The inner and outer surfaces of a furnace wall, 25 cm thick, are at 300 degree Celsius and 30 degree Celsius. Here thermal conductivity is given by the relationK = (1.45 + 0.5 * 10¯⁵ t²) KJ/m hr degWhere, t is the temperature in degree centigrade. Calculate the heat loss per square meter of the wall surface area?

The inner and outer surfaces of a furnace wall, 25 cm thick, are at 30

1.	The inner and outer surfaces of a furnace wall, 25 cm thick, are at 300 degree Celsius and 30 degree Celsius. Here thermal conductivity is given by the relationK = (1.45 + 0.5 * 10¯⁵ t²) KJ/m hr degWhere, t is the temperature in degree centigrade. Calculate the heat loss per square meter of the wall surface area?
A.	1355.3 kJ/m² hr
B.	2345.8 kJ/m² hr
C.	1745.8 kJ/m² hr
D.	7895.9 kJ/m² hr
Answer» D. 7895.9 kJ/m² hr

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