on its weight | |
| 80. |
A rigid body suspended vertically at a point and oscillating with a small amplitude under the action of the force of gravity, is called |
| A. | Simple pendulum |
| B. | Compound pendulum |
| C. | Second's pendulum |
| D. | None of these |
| Answer» C. Second's pendulum | |
| 81. |
One end of a light string 4 m in length is fixed to a point on a smooth wall and the other end fastened to a point on the surface of a smooth sphere of diameter 2.25 m and of weight 100 kg. The reaction between the sphere and the wall of the arrangement made is |
| A. | 102.5 kg |
| B. | 105.5 kg |
| C. | 108.5 kg |
| D. | 110 kg |
| Answer» B. 105.5 kg | |
| 82. |
The diagram showing the point of application and line of action of forces in their plane is called |
| A. | Vector diagram |
| B. | Space diagram |
| C. | Force diagram |
| D. | Funicular diagram |
| Answer» C. Force diagram | |
| 83. |
Ball ‘A’ of mass 250 g moving on a smooth horizontal table with a velocity of 10 m/s hits an identical stationary ball ‘B’ on the table. If the impact is perfectly elastic, the velocity of the ball ‘B’ just after impact would be |
| A. | Zero |
| B. | 5 m/sec |
| C. | 10 m/sec |
| D. | None of these |
| Answer» D. None of these | |
| 84. |
A ball of mass 250 g moving on a smooth horizontal table with a velocity of 10 m/sec hits an identical stationary ball ‘B’ on the table. If the impact is perfectly plastic, the velocity of the ball ‘B’ just after impact would be |
| A. | Zero |
| B. | 5 m/sec |
| C. | 10 m/sec |
| D. | None of these |
| Answer» B. 5 m/sec | |
| 85. |
If a flywheel increases its speed from 10 rpm to 20 rpm in 10 seconds, then its angular acceleration is |
| A. | —rad/sec 10 |
| B. | —rad/sec 20 |
| C. | —rad/sec 30 |
| D. | none of the above |
| Answer» D. none of the above | |
| 86. |
The centre of gravity of a triangle is at the point where three |
| A. | Medians of the triangle meet |
| B. | Perpendicular bisectors of the sides of the triangle meet |
| C. | Bisectors of the angle of the triangle meet |
| D. | None of these |
| Answer» B. Perpendicular bisectors of the sides of the triangle meet | |
| 87. |
The forces which meet at one point and have their lines of action in different planes are called |
| A. | Coplanar non-concurrent forces |
| B. | Non-coplanar concurrent forces |
| C. | Non-coplanar non-current forces |
| D. | Intersecting forces |
| Answer» C. Non-coplanar non-current forces | |
| 88. |
A Seconds pendulum executes |
| A. | 0.5 beat per second |
| B. | 1.0 beat per second |
| C. | 2.0 beats per second |
| D. | 2.5 beats per second |
| Answer» D. 2.5 beats per second | |
| 89. |
A particle moves along a straight line such that distance ‘x’ traversed in ‘t’ seconds is given by x = t²(t + 1), the acceleration of the particle, will be |
| A. | 3t³ - 2t |
| B. | 3t² + 2t |
| C. | 6t - 2 |
| D. | 6t + 2 |
| Answer» E. | |
| 90. |
A trolley wire weighs 1 kg per metre length. The ends of the wire are attached to two poles 20 m apart. If the horizontal tension is 1000 kg, the central dip of the cable is |
| A. | 2 cm |
| B. | 3 cm |
| C. | 4 cm |
| D. | 5 cm |
| Answer» E. | |
| 91. |
A train weighing 196 tonnes experiences a frictional resistance of 5(11/22) per tonne. The speed of the train at the top of a down gradient 1 in 78.4 is 36 km/hour. The speed of the train after running 1 km down the slope, is |
| A. | 5 √10 m/sec |
| B. | 10 √5 m/sec |
| C. | 5 √3 m/sec |
| D. | 3 √5 m/sec |
| Answer» B. 10 √5 m/sec | |
| 92. |
The rate of change of displacement of a body with respect to its surrounding, is known |
| A. | Velocity |
| B. | Acceleration |
| C. | Speed |
| D. | None of these |
| Answer» D. None of these | |
| 93. |
The mechanical advantage of an ideal machine is 100. For moving the local through 2 m, the effort moves through |
| A. | 0.02 m |
| B. | 2 m |
| C. | 2.5 m |
| D. | 20 m |
| Answer» B. 2 m | |
| 94. |
A cube on a smooth horizontal surface |
| A. | Cannot be in stable equilibrium |
| B. | Cannot be in neutral equilibrium |
| C. | Cannot be in unstable equilibrium |
| D. | Can be in any of these states |
| Answer» E. | |
| 95. |
The Law of Polygon of Forces states that |
| A. | If a polygon representing the forces acting at point in a body is closed, the forces are in equilibrium |
| B. | If forces acting on a point can be represented in magnitude and direction by the sides of a polygon taken in order, then the resultant of the forces will be represented in magnitude and direction by t |
| C. | If forces acting on a point can be represented of a polygon taken in order, their sides of a polygon taken in order, their resultant will be represented in magnitude and direction by the closing side |
| D. | If forces acting on a point can be represented in magnitude and direction by the sides of a polygon in order, the forces are in equilibrium |
| Answer» D. If forces acting on a point can be represented in magnitude and direction by the sides of a polygon in order, the forces are in equilibrium | |
| 96. |
The dimensions of power are. |
| A. | M’L2T2 |
| B. | M’L’T3 |
| C. | M’L’r2 |
| D. | M’L-‘T* |
| Answer» C. M’L’r2 | |
| 97. |
If two forces are in equilibrium, then the forces must(i) Be equal in magnitude(ii) Be opposite in sense(iii) Act along the same line |
| A. | (i) and (ii) |
| B. | (i) and (iii) |
| C. | Only (i) |
| D. | All (i), (ii) and (iii) |
| Answer» E. | |
| 98. |
The instantaneous centre of a member lies at the point of intersection of two lines drawn at the ends of the member such that the lines are inclined to the direction of motion of the ends at |
| A. | 30° |
| B. | 45° |
| C. | 60° |
| D. | 90° |
| Answer» E. | |
| 99. |
Cartesian form of the equation of catenary is |
| A. | y = c cosh x/c |
| B. | y = c sinh x/c |
| C. | y = c tan x/c |
| D. | y = c sin x/c |
| Answer» B. y = c sinh x/c | |
| 100. |
The intrinsic equation of catenary is |
| A. | S = c tan ψ |
| B. | y = c cosh x/c |
| C. | y = c cosh ψ |
| D. | y = c sinh ψ |
| Answer» B. y = c cosh x/c | |