MCQOPTIONS
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| 1. |
With variable thermal conductivity, Fourier law of heat conduction through a plane wall can be expressed as |
| A. | Q = -k0 (1 + β t) A d t/d x |
| B. | Q = k0 (1 + β t) A d t/d x |
| C. | Q = – (1 + β t) A d t/d x |
| D. | Q = (1 + β t) A d t/d x |
| Answer» B. Q = k0 (1 + β t) A d t/d x | |